Chapter 1: Problem 61
Find an equation of the perpendicular bisector of the line segment joining the points \(A(1,4)\) and \(B(7,-2)\).
Short Answer
Expert verified
The perpendicular bisector of the segment is \( y = x - 3 \).
Step by step solution
01
Find the midpoint of segment AB
To find the perpendicular bisector, we first need the midpoint of the line segment joining points A(1,4) and B(7,-2). The formula for the midpoint M of a segment joining points \( A(x_1, y_1) \) and \( B(x_2, y_2) \) is given by: \[ M = \left(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2}\right) \] So, substituting the numbers, we have: \[ M = \left(\frac{1+7}{2}, \frac{4+(-2)}{2}\right) = \left(4, 1\right) \] Thus, the midpoint is (4,1).
02
Calculate the slope of line AB
Calculate the slope of the line joining points A(1,4) and B(7,-2) using the slope formula: \[ m = \frac{y_2 - y_1}{x_2 - x_1} \] Substituting the given points, we get: \[ m = \frac{-2 - 4}{7 - 1} = \frac{-6}{6} = -1 \] Thus, the slope of AB is -1.
03
Determine the slope of the perpendicular bisector
The slope of the perpendicular bisector is the negative reciprocal of the slope of line AB. Since the slope of line AB is -1, the negative reciprocal is: \[ m_{\perp} = -\left(\frac{1}{-1}\right) = 1 \] Hence, the slope of the perpendicular bisector is 1.
04
Use point-slope form to find the equation
Use the point-slope form of a line equation \( y - y_1 = m(x - x_1) \) with the midpoint \((4, 1)\) and the slope \(1\). Substitute the values: \[ y - 1 = 1(x - 4) \] Simplify this equation to get: \[ y - 1 = x - 4 \] \[ y = x - 3 \] Thus, the equation of the perpendicular bisector is \( y = x - 3 \).
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Midpoint Formula
The midpoint formula is a helpful tool in geometry. It allows you to find the center point of a line segment given its endpoints. This is crucial when you need to determine features like the perpendicular bisector. The formula is:
This midpoint balances the line segment, being equidistant from both A and B.
- \[ M = \left(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2}\right) \]
- \( x_1, y_1 \) are the coordinates of point A
- \( x_2, y_2 \) are the coordinates of point B
This midpoint balances the line segment, being equidistant from both A and B.
Slope Formula
Understanding the slope of a line is key in geometry, particularly for determining perpendicularity. A slope indicates how steep a line is. The formula for finding the slope \( m \) of a line joining two points \( A(x_1, y_1) \) and \( B(x_2, y_2) \) is:
For example, in the exercise, using points \( A(1,4) \) and \( B(7,-2) \), the slope is \( \frac{-2 - 4}{7 - 1} = -1 \). This result gives us valuable information: a slope of -1 means the line descends one unit vertically for every horizontal unit, forming a diagonal line.
For a perpendicular bisector, you need the negative reciprocal of this slope, which would be 1 for our current example.
- \[ m = \frac{y_2 - y_1}{x_2 - x_1} \]
For example, in the exercise, using points \( A(1,4) \) and \( B(7,-2) \), the slope is \( \frac{-2 - 4}{7 - 1} = -1 \). This result gives us valuable information: a slope of -1 means the line descends one unit vertically for every horizontal unit, forming a diagonal line.
For a perpendicular bisector, you need the negative reciprocal of this slope, which would be 1 for our current example.
Point-Slope Form
When devising a line's equation, the point-slope form is a handy approach. It expresses a line's equation through a known point and slope. The point-slope form is stated as:
Plugging in these values, we have:
This procedure helps in situations where line characteristics (a particular point and slope) enable easier calculations than using other formulas.
- \[ y - y_1 = m(x - x_1) \]
- \( m \) is the slope
- \((x_1, y_1)\) is a point on the line
Plugging in these values, we have:
- \[ y - 1 = 1(x - 4) \]
This procedure helps in situations where line characteristics (a particular point and slope) enable easier calculations than using other formulas.