Chapter 1: Problem 49
Solve the nonlinear inequality. Express the solution using interval notation and graph the solution set. $$(x+2)(x-1)(x-3) \leq 0$$
Short Answer
Expert verified
The solution set is \((-\infty, -2]\) and \([1, 3]\).
Step by step solution
01
Identify Key Points
The inequality \((x+2)(x-1)(x-3) \leq 0\) is zero at the points where each of the factors equals zero. Thus, solve \(x+2 = 0\), \(x-1 = 0\), and \(x-3 = 0\) to find key points: \(x = -2\), \(x = 1\), and \(x = 3\).
02
Determine Intervals
The key points divide the number line into intervals: \((-\infty, -2)\), \((-2, 1)\), \((1, 3)\), and \((3, \infty)\). We will test the sign of the expression in each interval.
03
Test Each Interval
Select test points from each interval (e.g., \(x = -3\) from \((-\infty, -2)\), \(x = 0\) from \((-2, 1)\), \(x = 2\) from \((1, 3)\), and \(x = 4\) from \((3, \infty)\)). Substitute these into the expression:- For \(x = -3\), \((-1)(-4)(-6) = -24\), negative.- For \(x = 0\), \((2)(-1)(-3) = 6\), positive.- For \(x = 2\), \((4)(1)(-1) = -4\), negative.- For \(x = 4\), \((6)(3)(1) = 18\), positive.
04
Analyze Equality and Solution Interval
The inequality includes equal to zero: \((x+2)(x-1)(x-3) \leq 0\). Thus, points where the expression equals zero (\(x = -2, 1, 3\)) are included in the solution set. From Step 3, identify intervals with non-positive values: \((-\infty, -2]\), \([1, 3]\).
05
Express Solution in Interval Notation
Combine the results from Step 4 to write the solution set. The inequality is satisfied for \((-\infty, -2]\) and \([1, 3]\) in interval notation.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Interval Notation
Interval notation is a way to express a range of values or solutions for a variable. It's very useful in inequalities, as it provides a clear and concise way to present the solution set. For example, if a solution includes a range from negative infinity to -2, and also includes -2, we use \((-\infty, -2]\). The parentheses \(()\) indicate that the endpoint isn't included, while square brackets \([]\) mean the endpoint is included.
For the inequality \( (x+2)(x-1)(x-3) \leq 0 \), our solution uses interval notation to show where the inequality holds true. The solution is \( (-\infty, -2] \) and \([1, 3] \). This means that all values less than or equal to -2, and between 1 and 3, satisfy the inequality.
When writing in interval notation:
For the inequality \( (x+2)(x-1)(x-3) \leq 0 \), our solution uses interval notation to show where the inequality holds true. The solution is \( (-\infty, -2] \) and \([1, 3] \). This means that all values less than or equal to -2, and between 1 and 3, satisfy the inequality.
When writing in interval notation:
- Use \(()\) for open intervals where endpoints aren't included.
- Use \([]\) for closed intervals where endpoints are included.
- Combine intervals using a union symbol (usually implicit).
Inequality Solutions
Solving inequalities is a core skill in algebra that allows us to understand ranges of values for which a condition is true. The process involves finding sets of values which, when substituted into the inequality, make it true.
In the case of \( (x+2)(x-1)(x-3) \leq 0 \), solving it requires several steps:
In the case of \( (x+2)(x-1)(x-3) \leq 0 \), solving it requires several steps:
- Identify where the product equals zero. This helps find boundary points.
- Divide the number line into intervals based on these points.
- Test each interval to find where the inequality holds.
- Pay attention to whether the inequality includes equals, which in this case, it does.
Nonlinear Inequalities
A nonlinear inequality involves a polynomial of degree higher than one, such as \( (x+2)(x-1)(x-3) \leq 0 \). They're different from linear inequalities because of the variable's power.
The key steps to solving nonlinear inequalities include:
These inequalities can represent real-world situations where thresholds or limits apply, such as in physics for defining ranges of safe operation.
The key steps to solving nonlinear inequalities include:
- Factor the expression, making it easier to find zeros and intervals.
- Use these zeros to divide the number line into several sections.
- Check each interval with a test point.
These inequalities can represent real-world situations where thresholds or limits apply, such as in physics for defining ranges of safe operation.