/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 43 Perform the addition or subtract... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Perform the addition or subtraction and simplify. $$\frac{1}{x+1}-\frac{1}{x+2}$$

Short Answer

Expert verified
The simplified expression is \( \frac{1}{(x+1)(x+2)} \).

Step by step solution

01

Identify the denominators

Recognize that the denominators are \(x+1\) and \(x+2\). To subtract these fractions, we need a common denominator.
02

Find the least common denominator (LCD)

The least common denominator of \(x+1\) and \(x+2\) is their product: \((x+1)(x+2)\).
03

Rewrite each fraction with the LCD

Rewrite \( \frac{1}{x+1} \) as \( \frac{x+2}{(x+1)(x+2)} \) and \( \frac{1}{x+2} \) as \( \frac{x+1}{(x+1)(x+2)} \).
04

Subtract the fractions

Subtract the rewritten fractions: \( \frac{x+2}{(x+1)(x+2)} - \frac{x+1}{(x+1)(x+2)} \).
05

Combine the numerators

Combine the numerators: \( (x+2) - (x+1) = 1 \). This gives us \( \frac{1}{(x+1)(x+2)} \).
06

Simplify the expression

Since \( \frac{1}{(x+1)(x+2)} \) is already simplified, the final answer is \( \frac{1}{(x+1)(x+2)} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

common denominator
When dealing with fractions, especially when subtracting them, finding a common denominator is key. A common denominator is simply a shared multiple of the original denominators. In this exercise, you have two fractions: \( \frac{1}{x+1} \) and \( \frac{1}{x+2} \).

To subtract these fractions, both must have the same denominator. The easiest way to find a common denominator is to multiply each denominator together, in this case, \((x+1)(x+2)\).

This product represents the least common denominator (LCD), which is the smallest expression that both original denominators can divide into without leaving a remainder.

This step is crucial because it allows you to convert the fractions into equivalent fractions with the same denominator. Once they share a common denominator, you can easily perform operations like subtraction.
fraction subtraction
Subtracting fractions may seem complex, but it's quite straightforward once you have a common denominator. After rewriting each fraction to have the same denominator of \((x+1)(x+2)\), you simply subtract the numerators.

In our exercise, this means your fractions will become \( \frac{x+2}{(x+1)(x+2)} \) and \( \frac{x+1}{(x+1)(x+2)} \). The subtraction process involves only the numerators, not the denominators.

So you subtract the numerators: \((x+2) - (x+1)\), which equals 1. The denominator remains the same, leading to the fraction \( \frac{1}{(x+1)(x+2)} \).

Important to remember:
  • Ensure both fractions have the same denominator before subtracting.
  • Keep the common denominator unchanged while performing operations on numerators.
simplifying fractions
Once subtraction is performed, it's important to simplify the resulting fraction if possible. Simplifying a fraction involves making it as straightforward as possible by reducing it to its simplest form.

In our exercise, after subtracting the numerators and obtaining \( \frac{1}{(x+1)(x+2)} \), you check if the numerator and denominator have any common factors.

Here are some tips for simplifying:
  • Inspect the numerator and denominator for any common factors that can be canceled out.
  • Remember that a fraction is in its simplest form when you cannot divide the numerator and denominator by any number other than 1.
  • If no common factors are found, it means the fraction is already simplified, as with our exercise's final result \( \frac{1}{(x+1)(x+2)} \).
Since the numerator is 1, and the denominator is a polynomial expression with no common factors, this fraction is already in its simplest form, concluding the simplification process.

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