Chapter 1: Problem 39
Solve the equation both algebraically and graphically. $$16 x^{4}=625$$
Short Answer
Expert verified
The solutions are \(x = \frac{5}{2}\) and \(x = -\frac{5}{2}\).
Step by step solution
01
Isolate the Power Term
We start with the equation \(16x^4 = 625\). We want to isolate \(x^4\) by dividing both sides by 16:\[x^4 = \frac{625}{16}\]
02
Take the Fourth Root
To solve for \(x\), take the fourth root of both sides. Recall that the fourth root of a number is equivalent to raising the number to the power of \(\frac{1}{4}\):\[x = \pm\left(\frac{625}{16}\right)^{\frac{1}{4}}\]
03
Simplify the Expression
Now simplify \(\left(\frac{625}{16}\right)^{\frac{1}{4}}\). We know \(625 = 25^2\) and \(16 = 4^2\), so:\[x = \pm\left(\frac{25^2}{4^2}\right)^{\frac{1}{4}} = \pm\left(\frac{25}{4}\right)^{\frac{1}{2}}\]Taking the square root gives us:\[x = \pm\frac{5}{2}\]
04
Graphical Verification
Graph the functions \(y = 16x^4\) and \(y = 625\) on the same set of axes. The solutions to the equation \(16x^4 = 625\) are the x-values where these curves intersect.Upon graphing, observe that the intersections occur at \(x = \frac{5}{2}\) and \(x = -\frac{5}{2}\), confirming our algebraic solutions.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Algebraic Solution
Solving a polynomial equation algebraically involves manipulating the equation to isolate the desired variable and solve for its value. In the given exercise, we start with the equation:
- 16x^4 = 625.
- \(x^4 = \frac{625}{16}\).
- \(x = \pm\left(\frac{625}{16}\right)^{\frac{1}{4}}\).
- 625 = 25\(^2\)
- 16 = 4\(^2\).
- \(x = \pm\left(\frac{25}{4}\right)^{\frac{1}{2}} = \pm\frac{5}{2}\).
Graphical Solution
To graphically solve a polynomial equation, we need to interpret the equation as a comparison of two function outputs. This means plotting each side of the equation as a separate function. For this particular exercise, we compare:
The function \(y = 16x^4\) is a curve that is symmetric with respect to the y-axis and strikes upwards, while \(y = 625\) is a horizontal line. The points where these two graphs meet represent our solutions.
Upon examining the graph, you'll see intersections at points \(x = \frac{5}{2}\) and \(x = -\frac{5}{2}\), verifying our algebraic results. This graphical approach provides a visual confirmation of the solutions, reinforcing the results acquired through algebraic methods.
- \(y = 16x^4\)
- \(y = 625\).
The function \(y = 16x^4\) is a curve that is symmetric with respect to the y-axis and strikes upwards, while \(y = 625\) is a horizontal line. The points where these two graphs meet represent our solutions.
Upon examining the graph, you'll see intersections at points \(x = \frac{5}{2}\) and \(x = -\frac{5}{2}\), verifying our algebraic results. This graphical approach provides a visual confirmation of the solutions, reinforcing the results acquired through algebraic methods.
Fourth Roots
Understanding fourth roots is central to solving equations like the one provided in this exercise. A fourth root of a given number is a value that, when raised to the power of four, yields the original number. Simply put, if \(x^4 = a\), then the fourth root of a is \(x = \pm a^{\frac{1}{4}}\).
Fourth roots often involve recognizing perfect squares, as seen in the equation \(16x^4 = 625\), where we found:
Calculating the fourth root efficiently involves breaking it into two steps:
Fourth roots often involve recognizing perfect squares, as seen in the equation \(16x^4 = 625\), where we found:
- \(\frac{625}{16}\) is simplified by identifying that
- 625 = 25\(^2\) and 16 = 4\(^2\).
Calculating the fourth root efficiently involves breaking it into two steps:
- First, simplify the expression within the fraction, or identify factors (in this case 25 and 4),
- Then, find the square root of the resulting simplified fraction: \((25/4)^{1/2} = 5/2\).
Intersection of Functions
The concept of intersection is an insightful aspect of solving equations graphically. When you have two functions, their intersection points on a graph provide the solutions to the equation formed by equaling those two functions.
For the equation 16\(x^4 = 625\), consider both sides as individual functions:
Graphing reveals exactly these points where the equation's solutions reside, specifically \(x = \frac{5}{2}\) and \(x = -\frac{5}{2}\).
This demonstrates not only solutions but the approach of using graphical intersections to find variable solutions and gain a deeper understanding of how equations behave visually.
For the equation 16\(x^4 = 625\), consider both sides as individual functions:
- Function A: \(y = 16x^4\)
- Function B: \(y = 625\).
Graphing reveals exactly these points where the equation's solutions reside, specifically \(x = \frac{5}{2}\) and \(x = -\frac{5}{2}\).
This demonstrates not only solutions but the approach of using graphical intersections to find variable solutions and gain a deeper understanding of how equations behave visually.