Chapter 1: Problem 103
Factor the expression completely. $$49-4 y^{2}$$
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Chapter 1: Problem 103
Factor the expression completely. $$49-4 y^{2}$$
These are the key concepts you need to understand to accurately answer the question.
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Factor the trinomial. $$(3 x+2)^{2}+8(3 x+2)+12$$
Factor the expression completely. $$4 x^{2}+4 x y+y^{2}$$
Factor the expression completely. (This type of expression arises in calculus when using the "Product Rule.") $$3(2 x-1)^{2}(2)(x+3)^{1 / 2}+(2 x-1)^{3}\left(\frac{1}{2}\right)(x+3)^{-1 / 2}$$
\(x^{4}+a x^{2}+b\) A trinomial of the form \(x^{4}+a x^{2}+b\) can sometimes be factored easily. For example, $$ x^{4}+3 x^{2}-4=\left(x^{2}+4\right)\left(x^{2}-1\right) $$ But \(x^{4}+3 x^{2}+4\) cannot be factored in this way. Instead, we can use the following method. \(x^{4}+3 x^{2}+4=\left(x^{4}+4 x^{2}+4\right)-x^{2} \quad \begin{array}{l}\text { Add and } \\ \text { subtract } x^{2}\end{array}\) Factor perfect \(=\left(x^{2}+2\right)^{2}-x^{2}\) \(=\left[\left(x^{2}+2\right)-x\right]\left[\left(x^{2}+2\right)+x\right] \quad \begin{array}{l}\text { Difference of } \\ \text { squares }\end{array}\) \(=\left(x^{2}-x+2\right)\left(x^{2}+x+2\right)\) Factor the following, using whichever method is appropriate. (a) \(x^{4}+x^{2}-2\) (b) \(x^{4}+2 x^{2}+9\) (c) \(x^{4}+4 x^{2}+16\) (d) \(x^{4}+2 x^{2}+1\)
Factor the trinomial. $$2(a+b)^{2}+5(a+b)-3$$
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