Chapter 9: Problem 8
Find the inverse of the matrix if it exists. $$\left[\begin{array}{ll}3 & 4 \\ 7 & 9\end{array}\right]$$
Short Answer
Expert verified
The inverse is \( \begin{bmatrix} -9 & 4 \\ 7 & -3 \end{bmatrix} \).
Step by step solution
01
Calculate the Determinant
To find the inverse of a 2x2 matrix \( \begin{bmatrix} a & b \ c & d \end{bmatrix} \), we need to first calculate the determinant. For the matrix \( \begin{bmatrix} 3 & 4 \ 7 & 9 \end{bmatrix} \), the determinant \( \Delta \) is given by the formula: \[ \Delta = ad - bc = (3)(9) - (4)(7) \]Calculating this, we have:\[ \Delta = 27 - 28 = -1 \]
02
Check Invertibility
A matrix is invertible if its determinant is not zero. Since we found that the determinant of the matrix is \( -1 \), which is not zero, the matrix is invertible.
03
Use the Adjugate Matrix Formula
Once we know the matrix is invertible, we use the inverse formula for a 2x2 matrix: \[ A^{-1} = \frac{1}{\Delta} \begin{bmatrix} d & -b \ -c & a \end{bmatrix} \]Where \( a = 3 \), \( b = 4 \), \( c = 7 \), \( d = 9 \), and \( \Delta = -1 \). The adjugate (also called adjoint) of the matrix is:\[ \begin{bmatrix} 9 & -4 \ -7 & 3 \end{bmatrix} \]
04
Calculate the Inverse Matrix
To find the inverse of the matrix, divide each term of the adjugate matrix by the determinant \( \Delta \):\[ A^{-1} = \frac{1}{-1} \begin{bmatrix} 9 & -4 \ -7 & 3 \end{bmatrix} = \begin{bmatrix} -9 & 4 \ 7 & -3 \end{bmatrix} \]Thus, the inverse of the given matrix is:\[ \begin{bmatrix} -9 & 4 \ 7 & -3 \end{bmatrix} \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Determinant Calculation
The determinant of a matrix is a special number that can be calculated from its elements and provides crucial insights into the properties of the matrix. For a 2x2 matrix, such as \( \begin{bmatrix} a & b \ c & d \end{bmatrix} \), the determinant \( \Delta \) is found using the formula:
\)for the matrix \( \begin{bmatrix} 3 & 4 \ 7 & 9 \end{bmatrix} \), we calculated the determinant as:
- \( \Delta = ad - bc \)
\)for the matrix \( \begin{bmatrix} 3 & 4 \ 7 & 9 \end{bmatrix} \), we calculated the determinant as:
- \( \Delta = (3)(9) - (4)(7) = 27 - 28 = -1 \)
Invertible Matrix
A matrix is said to be invertible if it has an inverse, which mathematically means that for a matrix \( A \), there exists another matrix \( A^{-1} \) such that:
In our context, since the determinant of the matrix \( \begin{bmatrix} 3 & 4 \ 7 & 9 \end{bmatrix} \) is \( -1 \), which is not zero, the matrix is invertible. This opens the way for further steps in calculating its inverse.
- \( A \cdot A^{-1} = I \)
In our context, since the determinant of the matrix \( \begin{bmatrix} 3 & 4 \ 7 & 9 \end{bmatrix} \) is \( -1 \), which is not zero, the matrix is invertible. This opens the way for further steps in calculating its inverse.
2x2 Matrix Inverse
The inverse of a 2x2 matrix can be found using a specific formula that relies on its determinant and its adjugate matrix. For a 2x2 matrix \( \begin{bmatrix} a & b \ c & d \end{bmatrix} \), the formula to find the inverse \( A^{-1} \) is given by:
Using our determinant \( \Delta = -1 \), and the elements from matrix \( \begin{bmatrix} 3 & 4 \ 7 & 9 \end{bmatrix} \), we find:
- \( A^{-1} = \frac{1}{\Delta} \begin{bmatrix} d & -b \ -c & a \end{bmatrix} \)
Using our determinant \( \Delta = -1 \), and the elements from matrix \( \begin{bmatrix} 3 & 4 \ 7 & 9 \end{bmatrix} \), we find:
- The inverse is \( \begin{bmatrix} -9 & 4 \ 7 & -3 \end{bmatrix} \)
Adjugate Matrix
The adjugate matrix, sometimes referred to as the adjoint, plays a key role in computing the inverse of a matrix. For a 2x2 matrix \( \begin{bmatrix} a & b \ c & d \end{bmatrix} \), the adjugate is created by swapping the positions of the diagonal elements \( a \) and \( d \), and changing the signs of the off-diagonal elements \( b \) and \( c \):
- The adjugate matrix is \( \begin{bmatrix} d & -b \ -c & a \end{bmatrix} \).