Chapter 9: Problem 7
Find the inverse of the matrix if it exists. $$\left[\begin{array}{ll}5 & 3 \\ 3 & 2\end{array}\right]$$
Short Answer
Expert verified
The inverse of the matrix is \( \begin{bmatrix} 2 & -3 \\ -3 & 5 \end{bmatrix} \).
Step by step solution
01
Determine the Determinant
To find the inverse of a 2x2 matrix, the first step is to calculate the determinant. The formula for the determinant \( D \) of the matrix \( \begin{bmatrix} a & b \ c & d \end{bmatrix} \) is given by \( D = ad - bc \). For our matrix \( \begin{bmatrix} 5 & 3 \ 3 & 2 \end{bmatrix} \), the determinant is: \[ D = (5)(2) - (3)(3) = 10 - 9 = 1 \].
02
Check Invertibility
A matrix is invertible if its determinant is not equal to zero. In our case, the determinant is 1. Since 1 is not zero, the matrix is invertible.
03
Use the Formula for Inverse
For a 2x2 matrix \( \begin{bmatrix} a & b \ c & d \end{bmatrix} \), the inverse is given by \[ \frac{1}{D} \begin{bmatrix} d & -b \ -c & a \end{bmatrix} \] where \( D \) is the determinant. Substituting the values from our matrix and \( D = 1 \), the inverse is: \[ \begin{bmatrix} 2 & -3 \ -3 & 5 \end{bmatrix} \].
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Understanding the Determinant
The determinant is a crucial factor when working with matrices, especially when we're seeking to find an inverse of a matrix. For any 2x2 matrix, say \[\begin{bmatrix} a & b \ c & d \end{bmatrix},\]the determinant \(D\) is computed using the formula: \(D = ad - bc\).
This simple calculation results in a scalar value, which actually gives us no direct visual insight into the matrix, but it carries significant weight.
This simple calculation results in a scalar value, which actually gives us no direct visual insight into the matrix, but it carries significant weight.
- First of all, if this value is equal to zero, the matrix is labeled as non-invertible, meaning an inverse doesn't exist.
- If the determinant is not zero, the matrix can be inverted, and this very number influences how the inverse matrix behaves.
The Nature of a 2x2 Matrix
When working with matrices, especially in introductory linear algebra, the 2x2 matrix often serves as a stepping stone to understanding larger and more complex matrix structures. A 2x2 matrix is categorized by two rows and two columns:\[\begin{bmatrix} a & b \ c & d \end{bmatrix}\]This simplicity makes 2x2 matrices an excellent learning tool.
- Firstly, they're relatively easy to visualize, making computations like determinants and inverses more tangible.
- They serve as foundational examples where concepts "just work" before scaling these methods to larger matrices.
Determining an Invertible Matrix
An invertible matrix is a core concept in linear algebra, referring to a matrix that has an inverse. Imagine it as a matrix with a "counterpart" that can revert any transformation back to its original state. For a 2x2 matrix to be invertible, its determinant must not be zero.
Why does the determinant matter? Let's break it down:
Why does the determinant matter? Let's break it down:
- A zero determinant means the matrix squishes transformations into a lower dimension, losing information, which cannot be undone.
- If the determinant is non-zero, the transformation is stable and reversible, allowing for the "counteraction" that an inverse provides.