Chapter 8: Problem 78
Find the indicated roots, and graph the roots in the complex plane. The cube roots of \(4 \sqrt{3}+4 i\)
Short Answer
Expert verified
The cube roots are approximately \(1.98+0.35i\), \(-1.98+0.35i\), and \(0-2i\). Graph these on the complex plane.
Step by step solution
01
Convert to Polar Form
To find the cube roots of a complex number, first express it in polar form. The complex number is given as \(4 \sqrt{3} + 4i\). Find the modulus: \(r = \sqrt{(4\sqrt{3})^2 + 4^2} = \sqrt{48 + 16} = \sqrt{64} = 8\). Next, find the argument \( \theta \) using \(\tan \theta = \frac{4}{4\sqrt{3}} = \frac{1}{\sqrt{3}}\). Hence, \( \theta = \frac{\pi}{6}\). The polar form is \( 8 \text{cis} \frac{\pi}{6} \).
02
Find Cube Roots
The cube roots of a complex number in polar form \( r \text{cis} \theta \) are given by \( \sqrt[3]{r} \text{cis} \left( \frac{\theta + 2k\pi}{3} \right) \) for \( k = 0, 1, 2 \). The cube root of the modulus is \( \sqrt[3]{8} = 2 \). The three roots are:- \( 2 \text{cis} \left( \frac{\pi}{18} \right) \) for \( k = 0\),- \( 2 \text{cis} \left( \frac{\pi}{18} + \frac{2\pi}{3} \right) = 2 \text{cis} \left( \frac{13\pi}{18} \right) \) for \( k = 1\),- \( 2 \text{cis} \left( \frac{\pi}{18} + \frac{4\pi}{3} \right) = 2 \text{cis} \left( \frac{25\pi}{18} \right) \) for \( k = 2\).
03
Convert Back to Rectangular Form
Convert each of the roots from polar back to rectangular form using \( \text{cis} \theta = \cos \theta + i \sin \theta \). The roots become:- For \( 2 \text{cis} \left( \frac{\pi}{18} \right) \), it's approximately \( 2 \left( \cos \frac{\pi}{18} + i \sin \frac{\pi}{18} \right) \approx 1.98 + 0.35i \).- For \( 2 \text{cis} \left( \frac{13\pi}{18} \right) \), it's approximately \( 2 \left( \cos \frac{13\pi}{18} + i \sin \frac{13\pi}{18} \right) \approx -1.98 + 0.35i \).- For \( 2 \text{cis} \left( \frac{25\pi}{18} \right) \), it's approximately \( 2 \left( \cos \frac{25\pi}{18} + i \sin \frac{25\pi}{18} \right) \approx 0 - 2i \).
04
Graph the Roots
To graph the roots on the complex plane, place each root at its respective coordinate:- \( (1.98, 0.35) \) for the first root.- \( (-1.98, 0.35) \) for the second root.- \( (0, -2) \) for the third root.These points form an equilateral triangle centered around the origin on the complex plane.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Polar Form
Polar form is a way to represent complex numbers, which can make it easier to perform certain calculations. Rather than writing a complex number as \( a + bi \) (called rectangular form), it can be expressed as \( r \text{cis} \theta \), where:
- \( r \) is the modulus or absolute value of the complex number.
- \( \theta \) is the argument, representing the angle formed with the positive x-axis in the complex plane.
- \( \text{cis} \theta \) is a shorthand for \( \cos \theta + i \sin \theta \).
Cube Roots
Finding cube roots of a complex number involves expressing the number in polar form first. When a complex number is expressed as \( r \text{cis} \theta \), its cube roots are found by using the formula:
- \( \sqrt[3]{r} \text{cis}\left( \frac{\theta + 2k\pi}{3} \right) \)
Complex Plane
The complex plane provides a visual representation of complex numbers. Imagine a two-dimensional plane where:
- The horizontal axis (x-axis) represents real numbers.
- The vertical axis (y-axis) represents imaginary numbers.
Rectangular Form
Rectangular form expresses a complex number as \( a + bi \), where:
- \( a \) is the real part.
- \( b \) is the imaginary part.