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Find \(2 u,-3 v, u+v,\) and \(3 u-4 v\) for the given vectors \(\mathbf{u}\) and \(\mathbf{v}\). $$\mathbf{u}=\mathbf{i}, \quad \mathbf{v}=-2 \mathbf{j}$$

Short Answer

Expert verified
\(2\mathbf{u}=2\mathbf{i}, -3\mathbf{v}=6\mathbf{j}, \mathbf{u}+\mathbf{v}=\mathbf{i}-2\mathbf{j}, 3\mathbf{u}-4\mathbf{v}=3\mathbf{i}+8\mathbf{j}\).

Step by step solution

01

Determine Scalar Multiplication for 2u

Given the vector \( \mathbf{u} = \mathbf{i} \). Multiply it by 2: \[ 2 \mathbf{u} = 2 \times \mathbf{i} = 2\mathbf{i} \]
02

Determine Scalar Multiplication for -3v

Given the vector \( \mathbf{v} = -2\mathbf{j} \). Multiply it by -3: \[ -3 \mathbf{v} = -3 \times (-2\mathbf{j}) = 6\mathbf{j} \]
03

Calculate the Sum of u and v

Find the sum of the vectors \( \mathbf{u} \) and \( \mathbf{v} \): \[ \mathbf{u} + \mathbf{v} = \mathbf{i} + (-2\mathbf{j}) = \mathbf{i} - 2\mathbf{j} \]
04

Calculate 3u - 4v

First find \( 3\mathbf{u} \) and \( 4\mathbf{v} \). \( 3\mathbf{u} = 3 \times \mathbf{i} = 3\mathbf{i} \) \( 4\mathbf{v} = 4 \times (-2\mathbf{j}) = -8\mathbf{j} \) Now subtract:\[ 3\mathbf{u} - 4\mathbf{v} = 3\mathbf{i} - (-8\mathbf{j}) = 3\mathbf{i} + 8\mathbf{j} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Scalar Multiplication
Scalar multiplication involves multiplying a vector by a scalar, which is just a fancy word for a real number.
When you multiply a vector, each component of the vector is multiplied by the scalar.
This can change the vector's length but not its direction, unless the scalar is negative.

Consider the vector \( \mathbf{u} = \mathbf{i} \). If we want to multiply by 2, we do the following calculation:
  • \( 2\mathbf{u} = 2 \times \mathbf{i} = 2\mathbf{i} \)
This multiplication doubles the length of the unit vector \(\mathbf{i}\), keeping it in the same direction.
Similarly, let's take the vector \( \mathbf{v} = -2\mathbf{j} \). Using the scalar of -3 gives:
  • \( -3\mathbf{v} = -3 \times (-2\mathbf{j}) = 6\mathbf{j} \)
Notice the sign change flips the direction of \(\mathbf{v}\) from negative \(\mathbf{j}\) to positive \(\mathbf{j}\). Scalar multiplication is a straightforward yet powerful tool in vector operations.
Vector Addition
Vector addition means combining vectors to get a new vector. This involves adding the respective components of the vectors.
For vectors in two-dimensional space, simply add their \(i\) and \(j\) components separately.

Take our example with vectors \(\mathbf{u} = \mathbf{i} \) and \( \mathbf{v} = -2\mathbf{j} \):
  • Adding these yields: \( \mathbf{u} + \mathbf{v} = \mathbf{i} + (-2\mathbf{j}) = \mathbf{i} - 2\mathbf{j} \)
The resulting vector points one unit in the direction of \(\mathbf{i}\) and two units in the opposite direction of \(\mathbf{j}.\)
Vector addition is intuitive once you understand that it's like adding the movements described by each vector.

Think of vectors as arrows on a map; adding them is like connecting the arrows tip-to-tail to find the final destination.
Unit Vectors
Unit vectors play a fundamental role in vector operations.
They have a magnitude or length of 1 and are used to indicate direction only.
The most common unit vectors in two-dimensional space are \(\mathbf{i}\) and \(\mathbf{j}\), which point in the direction of the x-axis and y-axis respectively.

In our exercise, \( \mathbf{u} = \mathbf{i} \), which implies \( \mathbf{u} \) is 1 unit in the direction of the x-axis.
This is why multiplying \( \mathbf{i} \) by any scalar just changes its length while maintaining its x-axis direction.

Unit vectors are also crucial when performing operations like normalization, in which a vector is converted to a unit vector.
They help simplify complex vector calculations and are a handy reference for direction representation.
  • Think of unit vectors as the compass showing the direction while ignoring the distance.
  • In 3D space, the unit vector also includes \(\mathbf{k}\), pointing along the z-axis.
Understanding unit vectors aids in grasping the essence of vector operations, making them easier to visualize and compute.

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