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Use an addition or subtraction formula to simplify the equation. Then find all solutions in the interval \([0,2 \pi)\). $$\cos x \cos 3 x-\sin x \sin 3 x=0$$

Short Answer

Expert verified
The solutions are \(x = \frac{\pi}{8}, \frac{3\pi}{8}, \frac{5\pi}{8}, \frac{7\pi}{8}, \frac{9\pi}{8}, \frac{11\pi}{8}, \frac{13\pi}{8}, \text{and} \frac{15\pi}{8}.\)

Step by step solution

01

Recognize the Trigonometric Identity

Notice that the expression \[ \cos x \cos 3x - \sin x \sin 3x \]matches the form of the sum-to-product identity: \[ \cos(A - B) = \cos A \cos B + \sin A \sin B \] Rearranging the expression, we have:\[ \cos(x + 3x) = \cos 4x \]
02

Set Up the Equation

Now, we express the given problem in the form:\[ \cos 4x = 0 \]This equation arises from using the cosine difference identity.
03

Solve for x

To solve \( \cos 4x = 0 \), recognize that cosine equals zero at odd multiples of \(\frac{\pi}{2}\):\[ 4x = \frac{\pi}{2} + n\pi \]where \(n\) is an integer.
04

Solve the Equation for x

Divide the entire equation \(4x = \frac{\pi}{2} + n\pi\) by 4, yielding:\[ x = \frac{\pi}{8} + \frac{n\pi}{4} \]
05

Find Solutions in the Interval [0, 2\pi)

We must find values within the interval \([0, 2\pi)\):- For \(n = 0\), \(x = \frac{\pi}{8}\)- For \(n = 1\), \(x = \frac{3\pi}{8}\)- For \(n = 2\), \(x = \frac{5\pi}{8}\)- For \(n = 3\), \(x = \frac{7\pi}{8}\)- For \(n = 4\), \(x = \frac{9\pi}{8}\)- For \(n = 5\), \(x = \frac{11\pi}{8}\)- For \(n = 6\), \(x = \frac{13\pi}{8}\)- For \(n = 7\), \(x = \frac{15\pi}{8}\)These are all within the interval \([0, 2\pi)\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Cosine Difference Identity
The cosine difference identity is a handy trigonometric formula that helps simplify expressions involving two angles by breaking them into separate sine and cosine terms. The fundamental identity is:
  • \( \cos(A - B) = \cos A \cos B + \sin A \sin B \)
This identity allows you to express the cosine of the difference between two angles, \(A\) and \(B\), using the cosines and sines of \(A\) and \(B\) themselves. It plays a crucial role in transforming complex trigonometric expressions into more manageable forms.
For example, in the problem \( \cos x \cos 3x - \sin x \sin 3x = 0 \), this identity helps identify the expression as \( \cos 4x \). Recognizing this pattern is key to simplifying and solving trigonometric equations efficiently.
Sum-to-Product Formulas
Sum-to-product formulas are another important tool in trigonometry that convert the sum or difference of trigonometric functions into products. These formulas can sometimes be confused with product-to-sum, but their main use is in easing calculations, especially when dealing with equations or evaluating integrals.
  • For example, \( \cos A + \cos B = 2 \cos\left(\frac{A + B}{2}\right)\cos\left(\frac{A - B}{2}\right) \)
  • And \( \cos A - \cos B = -2 \sin\left(\frac{A + B}{2}\right)\sin\left(\frac{A - B}{2}\right) \)
These formulas simplify expressions by transforming them using trigonometric identities. In the given exercise, the initial expression matched the form of such a structure. Realizing this allowed the solver to transform the left-hand side into a single cosine term, simplifying the equation and aiding in finding solutions.
Solving Trigonometric Equations
Solving trigonometric equations involves finding the values of the variable that satisfy the equation within a given interval. Different trigonometric functions have specific patterns of solutions due to their periodic nature.When solving equations like \( \cos 4x = 0 \), it is important to recognize where the function hits specific values, such as zero. Here, the cosine function equals zero at odd multiples of \(\frac{\pi}{2}\). Therefore, we set up:
  • \( 4x = \frac{\pi}{2} + n \pi \)
where \(n\) is an integer, which accounts for the periodic nature of cosine.
To find the solutions for \(x\), we divide by 4:
  • \( x = \frac{\pi}{8} + \frac{n \pi}{4} \)
Finally, we find the values of \(x\) within the desired interval by plugging in integer values for \(n\). This careful check within \([0, 2\pi)\) ensures that only legitimate solutions are considered. Understanding and applying such methods is crucial in solving trigonometric equations effectively.

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