Chapter 7: Problem 4
Find all solutions of the equation. $$\sqrt{2} \cos x-1=0$$
Short Answer
Expert verified
The solutions are \( x = \frac{\pi}{4} + 2k\pi \) and \( x = \frac{7\pi}{4} + 2k\pi \), where \( k \) is an integer.
Step by step solution
01
Isolate the Trigonometric Function
The given equation is \( \sqrt{2} \cos x - 1 = 0 \). To isolate \( \cos x \), add 1 to both sides of the equation:\[\sqrt{2} \cos x = 1\]
02
Solve for \( \cos x \)
Divide both sides of the equation by \( \sqrt{2} \) to solve for \( \cos x \):\[\cos x = \frac{1}{\sqrt{2}}\]Simplify the expression for \( \cos x \) using the identity \( \frac{1}{\sqrt{2}} = \frac{\sqrt{2}}{2} \):\[\cos x = \frac{\sqrt{2}}{2}\]
03
Determine General Solution
The general solution for \( \cos x = \frac{\sqrt{2}}{2} \) is based on the known angles where cosine equals \( \frac{\sqrt{2}}{2} \), which are \( x = \frac{\pi}{4} \) and \( x = \frac{7\pi}{4} \) for the unit circle. Since cosine function has a periodicity of \( 2\pi \), the general solution can be written as:\[x = \frac{\pi}{4} + 2k\pi \quad \text{or} \quad x = \frac{7\pi}{4} + 2k\pi\]where \( k \) is any integer.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Cosine Function
The cosine function is a fundamental part of trigonometry and is widely used in mathematics to measure angles and lengths in right triangles and circles. It takes an angle as input and returns a value between -1 and 1. The cosine of an angle in a right triangle is the adjacent side divided by the hypotenuse. From a unit circle perspective, this translates to the horizontal coordinate of a point \((x, y)\) on the circle.
- Function characteristics: Cosine is an even function, meaning \(\cos(-x) = \cos(x)\).
- Range: It ranges from -1 to 1 for any angle \(x\), repeating its values every \(2\pi\) radians.
- Periodicity: The period of the cosine function is \(2\pi\), indicating its values repeat every \(2\pi\) radians.
Unit Circle
The unit circle is a helpful tool for understanding trigonometric functions, providing a bridge between geometry and algebra. It's a circle with a radius of 1, centered at the origin \((0, 0)\) on the Cartesian plane. Each point on the unit circle corresponds to an angle \(\theta\), measured from the positive x-axis.
- Angle and coordinates: An angle \(\theta\) intersects the unit circle at a point \((\cos \theta, \sin \theta)\).
- Cosine on the circle: The x-coordinate of these points gives the cosine value of the angle.
- Quadrants: Angles \(\theta\) can be measured as positive (counterclockwise) or negative (clockwise) from the x-axis, impacting the sign of the cosine value depending on the quadrant.
General Solution
The general solution of a trigonometric equation addresses all possible values of the variable that satisfy the equation. Trigonometric functions, such as cosine, are periodic, repeating their values in a regular cycle. The general solution encompasses this periodic nature.Consider our core problem: solving \(\cos x = \frac{\sqrt{2}}{2}\). We find specific angles, \(x = \frac{\pi}{4}\) and \(x = \frac{7\pi}{4}\), where the cosine yields this value. Due to the periodicity of the cosine function, these angles repeat every \(2\pi\) radians.
- Periodic addition: To account for all such occurrences, add multiples of the period: \(x = \frac{\pi}{4} + 2k\pi\) and \(x = \frac{7\pi}{4} + 2k\pi\), where \(k\) is an integer.
- Infinite solutions: The general solution captures an infinite set of angles, achieved by varying the integer \(k\).