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Find the area of the triangle whose sides have the given lengths. $$a=11, \quad b=100, \quad c=101$$

Short Answer

Expert verified
The area of the triangle is 550 square units.

Step by step solution

01

Verify the Triangle Inequality

First, check if the given side lengths can form a triangle using the triangle inequality theorem. For a valid triangle, the sum of the lengths of any two sides must be greater than the length of the third side. Check:1. \( a + b > c \leftrightarrow 11 + 100 > 101 \), which is true.2. \( a + c > b \leftrightarrow 11 + 101 > 100 \), which is true.3. \( b + c > a \leftrightarrow 100 + 101 > 11 \), which is true.Since all inequalities hold, the sides do form a valid triangle.
02

Calculate the Semi-Perimeter

Use the formula for the semi-perimeter \( s \) of a triangle, which is half of the sum of its sides: \[ s = \frac{a+b+c}{2} \]Substitute the given lengths:\[ s = \frac{11 + 100 + 101}{2} = \frac{212}{2} = 106 \]
03

Use Heron's Formula to Find the Area

Heron's formula for the area \( A \) of a triangle given its side lengths \( a \), \( b \), and \( c \) and its semi-perimeter \( s \) is: \[ A = \sqrt{s(s-a)(s-b)(s-c)} \]Substitute \( s = 106 \), \( a = 11 \), \( b = 100 \), and \( c = 101 \) into the formula:\[ A = \sqrt{106(106-11)(106-100)(106-101)} \]Simplify inside the square root:\[ A = \sqrt{106 \times 95 \times 6 \times 5} \]Calculate step-by-step:- \( 6 \times 5 = 30 \),- \( 95 \times 30 = 2850 \),- \( 106 \times 2850 = 302100 \),Finally, \[ A = \sqrt{302100} = 550 \].Thus, the area of the triangle is 550 square units.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Triangle Inequality Theorem
The triangle inequality theorem is a foundational concept in geometry that helps determine whether three side lengths can construct a triangle. According to the theorem, for a set of three sides to form a triangle, the sum of the lengths of any two sides must exceed the length of the third side. This rule guarantees that a valid and closed figure is achieved.
To explore this further, consider a triangle with sides labeled as \(a\), \(b\), and \(c\). The theorem can be tested using these inequalities:
  • \(a + b > c\)
  • \(a + c > b\)
  • \(b + c > a\)
If each condition is satisfied, the sides can form a triangle. For instance, using \(a = 11\), \(b = 100\), and \(c = 101\) in these inequalities shows they satisfy all requirements, confirming you have a valid triangle.
Semi-Perimeter
The semi-perimeter of a triangle, represented by the symbol \(s\), is half of the triangle's perimeter. Consider it as a step that simplifies calculations when using formulas like Heron's formula to find the triangle's area.
To calculate the semi-perimeter of a triangle with sides \(a\), \(b\), and \(c\), use the formula:
  • \[ s = \frac{a+b+c}{2} \]
This provides a single value representing average side length-related information, streamlining further computations.
In the given problem, for a triangle with sides \(a = 11\), \(b = 100\), and \(c = 101\), the semi-perimeter is found as follows:
  • \[ s = \frac{11 + 100 + 101}{2} = 106 \]
Now equipped with the semi-perimeter, you can move to the next step in determining the triangle's area using Heron's formula.
Triangle Area Calculation
Calculating the area of a triangle can be straightforward, especially with Heron's formula, which relies on the side lengths and semi-perimeter. This method is effective when height and base are not easily determined. Begin by confirming the triangle's side lengths and calculate the semi-perimeter, \(s\).
Apply Heron's formula, which is as follows:
  • \[ A = \sqrt{s(s-a)(s-b)(s-c)} \]
This formula allows you to compute the area by substituting known values. For the triangle with side lengths \(a = 11\), \(b = 100\), and \(c = 101\) and semi-perimeter \(s = 106\), solve the following:
  • Calculate \(s - a\), \(s - b\), \(s - c\): \[ s-a = 106-11, \ s-b = 106-100, \ s-c = 106-101 \]
  • Then, find \( (s-a) \times (s-b) \times (s-c) \)
  • Finally, insert these into the formula to yield: \[ A = \sqrt{106 \times 95 \times 6 \times 5} = 550 \text{ square units} \]
Thus, Heron's formula gives the triangle's area effectively, even when traditional methods aren't applied.

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