Chapter 5: Problem 7
Find the exact value of the trigonometric function at the given real number. (a) \(\cos \frac{3 \pi}{4}\) (b) \(\cos \frac{5 \pi}{4}\) (c) \(\cos \frac{7 \pi}{4}\)
Short Answer
Expert verified
(a) \(-\frac{\sqrt{2}}{2}\), (b) \(-\frac{\sqrt{2}}{2}\), (c) \(\frac{\sqrt{2}}{2}\)."
Step by step solution
01
Understanding the Unit Circle Position
First, we need to determine the position on the unit circle for each given angle. For (a) \( \frac{3\pi}{4} \), this angle is located in the second quadrant. For (b) \( \frac{5\pi}{4} \), the angle lies in the third quadrant, and for (c) \( \frac{7\pi}{4} \), the angle is in the fourth quadrant.
02
Reference Angle Calculation
A reference angle helps in finding the cosine value based on the angle's symmetry in the unit circle. For (a) \( \frac{3\pi}{4} \), the reference angle is \( \pi - \frac{3\pi}{4} = \frac{\pi}{4} \). For (b) \( \frac{5\pi}{4} \), the reference angle is \( \frac{5\pi}{4} - \pi = \frac{\pi}{4} \). For (c) \( \frac{7\pi}{4} \), the reference angle is \( 2\pi - \frac{7\pi}{4} = \frac{\pi}{4} \).
03
Cosine Value from Reference Angle
The reference angle \( \frac{\pi}{4} \) has a cosine value of \( \frac{\sqrt{2}}{2} \). However, we must consider the sign based on the quadrant. For (a) in the second quadrant, cosine is negative, so \( \cos \frac{3\pi}{4} = -\frac{\sqrt{2}}{2} \). For (b) in the third quadrant, cosine is also negative, so \( \cos \frac{5\pi}{4} = -\frac{\sqrt{2}}{2} \). For (c) in the fourth quadrant, cosine is positive, so \( \cos \frac{7\pi}{4} = \frac{\sqrt{2}}{2} \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
unit circle
The unit circle is a fundamental concept in trigonometry, revolving around a circle with a radius of 1 centered at the origin of a coordinate plane. This circle allows us to connect angles with their corresponding trigonometric values in a simple and visual manner.
On the unit circle, every point \((x, y)\) corresponds to an angle measured in radians from the positive x-axis. When we talk about angles like \( \frac{3\pi}{4} \), \( \frac{5\pi}{4} \), or \( \frac{7\pi}{4} \), we are essentially finding specific points on this circle.
On the unit circle, every point \((x, y)\) corresponds to an angle measured in radians from the positive x-axis. When we talk about angles like \( \frac{3\pi}{4} \), \( \frac{5\pi}{4} \), or \( \frac{7\pi}{4} \), we are essentially finding specific points on this circle.
- The angle \( \frac{3\pi}{4} \) is located in the second quadrant.
- The angle \( \frac{5\pi}{4} \) lies in the third quadrant.
- The angle \( \frac{7\pi}{4} \) exists in the fourth quadrant.
reference angle
Reference angles are vital for simplifying the analysis of trigonometric functions. A reference angle is the smallest angle between the terminal side of the angle and the x-axis. For any angle \(\theta\) in a standard position, the reference angle is always an acute angle, meaning it is less than or equal to 90 degrees or \((\frac{\pi}{2}) \).
The process of determining a reference angle allows us to take advantage of the symmetry properties of the unit circle. For example:
The process of determining a reference angle allows us to take advantage of the symmetry properties of the unit circle. For example:
- For \( \frac{3\pi}{4} \), the reference angle is calculated as \( \pi - \frac{3\pi}{4} = \frac{\pi}{4} \).
- For \( \frac{5\pi}{4} \), it is \( \frac{5\pi}{4} - \pi = \frac{\pi}{4} \).
- For \( \frac{7\pi}{4} \), it becomes \( 2\pi - \frac{7\pi}{4} = \frac{\pi}{4} \).
cosine function
The cosine function is one of the primary trigonometric functions and is denoted as \( \cos(\theta) \). On the unit circle, the cosine of an angle is the x-coordinate of the corresponding point. By understanding the cosine function, we can determine how it behaves across different quadrants:
- In the first and fourth quadrants, the cosine values are positive because the x-coordinates are positive.
- In the second and third quadrants, cosine values are negative due to negative x-coordinates.
- For \( \cos \left( \frac{3\pi}{4} \right) \), it is negative because it is in the second quadrant, resulting in \( -\frac{\sqrt{2}}{2}\).
- For \( \cos \left( \frac{5\pi}{4} \right) \), it remains negative in the third quadrant, giving the same value of \( -\frac{\sqrt{2}}{2}\).
- For \( \cos \left( \frac{7\pi}{4} \right) \), it becomes positive in the fourth quadrant, yielding \( \frac{\sqrt{2}}{2}\).