Chapter 5: Problem 37
Find the period and graph the function. $$y=\tan 2\left(x+\frac{\pi}{2}\right)$$
Short Answer
Expert verified
The period is \( \frac{\pi}{2} \) and the graph shifts \( \frac{\pi}{2} \) units left.
Step by step solution
01
Identify the Standard Form
The standard form of a tangent function is given by \( y = \tan(bx+c) \), where the period is calculated as \( \frac{\pi}{|b|} \). In the given function, \( y = \tan(2(x+\frac{\pi}{2})) \). Rewrite it as \( y = \tan(2x + \pi) \), identifying \( b = 2 \) and \( c = \pi \).
02
Calculate the Period of the Function
Using the formula for the period of a tangent function: \( \frac{\pi}{|b|} \), substitute \( b = 2 \) into the formula. Therefore, the period is \( \frac{\pi}{2} \). This means that the function will repeat every \( \frac{\pi}{2} \) units along the x-axis.
03
Determine the Phase Shift
The phase shift of the function can be found using the formula \( -\frac{c}{b} \). Substitute \( c = \pi \) and \( b = 2 \) into the formula, giving \( -\frac{\pi}{2} \). This indicates the graph is shifted \( \frac{\pi}{2} \) units to the left.
04
Sketch the Graph of the Function
Draw the graph of \( y = \tan 2x \) first, which has a period of \( \frac{\pi}{2} \). Then apply the phase shift of \( \frac{\pi}{2} \) units to the left. This involves shifting the entire graph (including its asymptotes and repeating cycles) \( \frac{\pi}{2} \) units in the negative direction on the x-axis.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Period of a Function
The period of a function tells us how often the function repeats itself along the x-axis. For the tangent function, which is different from sine and cosine functions, the period is given by the formula:
In this problem, since we have \( y = \tan 2(x+\frac{\pi}{2}) \), we first simplify it to \( y = \tan(2x + \pi) \).
- Period = \( \frac{\pi}{|b|} \)
In this problem, since we have \( y = \tan 2(x+\frac{\pi}{2}) \), we first simplify it to \( y = \tan(2x + \pi) \).
- We see that \( b = 2 \).
- Then using our period formula, we find that the period for this function is \( \frac{\pi}{2} \).
Phase Shift
The phase shift of a trigonometric function is a horizontal movement of the entire graph along the x-axis. We can calculate this shift with the formula:
This phase shift is essential because it aligns the function's cycle to start at a different point on the x-axis.
- Phase Shift = \( -\frac{c}{b} \)
- Here, \( c = \pi \)
- and \( b = 2 \).
- Using the formula, the phase shift becomes \( -\frac{\pi}{2} \).
This phase shift is essential because it aligns the function's cycle to start at a different point on the x-axis.
Tangent Function
The tangent function, one of the primary trigonometric functions, behaves distinctively compared to sine and cosine. Its general form is given by:
- \( y = \tan(bx + c) \)
- The tangent graph has asymptotes, which are vertical lines where the function is undefined and the graph approaches infinity.
- Typically, without alterations, it has a period of \( \pi \), where it repeats its behavior between the intervals.
- The period changes to \( \frac{\pi}{2} \), due to the coefficient \( b = 2 \).
- The phase shift of \( -\frac{\pi}{2} \) results from \( c = \pi \).
- These alterations mean the typical repeating cycle and asymptotes of the tangent function are adjusted to reflect \( \frac{\pi}{2} \) spacing along the x-axis.