/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 5 Evaluate the expression. $$\lo... [FREE SOLUTION] | 91Ó°ÊÓ

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Evaluate the expression. $$\log _{4} 192-\log _{4} 3$$

Short Answer

Expert verified
The value of the expression is 3.

Step by step solution

01

Understand the property of logarithms

We need to know that when two logarithms with the same base are subtracted, we can use the property \( \log_b M - \log_b N = \log_b \left( \frac{M}{N} \right) \). This will simplify our expression.
02

Simplify using the logarithmic property

Apply the property to the expression: \( \log_4 192 - \log_4 3 = \log_4 \left( \frac{192}{3} \right) \). Now we need to calculate \( \frac{192}{3} \).
03

Compute the division

Calculate \( \frac{192}{3} = 64 \). Thus, the expression is simplified to \( \log_4 64 \).
04

Evaluate the simplified expression

Recognize that \( 64 \) is a power of \( 4 \). Specifically, \( 64 = 4^3 \). Therefore, \( \log_4 64 = \log_4 (4^3) \).
05

Solve the logarithmic expression

The property \( \log_b (b^k) = k \) tells us that \( \log_4 (4^3) = 3 \). Hence, the value of the original expression is 3.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Logarithmic Properties
Logarithmic properties are fundamental rules that help simplify or manipulate expressions involving logarithms.
These properties are essential for tackling complex logarithmic expressions in a straightforward manner. Here are some key logarithmic properties:
  • Product Property: \( \log_b (M \cdot N) = \log_b M + \log_b N \)
  • Quotient Property: \( \log_b \left( \frac{M}{N} \right) = \log_b M - \log_b N \)
  • Power Property: \( \log_b (M^k) = k \cdot \log_b M \)
Understanding and applying these properties allow us to simplify logarithmic expressions, as seen in this exercise where the quotient property was crucial. Recognizing how these properties interplay can transform complex problems into simpler terms.
Logarithm Subtraction
Logarithm subtraction is made simpler by using the quotient property of logarithms.
When you subtract two logarithms with the same base, you can combine them into a single logarithm by dividing their arguments. This is because:\[ \log_b M - \log_b N = \log_b \left( \frac{M}{N} \right) \]In our example, the expression \( \log_4 192 - \log_4 3 \) is simplified using this property.
We convert it into a single logarithmic term \( \log_4 \left( \frac{192}{3} \right) \). This technique is particularly useful in reducing the complexity of an expression and making calculations more straightforward.
Logarithmic Simplification
Logarithmic simplification involves reducing a complex logarithmic expression to its simplest form.
This often requires using logarithmic properties effectively. Once you use the logarithm subtraction property, the expression can be simplified further by performing calculations within the logarithm. In our worked example, we compute \( \frac{192}{3} \) to simplify \( \log_4 \left( \frac{192}{3} \right) \) to \( \log_4 64 \).
Recognizing that \( 64 = 4^3 \) enables further simplification using the power property of logarithms.The goal of simplification is to convert logarithmic expressions into a more easily computable form, often revealing known values or powers.
Exponent Rules
Exponent rules are closely tied to logarithms, as logarithms are inherently the inverse operations of exponents.
When simplifying expressions like \( \log_b (b^k) \), exponent rules play a significant role. This specific property states that:\[ \log_b (b^k) = k \]Essentially, this means that when you have a base raised to an exponent within a logarithmic function, the result will always be the exponent.
In the example exercise, recognizing \( 64 = 4^3 \) helps us apply this rule to find that \( \log_4 64 = 3 \).Understanding and applying exponent rules facilitate quick resolutions of logarithmic problems, as they simplify evaluations by providing direct answers when bases and exponents are apparent.

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