/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 4 Find the solution of the exponen... [FREE SOLUTION] | 91Ó°ÊÓ

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Find the solution of the exponential equation, correct to four decimal places. $$e^{3 x}=12$$

Short Answer

Expert verified
The solution is approximately \( x = 0.8283 \).

Step by step solution

01

Understand the Exponential Equation

We are given the exponential equation \( e^{3x} = 12 \). Our goal is to solve for \( x \) by expressing it in a form that can be calculated.
02

Take the Natural Logarithm

To solve for \( x \), take the natural logarithm (\( \ln \)) of both sides of the equation. This will help us to deal with the exponent. Applying \( \ln \) we get: \( \ln(e^{3x}) = \ln(12) \).
03

Simplify Using Logarithm Properties

Apply the logarithmic identity \( \ln(e^{a}) = a \) to simplify the left side: \( 3x = \ln(12) \). The natural logarithm of \( e^{a} \) simplifies directly to \( a \).
04

Solve for x

Divide both sides by 3 to solve for \( x \): \( x = \frac{\ln(12)}{3} \).
05

Calculate the Value of x

Use a calculator to evaluate \( \ln(12) \) and then divide the result by 3 to find \( x \). \( \ln(12) \approx 2.4849 \), so \( x \approx \frac{2.4849}{3} \approx 0.8283 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Natural Logarithm
The natural logarithm, represented as \( \ln \), is a specific logarithm which has the base \( e \). The number \( e \) is approximately equal to 2.71828 and is an important constant in mathematics, especially in calculus and exponential growth models. Natural logarithms are useful for solving equations involving the exponential function \( e^x \).
One of the key properties of natural logarithms is that they can efficiently reverse the process of exponentiation involving \( e \). For example, if \( e^y = x \), then \( y = \ln(x) \). This property allows us to solve equations where the unknown variable is in the exponent.
In the equation \( e^{3x} = 12 \), applying the natural logarithm is an effective first step, because it allows us to "bring down" the exponent. By taking \( \ln \) of both sides, we turn the exponential equation into a linear one, which is often more straightforward to solve.
Logarithmic Identities
Logarithmic identities are essential rules that simplify the handling of logarithms. These identities help us to transform complex expressions into simpler forms. When working with natural logarithms, one of the most commonly used identities is \( \ln(e^a) = a \). This identity is vital in solving equations like \( e^{3x} = 12 \), where the unknown is an exponent.
Other important logarithmic identities include:
  • \( \ln(xy) = \ln(x) + \ln(y) \) - the product rule
  • \( \ln\left(\frac{x}{y}\right) = \ln(x) - \ln(y) \) - the quotient rule
  • \( \ln(x^a) = a \cdot \ln(x) \) - the power rule
These identities are crucial for simplifying expressions and solving logarithmic equations. Knowing and applying them will help unlock solutions to problems that initially seem challenging.
Solving Equations
Solving equations often involves isolating the variable to determine its value. In the case of exponential equations like \( e^{3x} = 12 \), the process involves using logarithms to handle the exponent and equation manipulation to solve for the unknown.
Here is a general approach to solving an exponential equation using logarithms:
  • Take the logarithm of both sides: This step simplifies the equation by removing the exponent, using the natural logarithm property \( \ln(e^{a}) = a \).
  • Apply logarithmic identities: Use identities like \( \ln(e^{3x}) = 3x \) to simplify further.
  • Isolate the variable: Divide or multiply each side by a constant to solve for the variable, in our example, \( x = \frac{\ln(12)}{3} \).
  • Calculate or approximate: Use a calculator to evaluate expressions like \( \ln(12) \) and simplify to reach the final result.
Understanding these steps allows for a systematic approach to solving exponential equations, making complex problems approachable and solvable.

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Most popular questions from this chapter

Radioactive iodine is used by doctors as a tracer in diagnosing certain thyroid gland disorders. This type of iodine decays in such a way that the mass remaining after \(t\) days is given by the function $$ m(t)=6 e^{-0.087 t} $$ where \(m(t)\) is measured in grams. (a) Find the mass at time \(t=0\) (b) How much of the mass remains after 20 days?

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The difficulty in "acquiring a target" (such as using your mouse to click on an icon on your computer screen) depends on the distance to the target and the size of the target. According to Fitts's Law, the index of difficulty (ID) is given by $$\mathrm{ID}=\frac{\log (2 A / W)}{\log 2}$$ where \(W\) is the width of the target and \(A\) is the distance to the center of the target. Compare the difficulty of clicking on an icon that is \(5 \mathrm{mm}\) wide to one that is \(10 \mathrm{mm}\) wide. In each case, assume the mouse is \(100 \mathrm{mm}\) from the icon. (IMAGE CAN NOT COPY)

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