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These exercises use the radioactive decay model. The half-life of radium-226 is 1600 years. Suppose we have a 22-mg sample. (a) Find a function that models the mass remaining after \(t\) years. (b) How much of the sample will remain after 4000 years? (c) After how long will only 18 mg of the sample remain?

Short Answer

Expert verified
(a) \( M(t) = 22 \cdot e^{-0.0004331t} \); (b) 7.1 mg; (c) 523 years.

Step by step solution

01

Understand Radioactive Decay

Radioactive decay follows an exponential model, where the remaining quantity of a substance decreases over time. The formula is given by \( M(t) = M_0 \cdot e^{-kt} \), where \( M_0 \) is the initial amount, \( M(t) \) is the amount remaining after time \( t \), and \( k \) is the decay constant.
02

Calculate the Decay Constant

The decay constant \( k \) is related to the half-life by the equation \( k = \frac{\ln(2)}{\text{half-life}} \). For radium-226, the half-life is 1600 years, so the decay constant is \( k = \frac{\ln(2)}{1600} \approx 0.0004331 \).
03

Model the Mass Function

Substitute the initial mass and the decay constant into the equation \( M(t) = M_0 \cdot e^{-kt} \). With \( M_0 = 22 \) mg and \( k = 0.0004331 \), the function becomes \( M(t) = 22 \cdot e^{-0.0004331t} \).
04

Calculate Mass after 4000 Years

Substitute \( t = 4000 \) into the function \( M(t) = 22 \cdot e^{-0.0004331 \cdot 4000} \). This gives \( M(4000) \approx 7.1 \) mg.
05

Find Time for Mass to be 18 mg

Set \( M(t) = 18 \) and solve for \( t \): \( 18 = 22 \cdot e^{-0.0004331t} \). Divide both sides by 22: \( \frac{18}{22} = e^{-0.0004331t} \). Take the natural logarithm of both sides: \( \ln\left( \frac{18}{22} \right) = -0.0004331t \). Solve for \( t \): \( t = \frac{\ln\left( \frac{18}{22} \right)}{-0.0004331} \approx 523 \) years.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Exponential Model
An exponential model is a type of mathematical representation that showcases how quantities change over time. In the context of radioactive decay, substances decay exponentially, meaning their quantity decreases rapidly at first and then more slowly over time. The general form of the exponential decay model is given by the equation
  • \( M(t) = M_0 \cdot e^{-kt} \)
where:
  • \( M(t) \) is the amount of substance remaining at time \( t \),
  • \( M_0 \) is the initial amount of the substance, and
  • \( k \) is the decay constant, which characterizes the rate of decay.
This model applies universally across different radioactive materials. The key feature is the exponent \(-kt\), which leads to a continuous and smooth decline of the substance over time. Understanding the exponential nature ensures accuracy in predicting the remaining mass of a sample.
Half-Life
The half-life of a radioactive substance is the time required for half of the initial quantity to decay. It's an intrinsic property of the substance and does not change, regardless of the initial amount. In this exercise, the half-life of radium-226 is given as 1600 years.
  • This means that every 1600 years, the amount of radium-226 will reduce to half its previous amount.
The relationship between half-life and decay constant \( k \) is expressed by the equation:
  • \( k = \frac{\ln(2)}{\text{half-life}} \)
This crucial ratio allows us to calculate the decay constant for specific substances when their half-life is known, facilitating the use of the exponential model.
Decay Constant
The decay constant \( k \) is a crucial parameter in the exponential decay formula. It describes how quickly a substance undergoes radioactive decay. A higher decay constant indicates a faster decay process. The relationship between \( k \) and the half-life \( \tau \) of a substance is given by:
  • \( k = \frac{\ln(2)}{\tau} \)
For radium-226, with a half-life of 1600 years, the decay constant is calculated as:
  • \( k \approx 0.0004331 \)
Incorporating this decay constant into the exponential model helps ascertain the remaining mass \( M(t) \) at any given time. It is a pivotal factor in projecting both short-term and long-term decreases in radioactive material quantities.
Mass Function
The mass function is an equation providing the remaining mass of a radioactive substance after a period of time \( t \). Using the exponential decay model, we substitute the initial mass and decay constant to form the function:
  • \( M(t) = M_0 \cdot e^{-kt} \)
For the given problem with radium-226, the initial mass \( M_0 = 22 \) mg and the decay constant \( k = 0.0004331 \), hence the mass function is:
  • \( M(t) = 22 \cdot e^{-0.0004331t} \)
This function is our tool to calculate the remaining mass over time. For example, after 4000 years, substituting \( t = 4000 \) provides \( M(4000) \approx 7.1 \) mg. Using this function, we can also determine when only a certain mass, such as 18 mg, will remain, by solving for \( t \) given \( M(t) = 18 \). This versatility makes the mass function a crucial element in understanding radioactive decay.

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