/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 12 Find the solution of the exponen... [FREE SOLUTION] | 91Ó°ÊÓ

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Find the solution of the exponential equation, correct to four decimal places. $$2^{3 x}=34$$

Short Answer

Expert verified
x ≈ 1.8882

Step by step solution

01

Take the Logarithm of Both Sides

To solve the exponential equation, start by taking the logarithm of both sides. It doesn't matter whether you use natural logarithms (ln) or common logarithms (log) since either will work. In this case, we'll use natural logarithms for simplicity:\[ \ln(2^{3x}) = \ln(34) \]
02

Use the Power Rule for Logarithms

Apply the power rule for logarithms, which allows you to bring the exponent down in front of the logarithm. This transforms the equation as follows:\[ 3x \cdot \ln(2) = \ln(34) \]
03

Solve for x

Now, solve for \( x \) by isolating it. Divide both sides by \( 3 \ln(2) \) to get:\[ x = \frac{\ln(34)}{3 \ln(2)} \]
04

Calculate the Value

Use a calculator to compute the logarithms and find the value of \( x \). Here is how it works step-by-step:1. Find \( \ln(34) \).2. Find \( \ln(2) \).3. Compute \( 3 \times \ln(2) \).4. Divide \( \ln(34) \) by the result from step 3 to find \( x \).Upon calculation, \( x \approx 1.8882 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Logarithms
Logarithms are a mathematical concept used to deal with exponential expressions. They allow us to work with the powers of a number using addition and subtraction instead of multiplication and division.
For example, if you have the exponential equation \(2^{3x} = 34\), taking the logarithm of both sides can simplify your work. You can use either natural logarithm (\(\ln\)) or common logarithm (\(\log_{10}\)), depending on what you find easier.
  • The natural logarithm (\(\ln\)) uses the constant \(e\), which is approximately 2.718. This is often used in calculus and mathematical analysis.
  • The common logarithm (\(\log_{10}\)) uses the base 10 and is often used in science and engineering.
The main advantage of logarithms is that they convert multiplicative processes, like those found in exponentials, into additive ones, which are often easier to handle.
Power Rule
The power rule is an essential formula used when working with logarithms. It's especially useful in transforming complex logarithmic expressions. The rule states that the logarithm of an exponentiated number can be simplified by moving the exponent in front of the logarithm itself.
For instance, if you have \(\ln(2^{3x})\), the power rule simplifies it to \(3x \cdot \ln(2)\). Here’s how the rule works:
  • Original expression: \(\ln(a^b)\)
  • Applying the power rule: \(b \cdot \ln(a)\)
This property is incredibly useful when solving equations because it reduces the complexity of the problem by bringing variables out of the exponent. This simplification makes it easier to solve for unknowns such as \(x\).
Natural Logarithm
Natural logarithms are logarithms with the base \(e\), where \(e\) is approximately equal to 2.718. They are denoted by \(\ln\).
Natural logarithms arise quite naturally in calculus and are commonly used in solving problems involving growth and decay, such as population models and radioactive decay.
In our example, transforming \(2^{3x} = 34\) into \(\ln(2^{3x}) = \ln(34)\) allows us to use the logarithmic rules to deal with the equation easily. Natural logarithms specifically help when the problems are expressed in terms of base \(e\) related scenarios.
They are instrumental in solving equations involving exponentials, as they align with the properties of continuity and the derivatives of exponential functions.
Solving Equations
The primary aim when solving equations, especially exponential ones, is to isolate the variable in question. Let's revisit our exercise \(2^{3x} = 34\). The process begins by equating logs to each side of the equation:
1. Apply the logarithm: \(\ln(2^{3x}) = \ln(34)\)
2. Use the power rule to simplify: \(3x \cdot \ln(2) = \ln(34)\)
3. Isolate \(x\) by dividing both sides by \(3\ln(2)\):
\[ x = \frac{\ln(34)}{3 \ln(2)} \]
By following these steps, we can calculate \(x\) using a calculator for precision, giving \(x \approx 1.8882\). This problem-solving shows that by using logarithms and their properties appropriately, one can simplify complex mathematical equations into manageable arithmetic operations. Understanding these steps will aid significantly in handling similar exponential equations.

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Most popular questions from this chapter

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