Chapter 3: Problem 45
Evaluate the expression and write the result in the form \(a+b i.\) $$i^{100}$$
Short Answer
Expert verified
The result is \( 1 + 0i \).
Step by step solution
01
Understand the Imaginary Unit
Remember that the imaginary unit \( i \) satisfies \( i^2 = -1 \). Consequently, powers of \( i \) follow a cycle: \( i^1 = i \), \( i^2 = -1 \), \( i^3 = -i \), and \( i^4 = 1 \). This cycle (\( i, -1, -i, 1 \)) repeats every four exponentiations.
02
Determine the Exponent's Modulo 4
Calculate the remainder when the exponent 100 is divided by 4, because \( i^4 = 1 \) resets the cycle. This means we only need \( 100 \mod 4 \) to find \( i^{100} \).
03
Calculate 100 Modulo 4
Perform the division: \[ 100 \div 4 = 25 \] with a remainder of \( 0 \). So, \( 100 \equiv 0 \mod 4 \).
04
Use the Cycle to Evaluate the Expression
Since \( 100 \equiv 0 \mod 4 \), this means \( i^{100} = i^0 \). From the properties of powers of \( i \), \( i^0 = 1 \). Hence, \( i^{100} \) simplifies to \( 1 \).
05
Write in the Form \( a + bi \)
The result \( i^{100} = 1 \) is already in the form \( a + bi \), with \( a = 1 \) and \( b = 0 \). Therefore, the expression is \( 1 + 0i \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Imaginary Unit
In the realm of complex numbers, the imaginary unit, denoted as \( i \), plays a crucial role. It is defined by the equation \( i^2 = -1 \). This definition sets the stage for a whole different world of numbers beyond the real number line. By using \( i \), complex numbers can represent solutions to equations where no real solutions exist. For example, the square root of a negative number, such as \( \sqrt{-1} \), can be written simply as \( i \).
This concept extends the number system from real numbers to complex numbers, expressed in the form \( a + bi \), where \( a \) and \( b \) are real numbers, and \( i \) is the imaginary unit. Complex numbers enable the visualization and mathematical manipulation of values in two dimensions, rather than just along a single number line.
This concept extends the number system from real numbers to complex numbers, expressed in the form \( a + bi \), where \( a \) and \( b \) are real numbers, and \( i \) is the imaginary unit. Complex numbers enable the visualization and mathematical manipulation of values in two dimensions, rather than just along a single number line.
- \( i \) is a fundamental unit in complex number arithmetic.
- It allows us to explore solutions and problems otherwise unsolvable with just real numbers.
- Often appears in electrical engineering, physics, and various fields of mathematics.
Powers of i
When working with the imaginary unit \( i \), understanding its powers becomes essential. Remarkably, powers of \( i \) follow a predictable cycle, repeating every four terms:
For instance, to simplify \( i^{100} \), you only need to determine where 100 falls in this cycle. By knowing this cycle:
- \( i^1 = i \)
- \( i^2 = -1 \)
- \( i^3 = -i \)
- \( i^4 = 1 \)
For instance, to simplify \( i^{100} \), you only need to determine where 100 falls in this cycle. By knowing this cycle:
- Every 4th power, \( i^{4n} \), is equal to 1.
- The sequence repeats, so identifying the position of the exponent in the sequence is key to simplification.
Modulo Arithmetic
Modulo arithmetic, or modular arithmetic, is akin to wrapping numbers around a circle, akin to a clock. It is a system of arithmetic for integers, where numbers "wrap around" after reaching a certain value, known as the modulus. Calculation "modulo 4" focuses on the remainder of dividing a number by 4.
When working with powers of \( i \), modular arithmetic is invaluable. Since the powers of \( i \) repeat every four terms, you can use this repetition to simplify calculations. In the exercise, you calculate \( 100 \mod 4 \) to help determine \( i^{100} \). Here, it's computed as:
When working with powers of \( i \), modular arithmetic is invaluable. Since the powers of \( i \) repeat every four terms, you can use this repetition to simplify calculations. In the exercise, you calculate \( 100 \mod 4 \) to help determine \( i^{100} \). Here, it's computed as:
- Divide 100 by 4, yielding a quotient of 25 with a remainder of 0.
- This zero remainder indicates that 100 falls exactly at the end of a cycle, or \( i^0 = 1 \).