Chapter 3: Problem 26
Factor the polynomial completely and find all its zeros. State the multiplicity of each zero. $$Q(x)=x^{4}+10 x^{2}+25$$
Short Answer
Expert verified
The zeros are \(x = \pm i\sqrt{5}\), each with multiplicity 2.
Step by step solution
01
Recognize the Polynomial Form
The given polynomial is of the form \(x^4 + 10x^2 + 25\). Notice that this is a quadratic in form, as it can be rewritten as \((x^2)^2 + 10(x^2) + 25\). This suggests that we might be able to factor it similarly to how we factor a quadratic.
02
Substitute and Simplify
Let \(u = x^2\), then the polynomial becomes \(u^2 + 10u + 25\). This is now clearly a quadratic expression in terms of \(u\). The goal now is to factor this quadratic expression.
03
Factor the Quadratic
To factor \(u^2 + 10u + 25\), look for two numbers that multiply to 25 and add up to 10. The numbers 5 and 5 satisfy this. So, we can write \(u^2 + 10u + 25 = (u + 5)(u + 5) = (u + 5)^2\).
04
Substitute Back the Original Variable
Replace \(u\) with \(x^2\) to get the expression back in terms of \(x\). Thus, \((u + 5)^2 = (x^2 + 5)^2\).
05
Find the Zeros
To find the zeros, solve the equation \((x^2 + 5)^2 = 0\). This implies \(x^2 + 5 = 0\). Solving for \(x^2 = -5\), we find that \(x = \pm \sqrt{-5} = \pm i\sqrt{5}\).
06
Determine the Multiplicity
The factor \((x^2 + 5)\) is squared in \(Q(x)\), which means both roots \(+i\sqrt{5}\) and \(-i\sqrt{5}\) each have a multiplicity of 2.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quadratic Form
A quadratic form is an expression that resembles the standard quadratic equation. In this scenario, the polynomial \( Q(x) = x^4 + 10x^2 + 25 \) appears more complex due to the \( x^4 \) term. However, with some observation, we can see it fits into a quadratic-like structure.
To simplify such expressions, we often use substitution. By letting \( u = x^2 \), the polynomial simplifies to \( u^2 + 10u + 25 \), which is a recognizable quadratic form. This substitution trick helps turn the problem into one we've faced before – making quadratic expressions easier to factor and manage.
Remember:
To simplify such expressions, we often use substitution. By letting \( u = x^2 \), the polynomial simplifies to \( u^2 + 10u + 25 \), which is a recognizable quadratic form. This substitution trick helps turn the problem into one we've faced before – making quadratic expressions easier to factor and manage.
Remember:
- Quadratic form doesn't always start with \( x^2 \). Sometimes you need creative substitutions.
- Look for replacements that simplify the higher order polynomial into a nestled quadratic form.
- Recognizing quadratic form patterns is essential in simplifying complex polynomials.
Complex Zeros
Complex zeros arise when a polynomial equals zero with a solution involving imaginary or non-real numbers. After factoring the polynomial, we reached the equation \((x^2 + 5)^2 = 0\), leading us to solve \(x^2 + 5 = 0\).
To solve \(x^2 + 5 = 0\), we rearrange it to \(x^2 = -5\), which suggests taking the square root results in an imaginary solution. Imaginary numbers are denoted with \(i\), where \(i\) is the square root of -1.
Here are the steps to derive complex zeros from \(x^2 = -5\):
Understanding complex zeros is crucial, especially when dealing with polynomials that do not factor into real numbers easily.
To solve \(x^2 + 5 = 0\), we rearrange it to \(x^2 = -5\), which suggests taking the square root results in an imaginary solution. Imaginary numbers are denoted with \(i\), where \(i\) is the square root of -1.
Here are the steps to derive complex zeros from \(x^2 = -5\):
- Take the square root of both sides: \(x = \pm \sqrt{-5}\).
- Implying \(x = \pm i\sqrt{5}\), where \(i\) represents \(\sqrt{-1}\).
Understanding complex zeros is crucial, especially when dealing with polynomials that do not factor into real numbers easily.
Multiplicity of Zeros
The multiplicity of zeros in a polynomial indicates how many times a particular zero appears. In our example, the factor \((x^2 + 5)\) is squared, resulting in multiplicity greater than one for each of its zeros.
Here's how to understand it:
Here's how to understand it:
- The equation \((x^2 + 5)^2 = 0\) suggests that zeros \(+i\sqrt{5}\) and \(-i\sqrt{5}\) each appear as solutions twice.
- Thus, both these zeros have a multiplicity of 2.
- This multiplicity impacts the polynomial's derivative and graph behavior around those zeros.