/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 12 Sketch the graph of the polynomi... [FREE SOLUTION] | 91Ó°ÊÓ

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Sketch the graph of the polynomial function. Make sure your graph shows all intercepts and exhibits the proper end behavior. $$P(x)=(x-1)(x+1)(x-2)$$

Short Answer

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Sketch a cubic graph passing through \((-1,0)\), \((0,2)\), \((1,0)\), \((2,0)\), rising from -∞ to +∞.

Step by step solution

01

Identify the Roots of the Polynomial

The polynomial given is \(P(x) = (x - 1)(x + 1)(x - 2)\). This is a cubic polynomial. The roots of the polynomial are the values of \(x\) that make \(P(x) = 0\). By setting each factor equal to zero, we find the roots: \(x = 1\), \(x = -1\), and \(x = 2\). These roots are the x-intercepts of the graph.
02

Determine the End Behavior

To determine the end behavior, observe the leading term of the expanded polynomial. When expanded, \(P(x) = x^3 - 2x^2 - x + 2\), the leading term is \(x^3\). Since the coefficient of \(x^3\) is positive and it's an odd power, as \(x\) approaches \(-\infty\), \(P(x)\) approaches \(-\infty\), and as \(x\) approaches \(+\infty\), \(P(x)\) approaches \(+\infty\). This describes the end behavior of the graph.
03

Find the Y-intercept

To find the y-intercept, evaluate \(P(x)\) at \(x = 0\). We have \(P(0) = (0 - 1)(0 + 1)(0 - 2) = (-1)(1)(-2) = 2\). Thus, the y-intercept is \((0, 2)\).
04

Sketch the Graph

Now, we can sketch the polynomial using the information from the previous steps. Plot the x-intercepts at \((-1, 0)\), \( (1, 0) \), and \( (2, 0) \). Mark the y-intercept at \((0, 2)\). The graph should pass through these points. Due to the end behavior, the graph will start from the bottom left (as \(x\to -\infty\), \(P(x)\to -\infty\)), rise through the intercept at \((0, 2)\), turn downwards after crossing \((1, 0)\), and finally turn upwards again after crossing \((2, 0)\) towards +∞.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Roots of the Polynomial
When dealing with polynomial functions like \(P(x) = (x - 1)(x + 1)(x - 2)\), finding the roots is an important step. The roots of a polynomial are the values of \(x\) that make the polynomial equation equal zero. Here, each factor can be individually set to zero to find the roots. These factors, \((x-1)\), \((x+1)\), and \((x-2)\), provide us with the roots \(x=1\), \(x=-1\), and \(x=2\) respectively.
Each root corresponds to an x-intercept on the graph of the polynomial function, meaning the graph will cross the x-axis at these points. Understanding roots helps in visualizing where the function changes its behavior, giving a clear framework for sketching the polynomial graph.
In summary, always set each factor of the polynomial equal to zero to solve for its roots. This tactic directly gives you the x-intercepts and aids in mapping out key points on the graph.
End Behavior
The end behavior of a polynomial graph describes how the function behaves as \(x\) approaches infinity or negative infinity. It's essential to understand this concept to predict the growth or decline trend of the polynomial function at its extremes. For the polynomial given \(P(x) = x^3 - 2x^2 - x + 2\), the leading term is \(x^3\). The leading term plays a critical role in determining the end behavior.
Since the coefficient of \(x^3\) is positive, and it is an odd power, the graph will behave differently at each end. As \(x\) approaches \(-\infty\), \(P(x)\) will also approach \(-\infty\), indicating the graph decreases as we move left. Conversely, as \(x\) approaches \(+\infty\), \(P(x)\) will grow towards \(+\infty\), indicating the graph rises as we move to the right.
Knowing this behavior is crucial when sketching polynomial graphs, as it helps indicate the direction in which the graph will extend beyond the plotted points.
X-intercepts
X-intercepts are crucial points on the graph where the function crosses the x-axis. These occur where the value of the polynomial is zero. For \(P(x) = (x-1)(x+1)(x-2)\), the x-intercepts occur at \(x = 1\), \(x = -1\), and \(x = 2\).
Plotting x-intercepts provides a clear indication of where the polynomial crosses the x-axis, allowing students to visually discern changes in the function's direction. Make sure each intercept is correctly placed on the graph when sketching. It not only provides ascertainable markers but also improves the accuracy of your sketch.
These intercepts serve as turning points or phases where the graph changes its trajectory, which is vital for understanding the function's graph.
Y-intercepts
The y-intercept of a polynomial function is the point where the graph intersects the y-axis. This happens when \(x\) is zero. To find the y-intercept, substitute \(x = 0\) into the polynomial equation. So in \(P(x) = (x-1)(x+1)(x-2)\), calculate \(P(0)\):
  • \((0 - 1) = -1\)
  • \((0 + 1) = 1\)
  • \((0 - 2) = -2\)

Multiply these results to get \((-1) \times 1 \times (-2) = 2\). Thus, the y-intercept is at the point \((0, 2)\), which tells you where the graph will intersect the y-axis.
The y-intercept provides a helpful reference point when sketching your graph, as it dictates how the curve moves initially from the y-axis.

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