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Find the domain of the function. $$h(x)=(x-3)^{-1 / 4}$$

Short Answer

Expert verified
The domain of the function is \((3, \infty)\).

Step by step solution

01

Understand the Function

The function given is \( h(x) = (x-3)^{-1/4} \). It involves an expression raised to a negative fractional power.
02

Identify Conditions for the Radical Function

For the expression \((x-3)^{-1/4}\) to be defined, the base \(x-3\) must be positive because only positive real numbers allow for real-valued roots when dealing with real exponents.
03

Solve the Inequality

Set the inequality \(x-3 > 0\). This requirement ensures that there are no issues with even roots of negative numbers or division by zero. Solve it to find: \(x > 3\).
04

Determine the Domain

The domain of the function is restricted to the values of \(x\) that satisfy the inequality. Therefore, the domain of \(h(x)\) is \((3, \infty)\), meaning all real numbers greater than 3.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Negative Fractional Power
Understanding negative fractional powers is crucial when dealing with certain types of functions. A negative fractional power involves two main components: negativity and fractionality.

Consider the function given in the exercise, \(h(x) = (x-3)^{-1/4}\). In this expression, \(-1/4\) is the exponent, where:
  • The "negative" part indicates that we are dealing with a reciprocal.
  • The "fractional" part (or \(1/4\) here) signifies that we are dealing with a root.
So, \((x-3)^{-1/4}\) means the reciprocal of the fourth root of \(x-3\). This can be rewritten as \(\frac{1}{\sqrt[4]{x-3}}\).

These properties influence the domain of the function, requiring \(x-3\) to be positive to get a real value for the root.
Radical Function
A radical function is one that contains roots, such as square roots, cube roots, or in this case, a fourth root.

Radical functions have specific requirements for their domain because taking even roots (like square roots or fourth roots) of negative numbers does not yield real numbers. In the function \(h(x) = (x-3)^{-1/4}\), if \(x-3\) is negative, the fourth root becomes undefined for real numbers.

To ensure the root is always calculated within real numbers, the expression inside the root, \(x-3\), must be greater than zero. This principle helps you identify the valid inputs for \(x\) in the domain, avoiding any undefined or imaginary numbers.
Inequality Solving
Solving inequalities is a foundation in finding domains of many functions, especially involving radicals or fractions.

For the problem at hand, solving the inequality \(x-3 > 0\) is necessary to determine where the function \(h(x)\) is defined. The inequality simply requires us to find when \(x\), the input to the function, makes the expression inside the radical positive.
  • Start by isolating \(x\), which gives: \(x > 3\).
  • This result implies that any number greater than 3 satisfies the inequality.
After solving the inequality, you can define the domain of the function as \((3, \infty)\) indicating that \(x\) can be any real number greater than 3. Solving such inequalities helps ensure that you're working within the region where the function behaves correctly without running into division by zero or taking roots of negative numbers.

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