/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 79 Find a function whose graph is t... [FREE SOLUTION] | 91Ó°ÊÓ

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Find a function whose graph is the given curve. The line segment joining the points (-2,1) and (4,-6)

Short Answer

Expert verified
The graph is represented by the function: \( y = -\frac{7}{6}x - \frac{4}{3} \).

Step by step solution

01

Identify the Type of Function

Given the curve is a line segment, the function is a linear function. A linear function generally has the form: \( y = mx + b \).
02

Find the Slope

The slope \( m \) of a line through two points \((x_1, y_1)\) and \((x_2, y_2)\) is given by \( m = \frac{y_2 - y_1}{x_2 - x_1} \). Substitute \( (x_1, y_1) = (-2, 1) \) and \( (x_2, y_2) = (4, -6) \) into the formula: \[ m = \frac{-6 - 1}{4 - (-2)} = \frac{-7}{6} \]
03

Use Point-Slope Form

Using the point-slope form of a line, \( y - y_1 = m(x - x_1) \), we can substitute one of the points, say \((-2, 1)\), and the slope \( m = -\frac{7}{6} \). The equation becomes:\[y - 1 = -\frac{7}{6}(x - (-2)) \] or \[ y - 1 = -\frac{7}{6}(x + 2) \]
04

Simplify the Equation

Distribute and simplify the equation:\[ y - 1 = -\frac{7}{6}x - \frac{14}{6} \]Simplifying \(-\frac{14}{6}\) gives \(-\frac{7}{3}\):\[ y - 1 = -\frac{7}{6}x - \frac{7}{3} \]Adding 1 to both sides gives:\[ y = -\frac{7}{6}x - \frac{7}{3} + 1 \]Convert 1 to a fraction with denominator 3:\[y = -\frac{7}{6}x - \frac{7}{3} + \frac{3}{3} \]Combine constants:\[ y = -\frac{7}{6}x - \frac{4}{3} \]
05

Final Function

The function that represents the line segment is:\[ y = -\frac{7}{6}x - \frac{4}{3} \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding the Slope Formula
The slope formula is a core concept in understanding linear functions. It helps us find the steepness of a line. The slope is represented by the letter \( m \) and calculated using the formula: \( m = \frac{y_2 - y_1}{x_2 - x_1} \). Here, \((x_1, y_1)\) and \((x_2, y_2)\) are any two points on the line.

The slope tells us how much \( y \) changes when \( x \) increases by one unit.
  • If the slope is positive, the line rises as we move from left to right.
  • If the slope is negative, the line falls.
  • If the slope is zero, the line is horizontal, indicating no change in \( y \) as \( x \) changes.
For example, using the points given in the problem,
  • Point 1: \((-2, 1)\)
  • Point 2: \((4, -6)\)
we apply the formula to find the slope: \( m = \frac{-6 - 1}{4 - (-2)} = \frac{-7}{6} \). This tells us that the line decreases by approximately 1.167 units in \( y \) for each unit increase in \( x \).
Understanding the slope formula is crucial to forming equations for linear functions.
Exploring the Point-Slope Form
Once we have the slope of a line, we can use it to form the equation of the line using the point-slope form. This formula is handy. It helps us write the equation quickly when we know one point on the line and the slope. The point-slope form is represented as \( y - y_1 = m(x - x_1) \). Here, \((x_1, y_1)\) is a point on the line and \( m \) is the slope.

For instance, in the exercise, we used the point \((-2, 1)\) and slope \(-\frac{7}{6}\) to frame the equation:
  • Substitute \((-2, 1)\) and \(-\frac{7}{6}\) into the formula:
\[ y - 1 = -\frac{7}{6}(x + 2) \] This form of the equation clearly shows the relation between the specific point chosen and the slope.
The point-slope form is very useful, especially in finding equations of lines quickly without the need for complicated algebraic manipulation.
Formulating Linear Equations
A linear equation represents a straight line in the Cartesian plane. It usually takes the form \( y = mx + b \), where \( m \) is the slope and \( b \) is the y-intercept. The y-intercept is the point where the line crosses the y-axis.

In our exercise, after using the point-slope form, we continued to simplify the equation to convert it into the linear equation form.
  • Start with: \( y - 1 = -\frac{7}{6}x - \frac{7}{3} \)
  • Add 1 to both sides and simplify: \( y = -\frac{7}{6}x - \frac{4}{3} \)
This is the final linear equation representing the line between the points \((-2,1)\) and \((4,-6)\).
Linear equations are essential in mathematics because they form the basis for understanding more complex functions and modeling real-world situations, like predicting trends or calculating rates of change.

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