Chapter 2: Problem 72
Find the maximum value of the function $$f(x)=3+4 x^{2}-x^{4}$$ [Hint: Let \(\left.t=x^{2} .\right]\)
Short Answer
Expert verified
The maximum value of the function is 7.
Step by step solution
01
Substitution Step
Let us substitute \(t = x^2\) so that the function \(f(x) = 3 + 4x^2 - x^4\) can be rewritten in terms of \(t\). This gives us \(f(t) = 3 + 4t - t^2\).
02
Write the Quadratic Function
The function in terms of \(t\) is now a quadratic: \(f(t) = -t^2 + 4t + 3\). This is a standard quadratic equation of the form \(f(t) = at^2 + bt + c\) where \(a = -1\), \(b = 4\), and \(c = 3\).
03
Find the Vertex
The maximum or minimum value of a quadratic function \(f(t) = at^2 + bt + c\) occurs at \(t = \frac{-b}{2a}\). Here, \(a = -1\) and \(b = 4\), so the maximum of \(f(t)\) occurs at \(t = \frac{-4}{2(-1)} = 2\).
04
Calculate the Maximum Value
Substitute \(t = 2\) back into the function: \(f(2) = -(2)^2 + 4(2) + 3 = -4 + 8 + 3 = 7\). Thus, the maximum value of \(f(t)\) is 7.
05
Relate to Original Function
Since \(t = x^2\) and the transformation was valid for real numbers, the maximum value of the original function \(f(x)\) can also be found when \(x^2 = 2\). Thus, \(f(x)\) reaches a maximum value of 7.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quadratic Functions
Quadratic functions are polynomial functions of the form \( ax^2 + bx + c \) where \( a \), \( b \), and \( c \) are constants, and \( a eq 0 \). In the case presented, we made a substitution, turning the original function into a quadratic. This makes it easier to analyze and find its maximum or minimum values. Key characteristics of quadratic functions:
- They graph as parabolas, which can open upwards if \( a > 0 \), or downwards if \( a < 0 \).
- The vertex of the parabola represents the maximum or minimum point.
- The axis of symmetry passes through the vertex, and it can be found using \( x = \frac{-b}{2a} \).
Function Substitution
Function substitution is a helpful technique for simplifying complex equations or expressions. By replacing parts of the function with a suitable variable, you can easily understand and solve it. In the given exercise, function substitution simplified \( f(x) = 3 + 4x^2 - x^4 \) to a quadratic form \( f(t) = 3 + 4t - t^2 \) by letting \( t = x^2 \). Why use substitution?
- Simplifies solving: By reducing the complexity of the function, we can tap into well-known methods for solving simpler equations, like quadratics.
- Makes visualization easier: A substitution can help turn a higher-degree polynomial into a standard quadratic, making it easier to graph and analyze.
- Uncovers underlying patterns: Sometimes substitutions reveal symmetries or other features not readily noticeable in the original form.
Vertex Formula
The vertex formula is an essential tool for finding the vertex of a quadratic function. For any quadratic function \( f(x) = ax^2 + bx + c \), the vertex \( (h, k) \) can be determined using:\[ h = \frac{-b}{2a} \]Once you find \( h \), substitute back into the function to find \( k = f(h) \), which is either the maximum or minimum value, depending on the parabola's orientation.For our quadratic equation \( f(t) = -t^2 + 4t + 3 \), we calculated:
- \( h = \frac{-4}{2(-1)} = 2 \)
- \( k = f(2) = -4 + 8 + 3 = 7 \)