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Find the domain and range of the function. $$f(x)=2 x^{2}+6 x-7$$

Short Answer

Expert verified
Domain: \((-\infty, \infty)\). Range: \([-\frac{23}{2}, \infty)\).

Step by step solution

01

Identify the Type of Function

The function given is a quadratic function written in the form \( f(x) = ax^2 + bx + c \), where \( a = 2 \), \( b = 6 \), and \( c = -7 \). We can recognize this as a parabola.
02

Determine the Domain

Since quadratic functions are defined for all real numbers, the domain of the function \( f(x) = 2x^2 + 6x - 7 \) is all real numbers, which is written in interval notation as \((-fty, fty)\).
03

Find the Vertex as the Extreme Point

The vertex formula for a parabola \( f(x) = ax^2 + bx + c \) is given by \( x = -\frac{b}{2a} \). Substituting the values, we get \( x = -\frac{6}{2(2)} = -\frac{3}{2} \).
04

Calculate the Vertex's y-coordinate

Substitute \( x = -\frac{3}{2} \) into the function to find the y-coordinate. \[ f\left(-\frac{3}{2}\right) = 2\left(-\frac{3}{2}\right)^2 + 6\left(-\frac{3}{2}\right) - 7 \] \[ = 2\left(\frac{9}{4}\right) - 9 - 7 = \frac{9}{2} - \frac{32}{2} = -\frac{23}{2} \].
05

Determine the Range

Since the parabola opens upwards (as the coefficient of \( x^2 \) is positive), the vertex represents the minimum point of the function. Therefore, the range is from \(-\frac{23}{2}\) to infinity. In interval notation, the range is \([-\frac{23}{2}, fty)\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Domain and Range
When dealing with quadratic functions, we often need to determine their domain and range. The domain of a function is the set of all possible input values (usually represented by the variable \( x \)) that the function can accept. For quadratic functions like \( f(x) = 2x^2 + 6x - 7 \), the input can be any real number.
Therefore, the domain is all real numbers, which can be expressed as an interval: \((-fty, \infty)\). This essentially means there's no restriction on the values that \( x \) can take.
The range, on the other hand, is the set of all possible output values (usually represented by \( f(x) \)). The nature of a quadratic function as a parabolic function determines this. The graph of a parabola can either open upwards or downwards, depending on the sign of the coefficient of \( x^2 \).
  • If the coefficient of \( x^2 \), \( a \), is positive, the parabola opens upwards.
  • If \( a \) is negative, the parabola opens downwards.
In our function, since \( a = 2 \) (positive), the parabola opens upwards and consequently has a minimum point, the vertex. Hence, the range of our function is from the y-coordinate of the vertex to infinity: \([- rac{23}{2}, \infty)\).
Parabolic Functions
Parabolic functions are a subset of polynomial functions of degree two. They are represented by the general form \( f(x) = ax^2 + bx + c \). These functions produce graphs known as parabolas, which are mirror-symmetrical and have distinct features such as a vertex, axis of symmetry, and either a maximum or minimum point.
Parabolas open upwards or downwards based on the coefficient of \( x^2 \). Here are some characteristics:
  • If the parabola opens upwards (\( a > 0 \)), it has a minimum point.
  • If it opens downwards (\( a < 0 \)), it has a maximum point.
  • The vertex of the parabola represents either this minimum or maximum value.
  • Parabolas are symmetric about a vertical line running through the vertex, called the axis of symmetry.
Understanding these basic properties helps predict the shape and behavior of a parabolic function graph.
The quadratic function \( f(x) = 2x^2 + 6x - 7 \) gives us an upward opening parabola due to the positive \( a \), indicating it has a minimum vertex. This important characteristic determines the function's range and behavior.
Vertex of a Parabola
The vertex of a parabola is a crucial element in understanding the properties and graph of a quadratic function. It represents the point where the function reaches its minimum or maximum value. For the quadratic function \( f(x) = ax^2 + bx + c \), the x-coordinate of the vertex can be calculated using the formula \( x = -\frac{b}{2a} \).
For our function, \( a = 2 \) and \( b = 6 \), so substituting into the formula gives us:
\( x = -\frac{6}{2(2)} = -\frac{3}{2} \).
The y-coordinate of the vertex is found by plugging this x-value back into the original function. So,
\( f\left(-\frac{3}{2}\right) = 2\left(-\frac{3}{2}\right)^2 + 6\left(-\frac{3}{2}\right) - 7 \), which simplifies to \( -\frac{23}{2} \).
Thus, the vertex of \( f(x) = 2x^2 + 6x - 7 \) is \( \left(-\frac{3}{2}, -\frac{23}{2}\right) \). It defines the minimum point of the parabola, indicating the lowest output the function can achieve. This vertex plays a pivotal role in establishing the range and symmetry of the function.

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