/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 42 Sketch the graph of the piecewis... [FREE SOLUTION] | 91Ó°ÊÓ

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Sketch the graph of the piecewise defined function. $$f(x)=\left\\{\begin{array}{ll}2 x+3 & \text { if } x<-1 \\ 3-x & \text { if } x \geq-1\end{array}\right.$$

Short Answer

Expert verified
The graph is a combination of two linear pieces: \( 2x + 3 \) for \( x < -1 \), and \( 3-x \) for \( x \geq -1 \).

Step by step solution

01

Understand the Piecewise Function

The function \( f(x) \) is defined by two different equations depending on the value of \( x \). For \( x < -1 \), the function is represented by \( 2x + 3 \). For \( x \geq -1 \), the function is represented by \( 3 - x \).
02

Analyze the First Piece

The first piece of the function is \( 2x + 3 \) for \( x < -1 \). This is a linear equation with a slope of 2 and a y-intercept of 3. Determine a couple of points by selecting values of \( x \) less than -1. For example: When \( x = -2 \), \( f(x) = 2(-2) + 3 = -4 + 3 = -1 \). When \( x = -3 \), \( f(x) = 2(-3) + 3 = -6 + 3 = -3 \).
03

Analyze the Second Piece

The second piece of the function is \( 3 - x \) for \( x \geq -1 \). This is also a linear equation with a slope of -1 and a y-intercept of 3. Determine a couple of points by selecting values of \( x \) greater than or equal to -1. For example: When \( x = -1 \), \( f(x) = 3 - (-1) = 4 \). When \( x = 0 \), \( f(x) = 3 - 0 = 3 \).
04

Plot the Points and Draw the Graph

On a coordinate plane, plot the points obtained in Steps 2 and 3. For the first piece, plot (-3, -3) and (-2, -1). Since this is for \( x < -1 \), draw a line through these points extending to negative infinity but stop at \( x = -1 \) with an open circle. For the second piece, plot (-1, 4) and (0, 3). Since this is for \( x \geq -1 \), start at \( x = -1 \) with a closed circle and draw a line through these points extending to positive infinity.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Linear Equations
Linear equations are fundamental in algebra. They have the general form \( y = mx + b \), where \( m \) represents the slope and \( b \) is the y-intercept. Such equations plot to form straight lines on a graph. The key aspect of linear equations is that the graph of these functions remains straight, no matter the portion of the function you evaluate.
\( m \) or the slope describes how steep the line is. It shows how much \( y \) increases or decreases when \( x \) increases by 1. A positive slope means the line goes upwards, while a negative slope means it goes downwards. Meanwhile, the y-intercept, \( b \), shows where the line crosses the y-axis.
This concept is crucial for graphing functions, especially when dealing with piecewise functions, where understanding each segment or 'piece' involves linear equations. Linear functions are one of the simplest types to graph, making them a great starting point for learning about more complex functions.
Slope and Y-Intercept
The slope and y-intercept are two critical characteristics of a linear function. The slope, often shown as \( m \), measures the line's incline. It is calculated as the change in \( y \) over the change in \( x \), often written as \( \frac{\Delta y}{\Delta x} \). For instance, if for a function, moving 1 unit on the \( x \)-axis increases \( y \) by 2, then the slope \( m \) is 2.
Meanwhile, the y-intercept \( b \) signals the specific point where the function's line crosses the y-axis. In other words, it's the value of \( y \) when \( x \) is 0. Knowing the slope and y-intercept helps in quickly sketching the line graph of the equation. You start at \( b \) on the y-axis, then use \( m \) to find the direction and steepness of the line.
Both elements are vital when analyzing piecewise functions. As each segment of the function may have its slope and intercept, understanding these ensures each section is correctly represented.
Graphing Functions
Graphing functions requires understanding both algebra and visuals. When dealing with piecewise functions, this involves plotting separate linear equations as sections of the graph. Each piece of a piecewise function is graphed independently based on its conditions. It's like stitching together parts of different lines to form a complete picture on the graph.
To start graphing a piecewise function, evaluate each section at several points within its specified domain. For example, evaluate the equation for specific \( x \) values to get the corresponding \( y \) values. Plot these pairs on a coordinate plane, and connect them according to each part of the function. Pay attention to the boundary conditions—whether they are open or closed circles—indicating whether or not the endpoint is included.
Efforts in graphing not only translate equations into visible representations, but also provide deeper insight into how the function behaves across different regions. This thorough understanding of graphing can illuminate concepts and facilitate more complex calculations.

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Most popular questions from this chapter

A family of functions is given. In parts (a) and (b) graph all the given members of the family in the viewing rectangle indicated. In part (c) state the conclusions you can make from your graphs. \(f(x)=x^{c}\) (a) \(c=\frac{1}{2}, \frac{1}{4}, \frac{1}{6} ; \quad[-1,4]\) by \([-1,3]\) (b) \(c=1, \frac{1}{3}, \frac{1}{5} ; \quad[-3,3]\) by \([-2,2]\) (c) How does the value of \(c\) affect the graph?

Changing Temperature Scales The temperature on a certain afternoon is modeled by the function $$C(t)=\frac{1}{2} t^{2}+2$$ where \(t\) represents hours after 12 noon \((0 \leq t \leq 6),\) and \(C\) is measured in "C. (a) What shifting and shrinking operations must be performed on the function \(y=t^{2}\) to obtain the function \(y=C(t) ?\) (b) Suppose you want to measure the temperature in "F instead. What transformation would you have to apply to the function \(y=C(t)\) to accomplish this? (Use the fact that the relationship between Celsius and Fahrenheit degrees is given by \(F=\frac{9}{5} C+32 .\) ) Write the new function \(y=F(t)\) that results from this transformation.

Find the functions \(f \circ g, g \circ f, f \circ f,\) and \(g \circ g\) and their domains. $$f(x)=\sqrt[3]{x}, \quad g(x)=\sqrt[4]{x}$$

In Exercise 65 of Section 2.7 you were asked to solve equations in which the unknowns were functions. Now that we know about inverses and the identity function (see Exercise \(82),\) we can use algebra to solve such equations. For instance, to solve \(f \circ g=h\) for the unknown function \(f\) we perform the following steps: \(f \circ g=h\) Problem: Solve for \(f\) \(f \circ g \circ g^{-1}=h \circ g^{-1} \quad\) Compose with \(g^{-1}\) on the right \(f \circ I=h \circ g^{-1} \quad g \circ g^{-1}=I\) \(f=h \circ g^{-1} \quad\) f \(\circ I=f\) So the solution is \(f=h \circ g^{-1} .\) Use this technique to solve the equation \(f \circ g=h\) for the indicated unknown function. (a) Solve for \(f,\) where \(g(x)=2 x+1\) and \(h(x)=4 x^{2}+4 x+7\) (b) Solve for \(g,\) where \(f(x)=3 x+5\) and \(h(x)=3 x^{2}+3 x+2\)

You have a \(\$ 50\) coupon from the manufacturer good for the purchase of a cell phone. The store where you are purchasing your cell phone is offering a \(20 \%\) discount on all cell phones. Let \(x\) represent the regular price of the cell phone. (a) Suppose only the \(20 \%\) discount applies. Find a function \(f\) that models the purchase price of the cell phone as a function of the regular price \(x\). (b) Suppose only the \(\$ 50\) coupon applies. Find a function \(g\) that models the purchase price of the cell phone as a function of the sticker price \(x\)

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