Chapter 2: Problem 38
Find the maximum or minimum value of the function. $$g(x)=2 x(x-4)+7$$
Short Answer
Expert verified
The minimum value is -1.
Step by step solution
01
Expand the Function
The given function is \( g(x) = 2x(x-4) + 7 \). First, we need to expand this function to understand its general form. \[ g(x) = 2x^2 - 8x + 7 \] Thus, the function is a quadratic equation in the form \( g(x) = ax^2 + bx + c \) with \( a = 2 \), \( b = -8 \), and \( c = 7 \).
02
Find the Vertex
For a quadratic function \( g(x) = ax^2 + bx + c \), the vertex \( x \)-coordinate is given by the formula: \[ x = -\frac{b}{2a} \] Substituting the values of \( a \) and \( b \):\[ x = -\frac{-8}{2 \times 2} = 2 \] Thus, the vertex \( x \)-coordinate is 2.
03
Determine the Type of Extremum
To determine whether the vertex gives a maximum or minimum value, we consider the coefficient \( a \) from the quadratic equation. When \( a > 0 \), the quadratic opens upwards, indicating a minimum value. Since \( a = 2 \) and \( 2 > 0 \), the vertex represents the minimum point of the function.
04
Calculate the Minimum Value
Substitute \( x = 2 \) back into the function to find the minimum value:\[ g(x) = 2(2)^2 - 8(2) + 7 \] Calculating:\[ g(x) = 8 - 16 + 7 = -1 \] Thus, the minimum value of the function is \(-1\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Vertex Form
The vertex form of a quadratic function makes it easy to identify the vertex of the parabola, which is either a maximum or a minimum point depending on the direction the parabola opens. In general, the vertex form is given by:\[ g(x) = a(x-h)^2 + k \]Here:
- \(a\) determines the direction and the width of the parabola.
- \(h\) and \(k\) are the coordinates of the vertex \((h, k)\).
- The vertex of the quadratic function.
- The axis of symmetry of the parabola \(x=h\), which cuts the parabola into two symmetric halves.
Minimum Value
The minimum value of a quadratic function is the smallest value that the function can take. For quadratic functions of the form \(g(x) = ax^2 + bx + c\), the minimum or maximum value occurs at the vertex. To find the vertex, use the formula for the \(x\)-coordinate:\[ x = -\frac{b}{2a} \]With \(a = 2\) and \(b = -8\) from the problem, this leads to \(x = 2\). Given that \(a > 0\) (which is true for this problem), the parabola opens upwards. This means the vertex is the point where the minimum value occurs. Once you have the \(x\)-coordinate of the vertex, substitute it back into the original equation to find the corresponding \(y\)-coordinate or minimum value:\[ g(2) = 2(2)^2 - 8(2) + 7 \]Simplifying this gives a minimum value of \(g(2) = -1\). This vertex represents the lowest point on the curve.
Expanding Quadratic Expressions
Expanding a quadratic expression involves removing parentheses and simplifying the expression to the standard form \(ax^2 + bx + c\). For the problem at hand, the given expression was \(g(x) = 2x(x-4) + 7\). To expand it, distribute the \(2x\) across the \((x-4)\):
- \(2x \times x = 2x^2\)
- \(2x \times -4 = -8x\)