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Find the functions \(f \circ g, g \circ f, f \circ f,\) and \(g \circ g\) and their domains. $$f(x)=\frac{1}{\sqrt{x}}, \quad g(x)=x^{2}-4 x$$

Short Answer

Expert verified
\( f \circ g = \frac{1}{\sqrt{x^2 - 4x}}, \; \text{Domain:} \; (-\infty,0) \cup (4,\infty) \) \( g \circ f = \frac{1}{x} - \frac{4}{\sqrt{x}}, \; \text{Domain:} \; (0,\infty) \) \( f \circ f = \sqrt[4]{x}, \; \text{Domain:} \; (0,\infty) \) \( g \circ g = x^4-8x^3+12x^2+16x, \; \text{Domain:} \; \mathbb{R} \).

Step by step solution

01

Find the function \( f \circ g \)

Compute \( f(g(x)) \). The function \( g(x) = x^2 - 4x \). Substitute \( g(x) \) into \( f(x) \):\[f(g(x)) = f(x^2 - 4x) = \frac{1}{\sqrt{x^2 - 4x}}\]The domain of \( f(g(x)) \) is where the expression under the square root is positive: \( x^2 - 4x > 0 \). Solve this inequality by factoring:\( x(x - 4) > 0 \).The critical points are \( x = 0 \) and \( x = 4 \). Using a sign chart or testing intervals, we find:- \( x < 0 \) and \( x > 4 \) satisfy the inequality.Thus, the domain is \( (-\infty, 0) \cup (4, \infty) \).
02

Find the function \( g \circ f \)

Compute \( g(f(x)) \). The function \( f(x) = \frac{1}{\sqrt{x}} \). Substitute \( f(x) \) into \( g(x) \):\[g(f(x)) = g\left(\frac{1}{\sqrt{x}}\right) = \left(\frac{1}{\sqrt{x}}\right)^2 - 4\left(\frac{1}{\sqrt{x}}\right)\]Simplifying,\[g(f(x)) = \frac{1}{x} - \frac{4}{\sqrt{x}}\]For \( g(f(x)) \) to be defined, \( x > 0 \). Thus, the domain is \( (0, \infty) \).
03

Find the function \( f \circ f \)

Compute \( f(f(x)) \). Substitute \( f(x) \) into itself:\[f(f(x)) = f\left(\frac{1}{\sqrt{x}}\right) = \frac{1}{\sqrt{\frac{1}{\sqrt{x}}}}\]Simplifying further,\[f(f(x)) = \sqrt[4]{x}\]The domain is \( x > 0 \) because both inner and outer functions require the argument to be positive. Thus, the domain is \( (0, \infty) \).
04

Find the function \( g \circ g \)

Compute \( g(g(x)) \). Substitute \( g(x) \) into itself:\[g(g(x)) = g(x^2-4x) = (x^2 - 4x)^2 - 4(x^2 - 4x)\]Expanding,\[g(g(x)) = x^4 - 8x^3 + 16x^2 - 4x^2 + 16x = x^4 - 8x^3 + 12x^2 + 16x\]The polynomial function \( g(g(x)) \) has a domain of all real numbers \( (-\infty, \infty) \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Domain of Functions
When dealing with functions, understanding their domain is crucial. The domain of a function is the set of all possible inputs for which the function is defined. In simpler terms, it answers the question: "What values of \( x \) can we plug into this function?" To find a function's domain, especially when dealing with composite functions, we need to consider the domains of all involved functions.

For the function \( f(x) = \frac{1}{\sqrt{x}} \), the domain is all \( x > 0 \), because the expression \( \sqrt{x} \) is only defined for positive \( x \), and the denominator cannot be zero.

In the case of the composite function \( f \circ g \), we start by considering the domain of \( g(x) = x^2 - 4x \), which is all real numbers. However, when this output is used as an input for \( f(x) \), it must be greater than zero: \( g(x) = x^2 - 4x > 0 \). Solving this inequality gives the values \( x < 0 \) or \( x > 4 \) where the domain of \( f \circ g \) is defined, resulting in \((-\infty, 0) \cup (4, \infty)\).

The careful consideration of each function's domain is essential when determining the composite function's domain.
Composite Functions
Composite functions involve combining two or more functions. Essentially, you apply one function's output as the input of another. We represent this with notation like \( f \circ g \), read as "\( f \) composed with \( g \)." To find \( f \circ g(x) \), you substitute \( g(x) \) into every instance of \( x \) in \( f(x) \).

For example, to determine \( f \circ g \) from the given functions \( f(x) = \frac{1}{\sqrt{x}} \) and \( g(x) = x^2 - 4x \), we'd calculate \( f(g(x)) = \frac{1}{\sqrt{x^2 - 4x}} \). This is the result of inserting \( g(x) \) into the function \( f \). Likewise, \( g \circ f(x) \) means substituting \( f(x) \) into \( g(x) \), calculated as \( g\left(\frac{1}{\sqrt{x}}\right) = \frac{1}{x} - \frac{4}{\sqrt{x}} \).

The composition of functions requires attention to detail to ensure that the resulting function is fully simplified and correct for its domain. Practicing with various combinations is a great way to master this mathematical concept.
Function Operations
Function operations are a set of techniques used to combine and manipulate functions to form new ones. Common operations include addition, subtraction, multiplication, and division, but composition also plays a key role.

When working with function composition, you essentially create a new function by using the entire output of one function as the input of another, as seen with \( f \circ g \). This is more complex than basic operations as it involves substitution, which requires careful handling of domains. Each step of substitution should be computed carefully, simplifying wherever possible.

For instance, with \( f \circ f \), we substitute the function into itself: \( f(f(x)) = \sqrt[4]{x} \). This shows how intricate function composition can be as the operations mix like Russian nesting dolls, each opening to reveal another layer. Operations on functions can transform simple equations into complex forms, providing valuable methods to solve real-world problems by combining functions in meaningful ways.

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Most popular questions from this chapter

Graph the functions on the same screen using the given viewing rectangle. How is each graph related to the graph in part (a)? Viewing rectangle \([-6,6]\) by \([-4,4]\) (a) \(y=\frac{1}{\sqrt{x}}\) (b) \(y=\frac{1}{\sqrt{x+3}}\) (c) \(y=\frac{1}{2 \sqrt{x+3}}\) (d) \(y=\frac{1}{2 \sqrt{x+3}}-3\)

Minimizing Time A man stands at a point \(A\) on the bank of a straight river, 2 mi wide. To reach point \(B\), \(7 \mathrm{mi}\) downstream on the opposite bank, he first rows his boat to point \(P\) on the opposite bank and then walks the remaining distance \(x\) to \(B\), as shown in the figure. He can row at a speed of \(2 \mathrm{mi} / \mathrm{h}\) and walk at a speed of \(5 \mathrm{mi} / \mathrm{h}\) (a) Find a function that models the time needed for the trip. (b) Where should he land so that he reaches \(B\) as soon as possible? (cant copy image)

Sketch the graph of each function. (a) \(f(x)=4 x-x^{2}\) (b) \(g(x)=\left|4 x-x^{2}\right|\)

Sums of Even and Odd Functions If \(f\) and \(g\) are both even functions, is \(f+g\) necessarily even? If both are odd, is their sum necessarily odd? What can you say about the sum if one is odd and one is even? In each case, prove your answer.

In the margin notes in this section we pointed out that the inverse of a function can be found by simply reversing the operations that make up the function. For instance, in Example 6 we saw that the inverse of $$f(x)=3 x-2 \quad \text { is } \quad f^{-1}(x)=\frac{x+2}{3}$$ because the "reverse" of "multiply by 3 and subtract 2" is "add 2 and divide by 3 " Use the same procedure to find the inverse of the following functions. (a) \(f(x)=\frac{2 x+1}{5}\) (b) \(f(x)=3-\frac{1}{x}\) (c) \(f(x)=\sqrt{x^{3}+2}\) (d) \(f(x)=(2 x-5)^{3}\) Now consider another function: \(f(x)=x^{3}+2 x+6\) Is it possible to use the same sort of simple reversal of operations to find the inverse of this function? If so, do it. If not, explain what is different about this function that makes this task difficult.

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