Chapter 2: Problem 37
Find the maximum or minimum value of the function. $$f(x)=3-x-\frac{1}{2} x^{2}$$
Short Answer
Expert verified
The maximum value of the function is 3.5.
Step by step solution
01
Identify the Type of Function
The function given is a quadratic function of the form \( f(x) = ax^2 + bx + c \), where \( a = -\frac{1}{2} \), \( b = -1 \), and \( c = 3 \). Since \( a < 0 \), the parabola opens downwards, indicating the function has a maximum point.
02
Find the Vertex Using the Vertex Formula
The maximum or minimum value of a quadratic function occurs at its vertex. The x-coordinate of the vertex for the function \( ax^2 + bx + c \) can be found using the formula \( x = -\frac{b}{2a} \). Plugging in the values \( a = -\frac{1}{2} \) and \( b = -1 \), we find \( x = -\frac{-1}{2 \times -\frac{1}{2}} = -1 \).
03
Substitute the Vertex into the Function
Substitute \( x = -1 \) back into the function to find the corresponding \( y \)-value. Calculate \( f(-1) = 3 - (-1) - \frac{1}{2}(-1)^2 \). Simplifying gives \( f(-1) = 3 + 1 - \frac{1}{2} = 3.5 \).
04
Determine the Maximum Value of the Function
Since the vertex where \( x = -1 \) gives \( f(x) = 3.5 \), and the parabola opens downwards, the maximum value of the function is \( 3.5 \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Vertex Formula
The vertex formula is a handy tool for finding the vertex of a quadratic function. A quadratic function is often written in the form of \( ax^2 + bx + c \), and the vertex represents a critical point of this function. By using the vertex formula, you can find the x-coordinate of the vertex, which is \( x = -\frac{b}{2a} \).
For our function \( f(x) = -\frac{1}{2}x^2 - x + 3 \), we identify:\
For our function \( f(x) = -\frac{1}{2}x^2 - x + 3 \), we identify:\
- \( a = -\frac{1}{2} \) (coefficient of \( x^2 \))
\( b = -1 \) (coefficient of \( x \))
\( c = 3 \) (constant term)
Maximum Value
Quadratic functions can show either a maximum or a minimum value because of their parabolic shape. For a parabola that opens downwards, like in our example, the vertex is where the function reaches its maximum value. This is determined by the sign of \( a \), the coefficient of \( x^2 \).
In our function, \( a = -\frac{1}{2} \), which means the parabola opens downwards. Therefore, it has a maximum value. Once you find the x-coordinate of the vertex, substitute it back into the function to find the corresponding y-value. For our function's vertex \( x = -1 \):\[\begin{align*} f(-1) &= 3 - (-1) - \frac{1}{2}(-1)^2 \&= 3 + 1 - \frac{1}{2} \&= 3.5 \end{align*}\] Thus, the maximum value of this function is \( 3.5 \), occurring at \( x = -1 \).
In our function, \( a = -\frac{1}{2} \), which means the parabola opens downwards. Therefore, it has a maximum value. Once you find the x-coordinate of the vertex, substitute it back into the function to find the corresponding y-value. For our function's vertex \( x = -1 \):\[\begin{align*} f(-1) &= 3 - (-1) - \frac{1}{2}(-1)^2 \&= 3 + 1 - \frac{1}{2} \&= 3.5 \end{align*}\] Thus, the maximum value of this function is \( 3.5 \), occurring at \( x = -1 \).
Parabolic Graph
A quadratic function manifests as a parabolic graph when plotted. The equation \( f(x) = ax^2 + bx + c \) defines the shape and direction of this parabola. Key characteristics of the parabola include:
- It opens upwards if \( a > 0 \), showing a minimum point.
- It opens downwards if \( a < 0 \), showing a maximum point.