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Use the Inverse Function Property to show that f and g are inverses of each other. $$\begin{aligned}&f(x)=x^{2}-4, \quad x \geq 0\\\&g(x)=\sqrt{x+4}, \quad x \geq-4\end{aligned}$$

Short Answer

Expert verified
Functions \( f(x) = x^2 - 4 \) and \( g(x) = \sqrt{x+4} \) are inverses on their domains.

Step by step solution

01

Understand the Inverse Property

Two functions \( f \) and \( g \) are inverses of each other if \( f(g(x)) = x \) and \( g(f(x)) = x \) for all \( x \) in their respective domains.
02

Simplify \( f(g(x)) \)

Substitute \( g(x) \) into \( f(x) \): \[ f(g(x)) = f(\sqrt{x+4}) = (\sqrt{x+4})^2 - 4 \]. Simplify by squaring the square root: \[ (\sqrt{x+4})^2 = x + 4 \]. Therefore, \( f(g(x)) = x + 4 - 4 = x \).
03

Simplify \( g(f(x)) \)

Substitute \( f(x) \) into \( g(x) \): \[ g(f(x)) = g(x^2 - 4) = \sqrt{(x^2 - 4) + 4} \]. Simplify inside the square root: \[ (x^2 - 4) + 4 = x^2 \]. Therefore, \( g(f(x)) = \sqrt{x^2} = x \).
04

Verify Domain Conditions

Ensure the domain conditions are satisfied. For \( f(x) \), \( x \geq 0 \), and for \( g(x) \), \( x \geq -4 \). Since both conditions are satisfied by the definitions of \( f \) and \( g \), the inverses' calculations hold true.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Inverse Function Property
The Inverse Function Property is a fascinating aspect of mathematics. It reveals if two functions, say \( f \) and \( g \), are inverses of each other. This is the case when both \( f(g(x)) = x \) and \( g(f(x)) = x \). The key point here is that when one function undoes the action of the other, their combination yields the starting value \( x \). This property ensures a symmetric relationship between \( f \) and \( g \).
  • If you input \( x \) into \( g \) and take the result through \( f \), you return to \( x \).
  • Conversely, if you start with \( x \) in \( f \) and pipe it through \( g \), you should also retrieve \( x \).
Understanding this property helps greatly simplify mathematical problems and verify whether two functions are indeed inverses of each other. Ensuring that this property holds true is essential in exercises like the one you might encounter in a textbook problem.
Function Composition
Function Composition involves plugging one function into another. It鈥檚 like following a recipe where each step depends on the outcome of the previous one.
Suppose you have two functions, \( f(x) \) and \( g(x) \). The composition \( f(g(x)) \) means taking the output of \( g(x) \) and using it as the input for \( f(x) \). In simpler terms, it鈥檚 saying, "First do \( g \), then do \( f \).鈥 This way, the output from \( g(x) \) directly influences the result you get from \( f(x) \).
  • When verifying inverses, composing two functions helps demonstrate that their actions can cancel each other out, as indicated in \( f(g(x)) = x \).
  • The opposite order, \( g(f(x)) \), must similarly resolve to \( x \) to confirm that \( f \) and \( g \) are truly inverses.
Function composition allows you to see how functions interact and can address complex equations simply by plugging one equation into another.
Domain and Range
The Domain and Range of functions are crucial in understanding their behavior and interactions. The domain is the collection of all possible input values \( x \) that a function can accept without leading to undefined expressions. The range, on the other hand, includes all possible output values derived from those inputs.
For the inverse functions, it's vital to ensure that these domains and ranges align properly. For instance:
  • The domain of \( f(x)=x^2 - 4 \) should be \( x \geq 0 \), ensuring the output covers the range suitable for \( g \).
  • Meanwhile, \( g(x)=\sqrt{x+4} \) has a domain \( x \geq -4 \) to cover when combining expressions.
Matching these beginning and resulting values between inverses confirms that the calculations are contextually valid. Misalignments between domain and range can disrupt the inverse relationship, making verification vital in exercises checking for inverses.

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Most popular questions from this chapter

The relative value of currencies fluctuates every day. When this problem was written, one Canadian dollar was worth 0.8159 U.S. dollar. (a) Find a function \(f\) that gives the U.S. dollar value \(f(x)\) of \(x\) Canadian dollars. (b) Find \(f^{-1} .\) What does \(f^{-1}\) represent? (c) How much Canadian money would \(\$ 12,250\) in U.S. currency be worth?

Even and Odd Power Functions What must be true about the integer \(n\) if the function $$ f(x)=x^{n} $$ is an even function? If it is an odd function? Why do you think the names "even" and "odd" were chosen for these function properties?

Graph of the Absolute Value of a Function (a) Draw the graphs of the functions \(f(x)=x^{2}+x-6\) and \(g(x)=\left|x^{2}+x-6\right| .\) How are the graphs of \(f\) and \(g\) related? (b) Draw the graphs of the functions \(f(x)=x^{4}-6 x^{2}\) and \(g(x)=\left|x^{4}-6 x^{2}\right| .\) How are the graphs of \(f\) and \(g\) related? (c) In general, if \(g(x)=|f(x)|,\) how are the graphs of \(f\) and \(g\) related? Draw graphs to illustrate your answer.

Suppose that $$\begin{array}{l}g(x)=2 x+1 \\\h(x)=4 x^{2}+4 x+7\end{array}$$ Find a function \(f\) such that \(f \circ g=h .\) (Think about what operations you would have to perform on the formula for \(g\) to end up with the formula for \(h .\) ) Now suppose that $$\begin{array}{l}f(x)=3 x+5 \\\h(x)=3 x^{2}+3 x+2\end{array}$$ Use the same sort of reasoning to find a function \(g\) such that \(f \circ g=h\)

Graph the functions on the same screen using the given viewing rectangle. How is each graph related to the graph in part (a)? Viewing rectangle \([-8,8]\) by \([-2,8]\) (a) \(y=\sqrt[4]{x}\) (b) \(y=\sqrt[4]{x+5}\) (c) \(y=2 \sqrt[4]{x+5}\) (d) \(y=4+2 \sqrt[4]{x+5}\)

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