/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 11 Sketch the graph of the function... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Sketch the graph of the function by first making a table of values. \(g(x)=\sqrt{x+4}\)

Short Answer

Expert verified
Plot points from the calculated table and draw a smooth curve for the graph of \(g(x)=\sqrt{x+4}\).

Step by step solution

01

Identify the Domain of the Function

The function is defined as \(g(x)=\sqrt{x+4}\). Since we cannot take the square root of a negative number, the expression inside the square root, \(x+4\), needs to be greater than or equal to zero. Solve \(x+4 \geq 0\) to find \(x \geq -4\). Therefore, the domain of this function is \(x \in [-4, \infty)\).
02

Select Appropriate Values for x

Select several values of \(x\) within the domain \([-4, \infty)\). Choose values that make calculation easy and cover several intervals, such as \(x = -4, -3, 0, 1, 5\).
03

Calculate Corresponding Values of g(x)

For each selected value of \(x\), calculate \(g(x)\) using the function \(g(x) = \sqrt{x + 4}\).1. \(x = -4\): \(g(-4) = \sqrt{-4 + 4} = 0\).2. \(x = -3\): \(g(-3) = \sqrt{-3 + 4} = \sqrt{1} = 1\).3. \(x = 0\): \(g(0) = \sqrt{0 + 4} = \sqrt{4} = 2\).4. \(x = 1\): \(g(1) = \sqrt{1 + 4} = \sqrt{5}\).5. \(x = 5\): \(g(5) = \sqrt{5 + 4} = \sqrt{9} = 3\).
04

Create a Table of Values

Using the calculations from Step 3, create a table showing the values of \(x\) and their corresponding \(g(x)\) values:\[\begin{array}{|c|c|}\hlinex & g(x) \\hline-4 & 0 \-3 & 1 \0 & 2 \1 & \sqrt{5} \5 & 3 \\hline\end{array}\]
05

Sketch the Graph Using the Table

Plot the points from the table of values on a coordinate plane: \((-4, 0), (-3, 1), (0, 2), (1, \sqrt{5}), (5, 3)\). Connect the plotted points with a smooth curve. The graph is the right half of a sideways-opening parabola, starting at \(x = -4\) and extending indefinitely to the right.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Domain of a Function
The domain of a function consists of all the possible input values, or 'x' values, which will not result in errors during function calculations. Understanding the domain is crucial because it tells you where the function is defined and where it isn't.
For the function \( g(x) = \sqrt{x+4} \), the expression inside the square root must be non-negative, as the square root of a negative number is not defined in the set of real numbers.
To find the domain, solve the inequality:
  • \( x + 4 \geq 0 \)
  • This simplifies to \( x \geq -4 \)
Thus, the domain of this function is \([ -4, \infty)\), meaning any \( x \) value greater than or equal to -4 is valid.
Finding the domain ensures that you use appropriate x-values when evaluating the function with no errors or undefined results.
Square Root Function
A square root function typically takes the form \( f(x) = \sqrt{g(x)} \), where \( g(x) \) must be a non-negative expression.
This is because you cannot find the real square root of a negative number. When graphing square root functions, you often observe a parabola-like curve, but only one "leg" of it.
For the function \( g(x) = \sqrt{x+4} \), the square root function starts at the point where the expression inside the square root is zero. Here, it begins at \( x = -4 \) because that’s when \( x + 4 = 0 \).
The graph will then stretch to the right and upwards as \( x \) increases and \( g(x) \) values become larger.
Key Characteristics:
  • Starts at a specific \( x \)-value, here \( x = -4 \).
  • Continues indefinitely to the right.
  • Increases gradually.
Understanding the shape and starting point of a square root function graph helps determine the behavior of the function.
Coordinate Plane
The coordinate plane is a vital tool in graphing functions. It consists of a horizontal axis (x-axis) and a vertical axis (y-axis) intersecting at the origin (0,0).
This two-dimensional surface allows us to visually represent mathematical functions by plotting points that correspond to function values.
When plotting the graph of \( g(x) = \sqrt{x+4} \), use the coordinate plane to place each calculated point derived from the function:
  • Start by identifying the domain, as we did with \([ -4, \infty) \).
  • Select points within this domain to evaluate, like \( x = -4, -3, 0, 1, 5 \).
  • Calculate the corresponding \( g(x) \) values to obtain points such as \( (-4, 0), (-3, 1), (0, 2), (1, \sqrt{5}), (5, 3) \).
Then, plot these points on the coordinate plane and connect them smoothly.
This gives the visual outline of the function, providing insight into the behavior and direction of the graph.
Utilizing the coordinate plane effectively allows for clearer understanding and interpretation of mathematical relationships present in functions.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Determine whether the function \(f\) is even, odd, or neither. If \(f\) is even or odd, use symmetry to sketch its graph. $$f(x)=x^{3}-x$$

A home owner mows the lawn every Wednesday afternoon. Sketch a rough graph of the height of the grass as a function of time over the course of a fourweek period beginning on a Sunday.

In Exercise 65 of Section 2.7 you were asked to solve equations in which the unknowns were functions. Now that we know about inverses and the identity function (see Exercise \(82),\) we can use algebra to solve such equations. For instance, to solve \(f \circ g=h\) for the unknown function \(f\) we perform the following steps: \(f \circ g=h\) Problem: Solve for \(f\) \(f \circ g \circ g^{-1}=h \circ g^{-1} \quad\) Compose with \(g^{-1}\) on the right \(f \circ I=h \circ g^{-1} \quad g \circ g^{-1}=I\) \(f=h \circ g^{-1} \quad\) f \(\circ I=f\) So the solution is \(f=h \circ g^{-1} .\) Use this technique to solve the equation \(f \circ g=h\) for the indicated unknown function. (a) Solve for \(f,\) where \(g(x)=2 x+1\) and \(h(x)=4 x^{2}+4 x+7\) (b) Solve for \(g,\) where \(f(x)=3 x+5\) and \(h(x)=3 x^{2}+3 x+2\)

Find the functions \(f \circ g, g \circ f, f \circ f,\) and \(g \circ g\) and their domains. $$f(x)=\frac{1}{x}, \quad g(x)=2 x+4$$

Graph of the Absolute Value of a Function (a) Draw the graphs of the functions \(f(x)=x^{2}+x-6\) and \(g(x)=\left|x^{2}+x-6\right| .\) How are the graphs of \(f\) and \(g\) related? (b) Draw the graphs of the functions \(f(x)=x^{4}-6 x^{2}\) and \(g(x)=\left|x^{4}-6 x^{2}\right| .\) How are the graphs of \(f\) and \(g\) related? (c) In general, if \(g(x)=|f(x)|,\) how are the graphs of \(f\) and \(g\) related? Draw graphs to illustrate your answer.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.