Chapter 12: Problem 26
Graph the piecewise-defined function and use your graph to find the values of the limits, if they exist. $$f(x)=\left\\{\begin{array}{ll} 2 x+10 & \text { if } x \leq-2 \\ -x+4 & \text { if } x>-2 \end{array}\right.$$ (a) \(\lim _{x \rightarrow-2^{-}} f(x)\) (b) \(\lim _{x \rightarrow-2^{+}} f(x)\) (c) \(\lim _{x \rightarrow-2} f(x)\)
Short Answer
Step by step solution
Interpret the Piecewise Function
Graphing the Function for x ≤ -2
Graphing the Function for x > -2
Analyze Limit at x approaches -2 from the Negative Side
Analyze Limit at x approaches -2 from the Positive Side
Evaluate the Two-Sided Limit at x = -2
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Limits of functions
- the left, written as \( \lim_{{x \to a^{-}}} f(x) \)
- the right, written as \( \lim_{{x \to a^{+}}} f(x) \)
- Substitute -2 into \( 2x + 10 \) to find the limit from the left: \( 6 \).
- Substitute -2 into \(-x + 4\), giving the limit from the right also as \( 6 \).
Graphing functions
- For the segment where \( x \leq -2 \), you sketch the graph of \( f(x) = 2x + 10 \). It's a simple linear function. Generate a few points, like (-2, 6) and (-3, 4), to plot.
- This part of the graph has a closed circle at \( x = -2 \), indicating that the value is included.
- Next, for \( x > -2 \), you switch to the second function piece, \( f(x) = -x + 4 \). Again, it is linear. Points like (-1, 5) and (0, 4) will help in plotting.
- The line will start with an open circle at \( x = -2 \), showing the value is not included here.
Continuity of functions
- The function is defined at \( a \), meaning \( f(a) \) exists.
- The limit of the function as \( x \) approaches \( a \) exists.
- \( \lim_{x \to a} f(x) = f(a) \), meaning the function's limit equals its value.
Since the left-hand and right-hand limits both equal 6, they meet the second requirement. So, we conclude that:
- Though the two-sided limit \( \lim_{x \to -2} f(x) \) is 6, continuity also depends on \( f(-2) \), which is also 6. This matches the limit point, confirming the function is continuous at \( x = -2 \).