Chapter 12: Problem 25
Graph the piecewise-defined function and use your graph to find the values of the limits, if they exist. $$f(x)=\left\\{\begin{array}{ll} -x+3 & \text { if } x<-1 \\ 3 & \text { if } x \geq-1 \end{array}\right.$$ (a) \(\lim _{x \rightarrow-1^{-}} f(x)\) (b) \(\lim _{x \rightarrow-1^{+}} f(x)\) (c) \(\lim _{x \rightarrow-1} f(x)\)
Short Answer
Step by step solution
Analyze the Piecewise Function
Graph the Function for \(x < -1\)
Graph the Function for \(x \geq -1\)
Determine \(\lim _{x \rightarrow-1^{-}} f(x)\)
Determine \(\lim _{x \rightarrow-1^{+}} f(x)\)
Determine \(\lim _{x \rightarrow-1} f(x)\)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Graphing Functions
- For the interval where \(x < -1\), the graph is a line described by the equation \(f(x) = -x + 3\). This line has a slope of -1 and a y-intercept of 3.
- For the interval where \(x \geq -1\), the function becomes constant, \(f(x) = 3\), forming a horizontal line.
When plotting these segments, look for special points where the intervals change, like \(x = -1\) in this function, to ensure accuracy. The graph assists in visualizing how these two parts relate to each other, and it's essential for further analysis.
Limits
- Left-sided limit: The value that \(f(x)\) approaches as x gets close to -1 from values less than -1.
- Right-sided limit: The value that \(f(x)\) approaches as x gets close to -1 from values greater than -1.
- A limit exists at a point if both the left-sided and right-sided limits are equal.
Unfortunately, since the values from the left and right are different (4 and 3 respectively), the two-sided limit \(\lim_{x \to -1} f(x)\) does not exist.
Continuity
For the piecewise function described:
- \(f(x)\) is not continuous at \(x = -1\) because the limit from the left (4) does not equal the function value (3), nor does it equal the limit from the right (3).
- To achieve continuity at a point, the function's value and the limits must all agree at that point.