Chapter 11: Problem 7
Use Pascal's triangle to expand the expression. $$\left(x^{2} y-1\right)^{5}$$
Short Answer
Expert verified
\(x^{10} y^{5} - 5x^8 y^4 + 10x^6 y^3 - 10x^4 y^2 + 5x^2 y - 1\).
Step by step solution
01
Understand Pascal's Triangle
Pascal's Triangle is a triangular array of numbers where each number is the sum of the two numbers directly above it. For expanding a binomial expression \((a + b)^n\), the coefficients are given by the \(n\)-th row (starting from row 0) of Pascal's Triangle.
02
Identify the Row in Pascal's Triangle
To expand \((x^2y - 1)^5\), you need to find the coefficients from the 5th row of Pascal's Triangle, which is \([1, 5, 10, 10, 5, 1]\).
03
Apply Binomial Expansion Formula
The binomial expansion formula is \((a + b)^n = \sum_{k=0}^{n}{\binom{n}{k}a^{n-k}b^k}\). Here, \(a = x^2 y\), \(b = -1\), and \(n=5\). Substitute these into the formula.
04
Calculate Each Term
Calculate each term of the expression using the coefficients and powers: - For \(k=0\): \(1 \times (x^2 y)^{5} \times (-1)^{0} = x^{10} y^{5}\)- For \(k=1\): \(5 \times (x^2 y)^{4} \times (-1)^{1} = -5x^8 y^4\)- For \(k=2\): \(10 \times (x^2 y)^{3} \times (-1)^{2} = 10x^6 y^3\)- For \(k=3\): \(10 \times (x^2 y)^{2} \times (-1)^{3} = -10x^4 y^2\)- For \(k=4\): \(5 \times (x^2 y)^{1} \times (-1)^{4} = 5x^2 y\)- For \(k=5\): \(1 \times (x^2 y)^{0} \times (-1)^{5} = -1\)
05
Write the Expanded Expression
Combine the terms obtained in the previous step to write the fully expanded expression: \(x^{10} y^{5} - 5x^8 y^4 + 10x^6 y^3 - 10x^4 y^2 + 5x^2 y - 1\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Binomial Expansion
Binomial expansion is a method used to express a binomial raised to any power as a sum of terms. When expanding a binomial \[(a + b)^n,\] each term of the expansion can be found using specific coefficients. These coefficients are derived from the corresponding row in Pascal's Triangle, a triangular array of numbers. Each term in the expansion consists of the product of a coefficient from Pascal's Triangle, a power of the first term of the binomial, and a power of the second term. The sum of the exponents in each product equals the exponent to which the binomial is raised. Binomial expansion is particularly useful:
- in algebraic simplifications,
- for solving polynomial equations, and
- in calculus, particularly in finding series expansions.
Binomial Theorem
The binomial theorem provides a quick and efficient way to expand binomials raised to a power without direct multiplication. By using the formula:\[(a + b)^n = \sum_{k=0}^{n}{\binom{n}{k}a^{n-k}b^k},\]the expansion is achieved by summing terms individually calculated for each value of \(k\) from 0 to \(n\). Here:
- \((a^{n-k}b^k)\) represents each term in the expanded form,
- \({\binom{n}{k}}\) is a binomial coefficient that can be found using Pascal's Triangle, which represents the number of ways to choose \(k\) items from \(n\).
Combinatorics
Combinatorics is a branch of mathematics focused on counting, arrangement, and combination of objects. At its core, it addresses questions like how many ways there are to arrange or select items from a set. In the context of binomial expansions, combinatorics provides the tools to determine binomial coefficients, which are essential for expanding binomials using the binomial theorem. These coefficients, denoted as \(\binom{n}{k}\), are calculated by:\[\binom{n}{k} = \frac{n!}{k!(n-k)!},\]where \(!\) denotes the factorial, which is the product of all positive integers up to that number. Applications in combinatorics extend far beyond binomial expansions:
- It is crucial in probability theory,
- has applications in computer science, particularly in algorithm analysis, and
- is important in data organization and analysis.