/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 46 A polar equation is given. (a)... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A polar equation is given. (a) Express the polar equation in parametric form. (b) Use a graphing device to graph the parametric equations you found in part (a). $$r=2^{\sin \theta}$$

Short Answer

Expert verified
Parametric form: \( x(\theta) = 2^{\sin\theta} \cos\theta \), \( y(\theta) = 2^{\sin\theta} \sin\theta \). Graph using a range of \( \theta \) from 0 to \( 2\pi \).

Step by step solution

01

Understanding the Polar Equation

A polar equation is given as \( r = 2^{\sin \theta} \). In this equation, \( r \) defines the radius or the distance from the origin, while \( \theta \) is the angle made with the positive x-axis.
02

Converting to Cartesian Coordinates

To express the polar equation in parametric form, we need to use the equations that relate polar and Cartesian coordinates: \( x = r\cos\theta \) and \( y = r\sin\theta \). First, we calculate \( r \cos\theta \) and \( r \sin\theta \) using the given polar equation: \( x = 2^{\sin\theta} \cos\theta \) and \( y = 2^{\sin\theta}\sin\theta \).
03

Expressing in Parametric Form

The parametric equations are derived by substituting the polar form expressions of \( x \) and \( y \): \( x(\theta) = 2^{\sin\theta} \cos\theta \) and \( y(\theta) = 2^{\sin\theta} \sin\theta \). These equations express the Cartesian coordinates in terms of the parameter \( \theta \).
04

Graphing the Parametric Equation

Using a graphing device, input the parametric equations \( x(\theta) = 2^{\sin\theta} \cos\theta \) and \( y(\theta) = 2^{\sin\theta} \sin\theta \), with \( \theta \) ranging from 0 to \( 2\pi \) to cover a full revolution. This graph will illustrate the curve represented by the original polar equation.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Parametric Equations
Parametric equations are a powerful way to describe curves in mathematics. Instead of using a single equation to represent relationships directly between variables such as \( x \) and \( y \), parametric equations use a third variable, called a parameter, often denoted as \( t \), to define the \( x \) and \( y \) coordinates separately. This approach allows for greater flexibility in representing complex curves that may be difficult to express with a simple equation between \( x \) and \( y \).
For example, consider the equations \( x(t) = \cos t \) and \( y(t) = \sin t \). These are the parametric equations for a circle with radius 1 centered at the origin. Here, each value of \( t \) corresponds to a point \((x, y)\) on the circle, where \( t \) represents the angle from the positive x-axis.
By allowing us to control the individual paths of variables, parametric equations offer a unique and dynamic way to explore and graph mathematical models. They are invaluable in fields like physics and engineering, where motion and trajectories need precise descriptions.
Cartesian Coordinates
Cartesian coordinates form the foundation of modern geometry and graphing systems. In this system, each point in a plane is characterized by a pair of numerical coordinates: \( x \) and \( y \). These coordinates define the position of a point relative to two perpendicular lines, namely the x-axis (horizontal) and the y-axis (vertical).
Imagine the Cartesian plane as a giant grid. The point where the axes meet is called the origin, denoted as the point \((0, 0)\). Moving to the right along the x-axis increases the x-coordinate, while moving to the left decreases it. Similarly, moving up or down along the y-axis increases or decreases the y-coordinate, respectively.
This system allows for easy graphing and visualization of mathematical relationships because the distances and positions can be precisely calculated using formulas such as the distance formula or mid-point formula. The Cartesian system's practicality and ease make it the most commonly used coordinate system, especially in algebra and calculus.
Polar to Cartesian Conversion
Converting from polar to Cartesian coordinates is an essential process in mathematics when dealing with equations or points defined using polar coordinates. It helps in visualizing the relationships in the more traditional Cartesian plane.
Polar coordinates describe a point in terms of its distance \( r \) from a reference center (usually the origin) and an angle \( \theta \) from a reference direction (often the positive x-axis). To convert these polar coordinates into Cartesian coordinates, we use the formulas:
  • \( x = r \cos\theta \)
  • \( y = r \sin\theta \)
These equations allow you to compute the \( x \) and \( y \) position for any polar coordinate \((r, \theta)\).
This conversion is particularly useful because it allows us to transform equations expressed in polar form into Cartesian formulas. For instance, in the original exercise, the polar equation \( r = 2^{\sin \theta} \) can be expressed in Cartesian coordinates when converted using the mentioned equations, resulting in parametric expressions that reveal the nature of the curve more intuitively when graphed.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

In this section we stated that parametric equations contain more information than just the shape of a curve. Write a short paragraph explaining this statement. Use the following example and your answers to parts (a) and (b) below in your explanation. The position of a particle is given by the parametric equations $$x=\sin t \quad y=\cos t$$ where \(t\) represents time. We know that the shape of the path of the particle is a circle. (a) How long does it take the particle to go once around the circle? Find parametric equations if the particle moves twice as fast around the circle. (b) Does the particle travel clockwise or counterclockwise around the circle? Find parametric equations if the particle moves in the opposite direction around the circle.

A pair of parametric equations is given. (a) Sketch the curve represented by the parametric equations. (b) Find a rectangular-coordinate equation for the curve by eliminating the parameter. $$x=\cos ^{3} t, \quad y=\sin ^{3} t, \quad 0 \leq t \leq 2 \pi$$

Use a graphing device to draw the curve represented by the parametric equations. $$x=\sin (\cos t), \quad y=\cos \left(t^{3 / 2}\right), \quad 0 \leq t \leq 2 \pi$$

When we found polar equations for the conics, we placed one focus at the pole. It's easy to find the distance from that focus to any point on the conic. Explain how the polar equation gives us this distance.

Complete the square to determine whether the equation represents an ellipse, a parabola, a hyperbola, or a degenerate conic. If the graph is an ellipse, find the center, foci, vertices, and lengths of the major and minor axes. If it is a parabola, find the vertex, focus, and directrix. If it is a hyperbola, find the center, foci, vertices, and asymptotes. Then sketch the graph of the equation. If the equation has no graph, explain why. $$4 x^{2}+25 y^{2}-24 x+250 y+561=0$$

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.