Chapter 10: Problem 26
(a)Use the discriminant to determine whether the graph of the equation is a parabola, an ellipse, or a hyperbola. (b) Use a rotation of axes to eliminate the \(x y\) -term. (c) Sketch the graph. $$(7 x+24 y)^{2}=600 x-175 y+25$$
Short Answer
Expert verified
The graph is a parabola with a discriminant of zero.
Step by step solution
01
Express in standard conic form
Rewrite the equation \((7x+24y)^2 = 600x - 175y + 25\) as:\\[(7x+24y)^2 - 600x + 175y - 25 = 0\]This is the general second-degree equation of the form \(Ax^2 + Bxy + Cy^2 + Dx + Ey + F = 0\), where you'll need to expand \((7x+24y)^2\) first to match this form.
02
Expand the square term
Expand \((7x+24y)^2\): \(7x+24y = a\). Then \(a^2 = (7x+24y)^2 = 49x^2 + 2(7x)(24y) + 576y^2 = 49x^2 + 336xy + 576y^2\).The equation becomes:\[49x^2 + 336xy + 576y^2 - 600x + 175y - 25 = 0\]
03
Identify coefficients
From the equation \(49x^2 + 336xy + 576y^2 - 600x + 175y - 25 = 0\), identify coefficients as follows:\(A = 49\), \(B = 336\), \(C = 576\), \(D = -600\), \(E = 175\), \(F = -25\).
04
Calculate discriminant
Use discriminant formula: \[ \,D = B^2 - 4AC\,\].Plug in the values: \[336^2 - 4(49)(576)\]. Calculate:\[112896 - 112896 = 0\].
05
Analyze discriminant result
Since the discriminant \(D = 0\), the graph represents a **parabola** in the conic sections.
06
Find angle of rotation
Use the formula \(\cot 2\theta = \frac{A-C}{B}\) to find the angle \(\theta\) that will eliminate the \(xy\)-term.Substitute the values: \[\cot 2\theta = \frac{49 - 576}{336}\]Calculate:\[\cot 2\theta = \frac{-527}{336}\], and find \(\theta\).
07
Apply rotation formulas
Using the rotation formulas:\[\begin{aligned}x &= x'\cos\theta - y'\sin\theta,\y &= x'\sin\theta + y'\cos\theta\end{aligned}\] substitute \(\theta\) from previous step and replace \(x\) and \(y\) in the original equation to eliminate the \(xy\)-term.
08
Solve resulting equation and sketch graph
Once the rotation eliminates the \(xy\)-term and the equation is expressed in a simpler form, solve for any intersections and general shape. Sketch the graph according to the results and new axes.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Discriminant
The discriminant is a very powerful tool in understanding the nature of conic sections. It helps determine whether a particular second-degree equation represents a parabola, ellipse, or hyperbola. In the case of the equation provided, which is expressed in the form \[Ax^2 + Bxy + Cy^2 + Dx + Ey + F = 0,\] we can calculate the discriminant using the formula \(D = B^2 - 4AC\). The values for \(A\), \(B\), and \(C\) are gathered from the expanded equation. Plugging in the values for this specific problem, we find\[D = 336^2 - 4(49)(576) = 112896 - 112896 = 0.\] Since the discriminant equals zero, the conic section is identified as a **parabola**.
- If \(D > 0\), the equation represents a hyperbola.
- If \(D < 0\), it represents an ellipse (or a circle, if \(A = C\)).
Rotation of Axes
Rotating the axes is a technique used to eliminate the \(xy\)-term in a conic equation, making it easier to analyze and sketch the graph. The formula to find the angle of rotation, \(\theta\), is\[\cot 2\theta = \frac{A - C}{B}.\]This helps us determine the angle necessary to simplify our equation. For the problem, substituting the values from the expanded form,\[\cot 2\theta = \frac{49 - 576}{336} = \frac{-527}{336}.\] It takes some trigonometric maneuvering to find the value of \(\theta\). Once the angle is known, the rotation formulas applied are:
- \(x = x'\cos\theta - y'\sin\theta\)
- \(y = x'\sin\theta + y'\cos\theta\)
Conic Equation
A conic equation takes the shape of a second-degree polynomial and defines the different types of conic sections such as circles, ellipses, hyperbolas, and parabolas. The general conic equation is given by:\[Ax^2 + Bxy + Cy^2 + Dx + Ey + F = 0.\]For simpler handling of these equations, especially when there's an \(xy\)-term present, it's sometimes beneficial to rotate the coordinate axes as mentioned earlier.
- Circles and ellipses have a negative discriminant (\(D < 0\)).
- Hyperbolas exhibit a positive discriminant (\(D > 0\)).
- Parabolas have a discriminant of zero (\(D = 0\)).