/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 20 Use a graphing device to graph t... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Use a graphing device to graph the parabola. $$x^{2}=-8 y$$

Short Answer

Expert verified
The parabola opens downward with vertex at the origin, focus at (0, -2), and directrix y = 2.

Step by step solution

01

Identify the Equation Type

First, recognize that the given equation is a quadratic equation in two variables, which describes a parabola. The equation is given as \(x^{2} = -8y\).
02

Rewrite the Equation

Rearrange the equation to identify crucial features. Here, it's already almost in vertex form for a parabola that opens downward. Notice that \(x^2 = -8y\) corresponds to \(y = -\frac{x^2}{8}\).
03

Determine Vertex and Orientation

The equation has the vertex at the origin \((0,0)\). The negative coefficient of \(y\) indicates the parabola opens downward. The equation aligns with \(x^2 = 4py\), where \(4p = -8\), resulting in \(p = -2\).
04

Identify Key Points

Calculate the focus and directrix. The focus is \((0, -2)\) and the directrix is \(y = 2\). These help guide your graph plotting.
05

Use a Graphing Tool

Input the equation \(y = -\frac{x^2}{8}\) into the graphing device. Visualize the graph to verify the orientation and position of the parabola with vertex at the origin and opening downward.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Quadratic Equations
Quadratic equations are mathematical expressions in which the highest power of the variable is squared. Sometimes they show up in the form \(ax^2 + bx + c = 0\), where \(a\), \(b\), and \(c\) are constants. However, in the context of graphing parabolas, quadratic expressions often manifest in terms of two variables, such as \(x^2 = ky\). This type of equation defines a parabola. In the equation \(x^2 = -8y\), you can see that it's a quadratic as the variable \(x\) is squared.
One key feature of quadratic equations in graphing is their ability to model parabolas, which are u-shaped curves. Depending on the sign and the coefficients of the terms, the parabola can turn different directions. Recognizing quadratic equations is the first step in understanding how to graph a parabola.
Parabola Orientation
The orientation of a parabola tells us which direction it opens. This is crucial for correctly graphing a quadratic equation like \(x^2 = -8y\), which is not in the standard \(y = ax^2 + bx + c\) form. Here, because the \(x\) variable is squared, it indicates an up or down opening rather than left or right.
When the equation is in the form \(x^2 = 4py\), the sign of \(p\) determines the opening direction. If \(p\) is positive, the parabola opens upwards. If \(p\) is negative, it opens downwards. In our given equation, \(-8y\) suggests that \(p\) is negative. Therefore, the parabola opens downward. Getting the orientation right helps with accurately sketching the parabola's shape and direction.
Vertex and Focus of Parabola
The vertex and focus are core elements in graphing a parabola. The vertex is the point of the parabolas' curve, either its highest or lowest point depending on its orientation. For most cases, like the equation \(x^2 = -8y\), the vertex form makes it easy to extract these details.
For the given problem, the vertex is at the origin \(0,0\), since the equation is already nearly in this format. This point is the starting position for sketching the parabola. The focus, in this case, calculated by \(4p = -8\), gives us \(p = -2\), leading to a focus at \(0, -2\). The focus is a special point inside the parabola that defines the curve's breadth and direction. Knowing these points is essential for correctly plotting the parabola using a graphing tool.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Determine the equation of the given conic in \(X Y\) -coordinates when the coordinate axes are rotated through the indicated angle. $$y=(x-1)^{2}, \quad \phi=45^{\circ}$$

Determine the equation of the given conic in \(X Y\) -coordinates when the coordinate axes are rotated through the indicated angle. $$x y=x+y, \quad \phi=\pi / 4$$

A satellite is in an elliptical orbit around the earth with the center of the earth at one focus. The height of the satellite above the earth varies between 140 mi and 440 mi. Assume the earth is a sphere with radius 3960 mi. Find an equation for the path of the satellite with the origin at the center of the earth.

Spiral Path of a Dog A dog is tied to a circular tree trunk of radius \(1 \mathrm{ft}\) by a long leash. He has managed to wrap the entire leash around the tree while playing in the yard, and finds himself at the point \((1,0)\) in the figure. Seeing a squirrel, he runs around the tree counterclockwise, keeping the leash taut while chasing the intruder. (a) Show that parametric equations for the dog's path (called an involute of a circle) are $$x=\cos \theta+\theta \sin \theta \quad y=\sin \theta-\theta \cos \theta$$ (b) Graph the path of the dog for \(0 \leq \theta \leq 4 \pi\). CAN'T COPY THE GRAPH

A pair of parametric equations is given. (a) Sketch the curve represented by the parametric equations. (b) Find a rectangular-coordinate equation for the curve by eliminating the parameter. $$x=\cos ^{3} t, \quad y=\sin ^{3} t, \quad 0 \leq t \leq 2 \pi$$

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.