Chapter 1: Problem 63
Make a table of values and sketch the graph of the equation. Find the \(x\) - and \(y\) -intercepts and test for symmetry. $$y=\sqrt{4-x^{2}}$$
Short Answer
Expert verified
The graph is the upper semicircle of a circle centered at the origin with radius 2, with x-intercepts at (-2, 0) and (2, 0), and a y-intercept at (0, 2). It is symmetric about the y-axis.
Step by step solution
01
Set up the Table of Values
To make the table of values, select values for \(x\) from the domain of the function \(y = \sqrt{4-x^2}\). Since the square root cannot be a square root of a negative number, \(4 - x^2 \geq 0\). Therefore, \(-2 \leq x \leq 2\). Use integer values within this range: -2, -1, 0, 1, and 2.
02
Calculate Corresponding \(y\) Values
Evaluate \(y = \sqrt{4-x^2}\) for each chosen \(x\) value. - For \(x = -2\), \(y = \sqrt{4 - (-2)^2} = \sqrt{0} = 0\)- For \(x = -1\), \(y = \sqrt{4 - (-1)^2} = \sqrt{3}\) - For \(x = 0\), \(y = \sqrt{4 - 0^2} = 2\)- For \(x = 1\), \(y = \sqrt{4 - 1^2} = \sqrt{3}\)- For \(x = 2\), \(y = \sqrt{4 - 2^2} = \sqrt{0} = 0\)
03
Identify the Intercepts
The \(x\)-intercepts occur where \(y = 0\). From the table, we see that the \(x\)-intercepts are at \((x, y) = (-2, 0)\) and \((x, y) = (2, 0)\).The \(y\)-intercept occurs where \(x = 0\). From the table, this point is \((0, 2)\).
04
Check for Symmetry
A function is symmetric with respect to the y-axis if substituting \(-x\) for \(x\) yields the original function. Calculate \(y = \sqrt{4 - (-x)^2} = \sqrt{4 - x^2}\), which is the same as the original function. Thus, it is symmetric with respect to the y-axis.
05
Sketch the Graph
Plot the points from the table on a coordinate grid: \((-2, 0)\), \((-1, \sqrt{3})\), \((0, 2)\), \((1, \sqrt{3})\), and \((2, 0)\). Connect the points with a smooth curve to form the upper semicircle of the circle centered at origin with radius 2, corresponding to the equation \(x^2 + y^2 = 4\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Table of Values
Creating a table of values is the foundational step in graphing functions like \( y = \sqrt{4 - x^2} \). By choosing specific \( x \) values from the function's domain and calculating the corresponding \( y \) values, we can plot these points on a coordinate grid. This helps create a visual representation of the equation.
For \( y = \sqrt{4 - x^2} \), we need to ensure that the expression under the square root is non-negative. This results in the condition \( 4 - x^2 \geq 0 \), meaning \( -2 \leq x \leq 2 \), because the square root of a negative number is not defined in the real numbers.
After choosing integer values \(-2, -1, 0, 1, 2\), calculate each \( y \) by substituting \( x \) into \( y = \sqrt{4 - x^2} \). For example:
For \( y = \sqrt{4 - x^2} \), we need to ensure that the expression under the square root is non-negative. This results in the condition \( 4 - x^2 \geq 0 \), meaning \( -2 \leq x \leq 2 \), because the square root of a negative number is not defined in the real numbers.
After choosing integer values \(-2, -1, 0, 1, 2\), calculate each \( y \) by substituting \( x \) into \( y = \sqrt{4 - x^2} \). For example:
- \( x = -2 \), \( y = \sqrt{0} = 0 \)
- \( x = -1 \), \( y = \sqrt{3} \)
- \( x = 0 \), \( y = 2 \)
- \( x = 1 \), \( y = \sqrt{3} \)
- \( x = 2 \), \( y = \sqrt{0} = 0 \)
Intercepts
Intercepts are key points where the graph intersects the axes; understanding them is crucial for graphing. For the equation \( y = \sqrt{4 - x^2} \), identifying the intercepts assists in outlining the graph's placement on the coordinate plane.
**Finding the \( x \)-Intercepts**
The \( x \)-intercepts occur where \( y = 0 \). From the function, \( y = \sqrt{4 - x^2} = 0 \) when \( x = -2 \) and \( x = 2 \). Therefore, the \( x \)-intercepts are the points \,(-2, 0)\, and \, (2, 0)\.
**Finding the \( y \)-Intercept**
The \( y \)-intercept is the point where the graph crosses the \( y \)-axis, which occurs when \( x = 0 \). Substitute this into the equation to find \( y \):
**Finding the \( x \)-Intercepts**
The \( x \)-intercepts occur where \( y = 0 \). From the function, \( y = \sqrt{4 - x^2} = 0 \) when \( x = -2 \) and \( x = 2 \). Therefore, the \( x \)-intercepts are the points \,(-2, 0)\, and \, (2, 0)\.
**Finding the \( y \)-Intercept**
The \( y \)-intercept is the point where the graph crosses the \( y \)-axis, which occurs when \( x = 0 \). Substitute this into the equation to find \( y \):
- \( y = \sqrt{4 - (0)^2} = 2 \)
Symmetry
Symmetry in graphing helps simplify complex functions and can reveal innate characteristics of graphs. For the function \( y = \sqrt{4 - x^2} \), we test for symmetry with respect to the \( y \)-axis to see if the graph is mirrored evenly across this axis.
A function is symmetric with respect to the \( y \)-axis if substituting \(-x\) for \(x\) yields the original function. Let's test this notion:
Substitute \(-x\) in place of \(x\):
\( y = \sqrt{4 - (-x)^2} = \sqrt{4 - x^2} \)
This new expression equals the original function, proving that \( y = \sqrt{4 - x^2} \) is symmetric regarding the \( y \)-axis.
Recognizing this symmetry assists in graphing: once we sketch one half, we can reflect these points across the \( y \)-axis to construct the other half.
A function is symmetric with respect to the \( y \)-axis if substituting \(-x\) for \(x\) yields the original function. Let's test this notion:
Substitute \(-x\) in place of \(x\):
\( y = \sqrt{4 - (-x)^2} = \sqrt{4 - x^2} \)
This new expression equals the original function, proving that \( y = \sqrt{4 - x^2} \) is symmetric regarding the \( y \)-axis.
Recognizing this symmetry assists in graphing: once we sketch one half, we can reflect these points across the \( y \)-axis to construct the other half.
Domain and Range
Understanding the domain and range is crucial in determining where the function exists in the Cartesian plane. For the function \( y = \sqrt{4 - x^2} \), both these concepts help set the boundaries of its graph.
**Domain**
The domain refers to all possible \( x \) values for which the function is defined. Since the expression under the square root, \( 4 - x^2 \), must be non-negative:
**Range**
The range is all possible \( y \) values the function can produce. Observing \( y = \sqrt{4 - x^2} \), we see:
Knowing the domain and range confines the graph's horizontal and vertical extents, allowing for accurate plotting.
**Domain**
The domain refers to all possible \( x \) values for which the function is defined. Since the expression under the square root, \( 4 - x^2 \), must be non-negative:
- \( 4 - x^2 \geq 0 \)
**Range**
The range is all possible \( y \) values the function can produce. Observing \( y = \sqrt{4 - x^2} \), we see:
- The minimum value of \( y \) is 0 (when \( x = 2 \) or \( x = -2 \))
- The maximum value of \( y \) is 2 (when \( x = 0 \))
Knowing the domain and range confines the graph's horizontal and vertical extents, allowing for accurate plotting.