/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 55 Make a table of values and sketc... [FREE SOLUTION] | 91Ó°ÊÓ

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Make a table of values and sketch the graph of the equation. Find the \(x\) - and \(y\) -intercepts and test for symmetry. $$y=1-x^{2}$$

Short Answer

Expert verified
The graph is a downward-opening parabola with x-intercepts at (1, 0) and (-1, 0), a y-intercept at (0, 1), and symmetry about the y-axis.

Step by step solution

01

Identify the Equation

The given equation is \( y = 1 - x^2 \). This is a quadratic equation and represents a parabola that opens downward as the coefficient of \( x^2 \) is negative.
02

Create a Table of Values

Choose a range of \( x \) values, substitute them into the equation to find corresponding \( y \) values, and then write these ordered pairs in a table.Example:- When \( x = -2 \), \( y = 1 - (-2)^2 = 1 - 4 = -3 \).- When \( x = -1 \), \( y = 1 - (-1)^2 = 1 - 1 = 0 \).- When \( x = 0 \), \( y = 1 - 0^2 = 1 \).- When \( x = 1 \), \( y = 1 - 1^2 = 0 \).- When \( x = 2 \), \( y = 1 - 2^2 = -3 \).| \( x \) | \( y \) ||---|---|| -2 | -3 || -1 | 0 || 0 | 1 || 1 | 0 || 2 | -3 |
03

Plot the Points and Sketch the Graph

Plot the points from the table on a coordinate plane: \((-2, -3)\), \((-1, 0)\), \((0, 1)\), \((1, 0)\), and \((2, -3)\). Connect these points with a smooth curve to sketch the graph of the parabola, which is located upside down.
04

Find the X-intercepts

The \( x \)-intercepts occur where \( y = 0 \). Set the equation \( 1 - x^2 = 0 \) and solve for \( x \):1. \( 1 = x^2 \)2. \( x = \pm 1 \)Thus, the \( x \)-intercepts are \( (1, 0) \) and \( (-1, 0) \).
05

Find the Y-intercept

The \( y \)-intercept occurs where \( x = 0 \). Substitute \( 0 \) for \( x \) in the equation:1. \( y = 1 - 0^2 = 1 \)Thus, the \( y \)-intercept is \( (0, 1) \).
06

Test for Symmetry

The graph of \( y = 1 - x^2 \) can be tested for symmetry:- **Y-axis Symmetry:** Replace \( x \) with \( -x \) in the equation and see if it is unchanged. \( y = 1 - (-x)^2 = 1 - x^2 \), which matches the original equation, confirming y-axis symmetry.- **Origin Symmetry:** Replace \( x \) with \(-x\) and \( y \) with \(-y\): \( -y = 1 - x^2 \) doesn't simplify to the original equation, thus no origin symmetry.- **X-axis Symmetry:** Not applicable as it conflicts with \( y eq -y \) in most functions.The graph is symmetric about the y-axis.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Quadratic Equation
A quadratic equation is one of the most fundamental concepts in algebra. It takes the general form \( ax^2 + bx + c = 0 \) where \( a \), \( b \), and \( c \) are constants, and \( a eq 0 \). In this article, however, we're looking at a specific case: the equation \( y = 1 - x^2 \). This is a simple equation where \( a = -1 \), \( b = 0 \), and \( c = 1 \).
The unique aspect of quadratic equations is their ability to form parabolas when graphed on a coordinate plane. The parabola's orientation—whether it opens upwards or downwards—depends on the sign of \( a \). Since the coefficient of \( x^2 \) in our equation is negative, the parabola opens downward. This feature will determine the overall shape when you plot points on a graph and connect them to visualize the curve.
X-intercepts
X-intercepts are the points where the graph of an equation crosses the x-axis. For these points, the value of \( y \) is always zero. To find the x-intercepts, you set the equation equal to zero and solve for \( x \).
For our equation \( y = 1 - x^2 \), setting \( y = 0 \) results in:
  • \( 1 - x^2 = 0 \)
  • Solving, we get \( x^2 = 1 \)
  • Thus, \( x = \pm 1 \)
The x-intercepts are the points \((1, 0)\) and \((-1, 0)\). These intercepts are critical in sketching the graph because they represent the points where the curve crosses the x-axis, visually confirming the equation's real-number solutions.
Y-intercepts
The y-intercept is where the graph of an equation crosses the y-axis. For these points, \( x \) is always zero. To determine the y-intercept, substitute \( x = 0 \) into the equation and solve for \( y \).
In our scenario with \( y = 1 - x^2 \):
  • Substituting \( x = 0 \) gives \( y = 1 - 0^2 = 1 \)
Therefore, the y-intercept is the point \((0, 1)\). This is significant because it provides a starting point on the y-axis from which you can graph the curve. Every line must intercept the y-axis, making this point a key reference in plotting your graph.
Symmetry
Symmetry in a parabola is a powerful property, making the graph easier to analyze and draw. A parabola can exhibit symmetry about the y-axis, the x-axis, or the origin.
For the equation \( y = 1 - x^2 \), the parabola shows symmetry about the y-axis. This means if you were to fold the graph along the y-axis, both sides would match perfectly. To test for y-axis symmetry, replace \( x \) with \( -x \) in the equation, and see if it remains unchanged:
  • \( y = 1 - (-x)^2 \) simplifies to \( y = 1 - x^2 \)
Since the outcome matches the original equation, y-axis symmetry is confirmed. You can't have symmetry about the x-axis because that would mean \( y = -y \), a contradiction with this parabola's equation. Symmetry about the origin isn't applicable here either as the transformation \( -y = 1 - x^2 \) doesn't revert back to the original equation. Recognizing symmetry helps efficiently plot the graph and understand its properties.

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