/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 47 An equation and its graph are gi... [FREE SOLUTION] | 91Ó°ÊÓ

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An equation and its graph are given. Find the \(x\) - and \(y\) -intercepts. $$y=4 x-x^{2}$$ (GRAPH CANT COPY)

Short Answer

Expert verified
The x-intercepts are (0, 0) and (4, 0); the y-intercept is (0, 0).

Step by step solution

01

Understanding Intercepts

The intercepts of a graph are points where the graph meets the axes. The \(x\)-intercept is where the graph meets the \(x\)-axis, and the \(y\)-intercept is where the graph meets the \(y\)-axis.
02

Finding the y-intercept

To find the \(y\)-intercept, substitute \(x = 0\) in the equation \(y = 4x - x^2\). This gives: \(y = 4(0) - 0^2 = 0\).Thus, the \(y\)-intercept is at the point \((0, 0)\).
03

Finding the x-intercepts

To find the \(x\)-intercepts, set \(y = 0\) in the equation \(y = 4x - x^2\). This gives: \[ 0 = 4x - x^2 \] Rewriting, we get: \[ x^2 - 4x = 0 \] Factor the equation: \[ x(x - 4) = 0 \] Setting each factor to zero gives: \(x = 0\) or \(x = 4\).Therefore, the \(x\)-intercepts are at the points \((0, 0)\) and \((4, 0)\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Finding x-intercept
To find where a graph crosses the x-axis, you need to understand the concept of the x-intercept. The x-intercept is the point where the graph of an equation meets the x-axis. At this point, the y-value is always zero because the point lies directly on the x-axis. So, our task is to find x-values where the equation is zero.For the equation given: \[ y = 4x - x^2 \] set the y to zero: \[ 0 = 4x - x^2 \]This transforms into a simple quadratic equation when rearranged:\[ x^2 - 4x = 0 \]Factor the equation:
  • Take out the common factor \(x\): \(x(x - 4) = 0\)
Now, solve for x by setting each factor equal to zero:
  • If \(x = 0\), we have one intercept at (0, 0).
  • If \(x - 4 = 0\), solve to get \(x = 4\), another intercept at (4, 0).
These steps show that the graph crosses the x-axis at points (0, 0) and (4, 0). Each x-intercept represents a solution to the equation when y equals zero.
Finding y-intercept
Next, let’s explore how to find the y-intercept of a graph. This is where the graph crosses the y-axis. At this point, the x-value will always be zero because the point lies directly on the y-axis.To find the y-intercept of the equation \( y = 4x - x^2 \), substitute \(x = 0\):\[ y = 4(0) - (0)^2 = 0 \]When x is zero, y is also zero. Thus, the point where the graph meets the y-axis is at (0, 0).In simpler terms:
  • Set x to zero in the equation.
  • Calculate y with this value.
  • The y-intercept is the y-value when x is zero.
This indicates the graph intersects the y-axis at the point (0, 0). Anytime you're uncertain about a graph's starting point in terms of y, computing the y-intercept is a great place to start.
Quadratic equations
Quadratic equations are fundamental expressions in algebra that involve a squared term. They are usually in the form: \( ax^2 + bx + c = 0 \). The equation given here: \( y = 4x - x^2 \) can be rearranged into this standard form: \( -x^2 + 4x + 0 = 0 \).What makes quadratics interesting is the shape of their graphs, typically parabolas. These are upward or downward-curving shapes based on the sign of the \(x^2\) coefficient:
  • If positive, the parabola opens upwards.
  • If negative, like in our equation, it opens downwards.
When analyzing a quadratic equation graph:
  • The solutions for \(x\) when \(y = 0\) give the x-intercepts.
  • The point where the parabola starts to turn is called the vertex.
  • The y-intercept is easily found by setting \(x = 0\).
Grasping these features gives insight into graph behaviors, making it easier to understand and predict outcomes based on diverse scenarios.

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