Chapter 1: Problem 45
Perform the addition or subtraction and simplify. $$\frac{1}{x+3}+\frac{1}{x^{2}-9}$$
Short Answer
Expert verified
\( \frac{x-2}{(x+3)(x-3)} \)
Step by step solution
01
Identify the Common Denominator
To perform the addition of fractions \( \frac{1}{x+3} \) and \( \frac{1}{x^{2}-9} \), we need a common denominator. Notice that \( x^2-9 \) is a difference of squares, which can be factored as \((x+3)(x-3)\). This implies our common denominator will be \((x+3)(x-3)\).
02
Rewrite the Fractions with a Common Denominator
Rewrite each fraction to have the common denominator. The first fraction \( \frac{1}{x+3} \) becomes \( \frac{x-3}{(x+3)(x-3)} \) because we multiply the numerator and denominator by \(x-3\). The second fraction already has the denominator \((x+3)(x-3)\), so it remains \( \frac{1}{(x+3)(x-3)} \).
03
Add the Fractions
Now that both fractions have a common denominator, we can add them: \[\frac{x-3}{(x+3)(x-3)} + \frac{1}{(x+3)(x-3)} = \frac{(x-3) + 1}{(x+3)(x-3)}\].
04
Simplify the Expression
Combine the numerators: \((x-3) + 1 = x - 2\). Therefore, the fraction becomes: \( \frac{x-2}{(x+3)(x-3)} \). Since there are no common factors in the numerator and denominator, this is the simplified form.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Common Denominator
When adding or subtracting rational expressions, finding a common denominator is essential. You can think of a denominator as the part of the fraction that tells you the size of each part into which we've divided our whole. For example, in the expressions \( \frac{1}{x+3} \) and \( \frac{1}{x^2-9} \), we need them both to share the same denominator to combine them. To find a common denominator, look for factors or expressions that allow both denominators to be compatible. In this case, notice \( x^2-9 \) can be factored into \((x+3)(x-3)\), a concept known as 'Difference of Squares', helping us easily find the common denominator as \((x+3)(x-3)\).
- Ensures compatible fraction sizes
- Makes adding or subtracting fractions possible
- Facilitates simplifying later on
Difference of Squares
The difference of squares is a specific rule that helps us factor certain quadratic equations. This rule states that any expression of the form \( a^2-b^2 \) can be written as \( (a-b)(a+b) \). Applied to the problem, \( x^2-9 \) represents a difference of squares because it can be rewritten as \( (x+3)(x-3) \). Understanding this principle is greatly beneficial as it simplifies problems and reveals common denominators for fraction work. Here's why it's important:
- Makes factoring quicker and easier
- Simplifies identifying common denominators
- Reduces algebraic expressions efficiently
Simplifying Fractions
After combining fractions with common denominators, the final step is simplifying the result. Simplification is the process of making a fraction as small and manageable as possible. For example, after adding the expressions to get \( \frac{x-2}{(x+3)(x-3)} \), checking for any common factors in the numerator and denominator is key. Since \( x-2 \) and \( (x+3)(x-3) \) share no common terms, the fraction is already in its simplest form.Simplification involves:
- Cancelling any common factors
- Ensuring the expression is easily understandable
- Making approximate comparisons more straightforward