Chapter 1: Problem 38
Find the lengths of the medians of the triangle with vertices \(A(1,0), B(3,6),\) and \(C(8,2) .\) (A median is a line segment from a vertex to the midpoint of the opposite side.)
Short Answer
Expert verified
AM = \(\frac{\sqrt{145}}{2}\), BM = \(\sqrt{27.25}\), CM = \(\sqrt{37}\).
Step by step solution
01
Find Midpoint of BC
To find the midpoint of segment BC, use the midpoint formula: \[ \text{Midpoint} = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right) \]Plugging in the coordinates for B(3,6) and C(8,2):\[ \text{Midpoint of } BC = \left( \frac{3 + 8}{2}, \frac{6 + 2}{2} \right) = \left( \frac{11}{2}, 4 \right) \]
02
Calculate Median from A to BC
Use the distance formula to calculate the length of median AM (from A to midpoint M of BC):\[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \]Applying it to A(1,0) and M\left( \frac{11}{2}, 4 \right):\[ AM = \sqrt{\left( \frac{11}{2} - 1 \right)^2 + (4 - 0)^2} \]\[ = \sqrt{\left( \frac{9}{2} \right)^2 + 4^2} \]\[ = \sqrt{\frac{81}{4} + 16} \]\[ = \sqrt{\frac{145}{4}} \]\[ = \frac{\sqrt{145}}{2} \]
03
Find Midpoint of AC
To find the midpoint of segment AC, use the midpoint formula:\[ \text{Midpoint} = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right) \]Plugging in coordinates for A(1,0) and C(8,2):\[ \text{Midpoint of } AC = \left( \frac{1 + 8}{2}, \frac{0 + 2}{2} \right) = (4.5, 1) \]
04
Calculate Median from B to AC
Use the distance formula to calculate the length of median BM (from B to midpoint M of AC):\[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \]Applying it to B(3,6) and M(4.5,1):\[ BM = \sqrt{(4.5 - 3)^2 + (1 - 6)^2} \]\[ = \sqrt{1.5^2 + (-5)^2} \]\[ = \sqrt{2.25 + 25} \]\[ = \sqrt{27.25} \]
05
Find Midpoint of AB
To find the midpoint of segment AB, use the midpoint formula:\[ \text{Midpoint} = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right) \]Plugging in coordinates for A(1,0) and B(3,6):\[ \text{Midpoint of } AB = \left( \frac{1 + 3}{2}, \frac{0 + 6}{2} \right) = (2,3) \]
06
Calculate Median from C to AB
Use the distance formula to calculate the length of median CM (from C to midpoint M of AB):\[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \]Applying it to C(8,2) and M(2,3):\[ CM = \sqrt{(2 - 8)^2 + (3 - 2)^2} \]\[ = \sqrt{(-6)^2 + 1^2} \]\[ = \sqrt{36 + 1} \]\[ = \sqrt{37} \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Midpoint Formula
The midpoint formula is a crucial tool in geometry for finding the center point between two points. When you have two coordinates, let's say
- Point 1: \(x_1, y_1\)
- Point 2: \(x_2, y_2\)
- Midpoint = \( rac{x_1 + x_2}{2}, rac{y_1 + y_2}{2} \)
Distance Formula
The distance formula helps us determine the length of a line segment between two points in a coordinate plane. It is derived from the Pythagorean theorem. Given two points,
- Point 1: \(x_1, y_1\)
- Point 2: \(x_2, y_2\)
- Distance = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}\
Geometry
Geometry provides the tools to understand shapes, sizes, and the properties of space. In the context of triangles, a key aspect includes understanding medians — line segments that connect a vertex with the midpoint of the opposite side. These medians are crucial because:
- They divide a triangle into two smaller triangles of equal area.
- The point where all three medians intersect is known as the centroid, which is the triangle’s center of balance.