Chapter 1: Problem 10
(a) Sketch lines through \((0,0)\) with slopes \(1,0, \frac{1}{2}, 2,\) and \(-1\) (b) Sketch lines through \((0,0)\) with slopes \(\frac{1}{3}, \frac{1}{2},-\frac{1}{3},\) and 3
Short Answer
Expert verified
Draw lines with specified slopes through the origin; positive slopes rise, negative slopes fall, and 0 is horizontal.
Step by step solution
01
Understanding Slopes
The slope of a line tells us how steep the line is. It is the 'rise' over the 'run'. A positive slope means the line rises to the right, while a negative slope means the line falls to the right. A slope of 0 means the line is horizontal. A line through the origin formulated as \(y = mx\), where \(m\) is the slope.
02
Plotting lines for part (a)
For lines through \((0,0)\) with slopes \(1,0, \frac{1}{2}, 2,\) and \(-1\): Draw the line \(y = x\) for a slope of 1, resulting in a line at a 45-degree angle rising to the right. A line with slope 0 is \(y = 0\), which is horizontal along the x-axis. The line \(y = \frac{1}{2}x\) climbs more gently upwards. The line \(y = 2x\) is steeper. Finally, the line \(y = -x\) falls at a 45-degree angle due to the negative slope.
03
Plotting lines for part (b)
For lines through \((0,0)\) with slopes \(\frac{1}{3}\), \(\frac{1}{2}\), \(-\frac{1}{3}\), and 3: The line \(y = \frac{1}{3}x\) rises gently. The line \(y = \frac{1}{2}x\) is slightly steeper. The line \(y = -\frac{1}{3}x\) falls to the right gently. Lastly, the line \(y = 3x\) rises steeply.
04
Final Visualization
Visualize both parts: Part (a) should show lines originating from the origin with varying inclines and one horizontal line. Part (b) lines also depart from the origin, with diverse rises and falls; each graphed according to its slope.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Slopes
Slopes play a crucial role in understanding linear equations and lines. The slope is a measure of the line's steepness and is defined as the ratio of the vertical change (rise) to the horizontal change (run). This relationship can be expressed as \( m = \frac{\text{rise}}{\text{run}} \). The greater this ratio, the steeper the line, while a smaller ratio means a gentler incline or decline.
In linear equations, the slope is represented by the variable \( m \) in the equation \( y = mx + b \). Here, \( b \) is the y-intercept, which is the point where the line crosses the y-axis. For lines that pass through the origin, the equation simplifies to \( y = mx \), where the line's path is solely determined by the slope \( m \) and there is no y-intercept. Understanding the slope will help you predict and sketch the line's trajectory accurately.
In linear equations, the slope is represented by the variable \( m \) in the equation \( y = mx + b \). Here, \( b \) is the y-intercept, which is the point where the line crosses the y-axis. For lines that pass through the origin, the equation simplifies to \( y = mx \), where the line's path is solely determined by the slope \( m \) and there is no y-intercept. Understanding the slope will help you predict and sketch the line's trajectory accurately.
Lines through the Origin
Lines that pass through the origin have a unique feature: they cross both the x-axis and the y-axis at the same point, the origin \((0,0)\). This means there are no added constants in the equation of the line, simplifying it to \( y = mx \). Here are some characteristics of lines through the origin:
- They share a common point of intersection with the axes, which is the origin \((0,0)\).
- The equation takes a simplified form \(y = mx\), making them easier to identify.
- The slope \(m\) exclusively determines the line's direction and steepness.
Positive and Negative Slopes
The concept of positive and negative slopes is essential in determining the direction a line will take. A positive slope means that the line will rise from the left to the right. This gives the line an upward trajectory as it moves along the x-axis. For instance, a line with a slope of 1, like \(y = x\), forms a 45-degree angle, moving upward.
Conversely, a negative slope indicates that the line falls from the left to the right. When a line has a slope of -1, as in \(y = -x\), it descends at a similar 45-degree angle, only in the opposite direction. The steepness remains the same, but the direction changes.
Conversely, a negative slope indicates that the line falls from the left to the right. When a line has a slope of -1, as in \(y = -x\), it descends at a similar 45-degree angle, only in the opposite direction. The steepness remains the same, but the direction changes.
- Positive slopes increase as x-values increase.
- Negative slopes decrease as x-values increase.
Horizontal and Vertical Lines
Horizontal and vertical lines show unique properties that distinguish them from lines with other slopes. A horizontal line has a zero slope, meaning there is no vertical rise as you move horizontally. The equation for a horizontal line is of the form \( y = b \), where \( b \) is the y-coordinate of any point on the line.
For example, if \(b = 0\), then the line is \(y = 0\), which is the x-axis itself.
A vertical line, on the other hand, has an undefined slope because there is vertical change but no horizontal movement. Any line parallel to the y-axis can be described with the equation \( x = a \), where \(a\) is the x-coordinate of every point on the line.
Remember:
For example, if \(b = 0\), then the line is \(y = 0\), which is the x-axis itself.
A vertical line, on the other hand, has an undefined slope because there is vertical change but no horizontal movement. Any line parallel to the y-axis can be described with the equation \( x = a \), where \(a\) is the x-coordinate of every point on the line.
Remember:
- Horizontal lines: \(y = b\), representing constant y-values.
- Vertical lines: \(x = a\), representing constant x-values and an undefined slope.