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State the conditions under which \(\mathbf{A}^{-1}\) exists. Then find a formula for \(\mathbf{A}^{-1}\). $$\mathbf{A}=\left[\begin{array}{llll}x & 1 & 1 & 1 \\\0 & y & 0 & 0 \\\0 & 0 & z & 0 \\\0 & 0 & 0 & w\end{array}\right]$$

Short Answer

Expert verified
The matrix is invertible if none of the diagonal elements are zero. The formula for \(\textbf{A}^{-1}\) is \(\begin{pmatrix} \frac{1}{x} & -\frac{1}{xy} & -\frac{1}{xz} & -\frac{1}{xw} \ 0 & \frac{1}{y} & 0 & 0 \ 0 & 0 & \frac{1}{z} & 0 \ 0 & 0 & 0 & \frac{1}{w} \end{pmatrix}\).

Step by step solution

01

Determine the Condition for Invertibility

The matrix \(\textbf{A}\) is invertible if its determinant is non-zero. Therefore, compute the determinant of \(\textbf{A}\). For a diagonal or nearly diagonal matrix, the determinant is the product of the diagonal elements.
02

Compute the Determinant

The determinant of matrix \(\textbf{A}\) is \( \text{det}(\textbf{A}) = x \times y \times z \times w \). The matrix \(\textbf{A}\) is invertible if \( \text{det}(\textbf{A}) eq 0 \). This implies that none of the diagonal elements \((x, y, z, w)\) should be zero.
03

Write Down the General Formula for \(\textbf{A}^{-1}\)

Use the condition that the determinant should be non-zero. The inverse of a diagonal matrix can be found by taking the reciprocal of each diagonal element. Thus, \(\textbf{A}^{-1}\) is given by: \[ \textbf{A}^{-1} = \begin{pmatrix} \frac{1}{x} & -\frac{1}{xy} & -\frac{1}{xz} & -\frac{1}{xw} \ 0 & \frac{1}{y} & 0 & 0 \ 0 & 0 & \frac{1}{z} & 0 \ 0 & 0 & 0 & \frac{1}{w} \end{pmatrix} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Matrix Equations
Matrix equations are used to represent and solve systems of linear equations. For example, an equation like \(\textbf{A}\textbf{x} = \textbf{b}\) translates a system of linear equations into matrix form. In this context, \(\textbf{A}\) represents a matrix of coefficients, \(\textbf{x}\) is a vector of variables, and \(\textbf{b}\) is a vector of constants. This approach is powerful because we can use matrix operations to manipulate and solve these equations.

We often need the inverse of a matrix, \(\textbf{A}^{-1}\), to solve for \(\textbf{x}\) by rearranging the equation to \(\textbf{x} = \textbf{A}^{-1}\textbf{b}\). However, the inverse exists only under certain conditions, which we will cover in the following sections.
Determinants
The determinant is a special number that can be calculated from a square matrix. It provides useful properties for the matrix, such as determining if the matrix is invertible. For a 2x2 matrix \(\textbf{A} = \begin{pmatrix}a & b \ c & d\end{pmatrix}\), the determinant is computed as \(\text{det}(\textbf{A}) = ad - bc\).

For larger matrices, the computation becomes more involved, often requiring breaking the matrix down into smaller parts (minors). Matrices with a determinant of zero (i.e., \(\text{det}(\textbf{A}) = 0\)) are singular and do not have an inverse. In our example, since matrix \(\textbf{A}\) is nearly diagonal, its determinant simplifies to the product of its diagonal elements: \(\text{det}(\textbf{A}) = x \times y \times z \times w\).
Invertibility Conditions
A matrix is invertible (or non-singular) if and only if its determinant is non-zero. For our matrix \(\textbf{A}\), the condition for invertibility is given by \(x \times y \times z \times w eq 0\). This means none of the diagonal elements \(x, y, z, w\) should be zero, ensuring the determinant is not zero.

Once this condition is satisfied, the inverse of the matrix can exist. The formula for the inverse of a general matrix can be complex, but for our diagonal matrix, it is straightforward as it involves reciprocals of the diagonal elements. The inverse of \(\textbf{A}\) is: \[\textbf{A}^{-1} = \begin{pmatrix} \frac{1}{x} & -\frac{1}{xy} & -\frac{1}{xz} & -\frac{1}{xw} \ 0 & \frac{1}{y} & 0 & 0 \ 0 & 0 & \frac{1}{z} & 0 \ 0 & 0 & 0 & \frac{1}{w} \end{pmatrix}\].
Diagonal Matrix
A diagonal matrix is a matrix in which the entries outside the main diagonal are all zero. In our case, matrix \(\textbf{A}\) is not purely diagonal but is nearly so, simplifying the computation of its inverse.

Diagonal matrices are particularly important because:
  • Their determinants are the product of their diagonal elements.
  • They are easy to invert by taking the reciprocal of each diagonal element.
  • They simplify many matrix operations.
Taking advantage of the structure of diagonal matrices allows us to efficiently solve matrix equations and find inverses.

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