/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 51 Four solutions of the equation \... [FREE SOLUTION] | 91Ó°ÊÓ

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Four solutions of the equation \(y=a x^{3}+b x^{2}+c x+d\) are given. Use a system of four equations in four variables to find the constants \(a, b, c,\) and \(d\) and write the equation. $$(-2,59),(-1,13),(1,-1), \text { and }(2,-17)$$

Short Answer

Expert verified
The polynomial equation is \( y = -2x^3 + 3x^2 + 4x - 6 \).

Step by step solution

01

- Write down the general form of the equation

The given equation is a cubic polynomial: \[ y = ax^3 + bx^2 + cx + d \]
02

- Form the system of equations

Substitute each given point \((-2,59),(-1,13),(1,-1),(2,-17)\) into the polynomial equation to form a system of equations. 1) For \((-2, 59)\): \[ 59 = a(-2)^3 + b(-2)^2 + c(-2) + d \Rightarrow 59 = -8a + 4b - 2c + d \] 2) For \((-1, 13)\): \[ 13 = a(-1)^3 + b(-1)^2 + c(-1) + d \Rightarrow 13 = -a + b - c + d \] 3) For \((1, -1)\): \[ -1 = a(1)^3 + b(1)^2 + c(1) + d \Rightarrow -1 = a + b + c + d \] 4) For \((2, -17)\): \[ -17 = a(2)^3 + b(2)^2 + c(2) + d \Rightarrow -17 = 8a + 4b + 2c + d \]
03

- Write down the system of linear equations

The system of equations is: \[ \begin{cases} -8a + 4b - 2c + d = 59 \ -a + b - c + d = 13 \ a + b + c + d = -1 \ 8a + 4b + 2c + d = -17 \end{cases} \]
04

- Solve the system of equations

Use methods for solving systems of linear equations such as substitution, elimination, or matrix operations to determine the values of \(a, b, c, \) and \(d\). After arranging and solving the system, we get: \[ a = -2, b = 3, c = 4, d = -6 \]
05

- Write the final polynomial equation

Substitute the values of \(a, b, c, \) and \(d\) back into the general form of the cubic equation to get the final polynomial: \[ y = -2x^3 + 3x^2 + 4x - 6 \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

cubic polynomial equation
A cubic polynomial equation is a mathematical expression of the form \(y = ax^3 + bx^2 + cx + d\), where \(a\), \(b\), \(c\), and \(d\) are constants and \(a eq 0\). The variable \(x\) is raised to the third power, giving the equation its name 'cubic.' These types of equations can have up to three real roots or solutions, and the graph of a cubic polynomial is a curve that intersects the \(y\)-axis at the coefficient \(d\). Cubic equations are important in various applications, such as physics, engineering, and economics. They help describe processes that involve acceleration, structural integrity, and optimization problems.
solving linear systems
Solving linear systems involves finding the values of variables that satisfy multiple linear equations simultaneously. In the context of finding the coefficients of a cubic polynomial, we can use the points provided to substitute into the polynomial and derive a system of linear equations. This system represents how the points fit the curve of the equation. Linear equations have the general form \(Ax + By = C\), where \(A\), \(B\), and \(C\) are constants. By solving the system, we determine the specific values of the unknowns that satisfy all equations at once. Linear systems can appear in numerous fields, including science, economics, and planning.
substitution method
The substitution method is a technique used to solve systems of linear equations. It involves solving one of the equations for one variable and then substituting that expression into the other equations. This process reduces the number of equations and makes it easier to find the values of the variables. Here’s a simple example: if we have the equations \(2x + y = 10\) and \(x - y = 2\), we could solve the second equation for \(x\) as \(x = y + 2\). Substituting \(x = y + 2\) into the first equation gives \(2(y + 2) + y = 10\), which simplifies to \(3y + 4 = 10\). Solving for \(y\), we get \(y = 2\). Finally, substituting \(y = 2\) back into \(x = y + 2\), we find \(x = 4\). The substitution method is particularly useful when one of the equations is easy to solve for a single variable.
elimination method
The elimination method, also known as the addition method, is another strategy for solving systems of linear equations. This method involves adding or subtracting the equations to eliminate one of the variables, making it possible to solve for the remaining variable(s). For instance, consider the equations \(3x + 2y = 16\) and \(x - 2y = 4\). By adding these equations directly, the \(2y\) terms cancel out, resulting in a simpler equation \(4x = 20\). Dividing by 4, we find \(x = 5\). Substituting this back into \(x - 2y = 4\), we get \(5 - 2y = 4\), which simplifies to \(y = \frac{1}{2}\). The elimination method is especially handy when the coefficients of one of the variables are directly opposites.
matrix operations
Matrix operations are powerful tools in solving systems of linear equations, particularly when dealing with large systems. In matrix form, a system of equations can be represented as \(AX = B\), where \(A\) is the matrix of coefficients, \(X\) is the column matrix of variables, and \(B\) is the column matrix of constants. By performing operations such as row reduction (Gaussian elimination) or using the inverse matrix (if it exists), we can find the solution to the system. For our cubic polynomial example, the matrix form would help us visually manage and solve the equations simultaneously to find \(a, b, c\), and \(d\). This method is widely used due to its ability to efficiently handle complex systems, valuable in different fields such as computer science, engineering, and economics.

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Most popular questions from this chapter

Fill in the blank with the correct term. Some of the given choices will not be used. Descartes' rule of signs the leading-term test the intermediate value theorem the fundamental theorem of algebra polynomial function rational function one- to-one function constant function horizontal asymptote vertical asymptote oblique asymptote direct variation inverse variation horizontal line vertical line parallel perpendicular Descartes' rule of signs the leading-term test the intermediate value theorem the fundamental theorem of algebra polynomial function rational function one-to-one function constant function horizontal asymptote vertical asymptote oblique asymptote direct variation inverse variation horizontal line vertical line parallel perpendicular $$A(n)$$ __________ is a function that is a quotient of two polynomials.

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