Chapter 8: Problem 89
Show that for any complex number \(z\) $$ \left|z^{2}\right|=|z|^{2} $$
Short Answer
Expert verified
\( |z^2| = |z|^2 \).
Step by step solution
01
Understand the properties of the modulus
The modulus of a complex number is a non-negative real number representing the distance of that complex number from the origin in the complex plane. If the complex number is represented as \( z = a + bi \), then its modulus is \( |z| = \sqrt{a^2 + b^2} \).
02
Recall the property of modulus in multiplication
For any two complex numbers \( z_1 \) and \( z_2 \), the modulus of their product is the product of their moduli: \( |z_1 z_2| = |z_1| |z_2| \).
03
Apply the property to our specific case
In the given problem, we need to show that \( |z^2| = |z|^2 \). Here, \( z^2 \) can be considered as \( z \cdot z \). Therefore, using the multiplication property of moduli, we get: \( |z^2| = |z \cdot z| = |z| \cdot |z| \).
04
Simplify the expression
From the previous step, we have \( |z^2| = |z| \cdot |z| \). This simplifies to \( |z^2| = |z|^2 \). Hence, we have shown that the modulus of \( z^2 \) is equal to the square of the modulus of \( z \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Complex Numbers
A complex number is a number that can be expressed in the form \(a + bi\), where \(a\) and \(b\) are real numbers, and \(i\) is an imaginary unit with the property that \(i^2 = -1\). The complex number combines both real and imaginary parts:
- Real part: \(a\)
- Imaginary part: \(bi\)
Modulus Property
The modulus (or absolute value) of a complex number \(z = a + bi\) is denoted as \(|z|\) and measures the distance of the complex number from the origin in the complex plane. Mathematically, it is given by \[|z| = \sqrt{a^2 + b^2}\.\]
Some important properties of the modulus include:
For example, if you have a complex number \(z = 3 + 4i\), its modulus would be \[|z| = \sqrt{3^2 + 4^2} = \sqrt{9 + 16} = 5.\]
Some important properties of the modulus include:
- It is always a non-negative real number.
- For any two complex numbers \(z_1\) and \(z_2\), the modulus of their product can be expressed as \( |z_1 z_2| = |z_1| |z_2| \).
- The modulus of a complex number remains the same whether the number is written in Cartesian form \(a + bi\) or in polar form \(r(cos(\theta) + i sin(\theta))\).
For example, if you have a complex number \(z = 3 + 4i\), its modulus would be \[|z| = \sqrt{3^2 + 4^2} = \sqrt{9 + 16} = 5.\]
Complex Multiplication
Multiplying complex numbers involves both their real and imaginary parts. To multiply \(z_1 = a + bi\) and \(z_2 = c + di\), you use the distributive property:
\begin{aligned} z_1 \times z_2 & = (a + bi)(c + di) \ &= ac + adi + bci + bdi^2\ \ &= ac + adi + bci - bd \ \ &= (ac - bd) + (ad + bc)i \ \text{(since } \(i^2 = -1\)) \end{aligned}
This yields a new complex number where:
To understand why \(|z^2| = |z|^2\), note that \( z^2 = z \times z \) follows the multiplication property of modulus: \[ |z^2| = |z \times z| = |z| \times |z| = |z|^2. \]
\begin{aligned} z_1 \times z_2 & = (a + bi)(c + di) \ &= ac + adi + bci + bdi^2\ \ &= ac + adi + bci - bd \ \ &= (ac - bd) + (ad + bc)i \ \text{(since } \(i^2 = -1\)) \end{aligned}
This yields a new complex number where:
- The real part is \(ac - bd\),
- The imaginary part is \(ad + bc\).
To understand why \(|z^2| = |z|^2\), note that \( z^2 = z \times z \) follows the multiplication property of modulus: \[ |z^2| = |z \times z| = |z| \times |z| = |z|^2. \]