Chapter 8: Problem 39
Find the value. $$\sin 45^{\circ}$$
Short Answer
Expert verified
\(\sin 45^{\circ} = \frac{\sqrt{2}}{2} \)
Step by step solution
01
Recognize the Angle
Identify the given angle. Here, the given angle is \( 45^{\circ} \).
02
Recall the Unit Circle Values
Recall that in the unit circle, \( \sin 45^{\circ} = \cos 45^{\circ} = \frac{1}{\sqrt{2}} \).
03
Simplify the Trigonometric Value
Simplify \(\sin 45^{\circ} = \frac{1}{\sqrt{2}} \) to rational form, \(\sin 45^{\circ} = \frac{\sqrt{2}}{2} \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Understanding the Unit Circle
The unit circle is a fundamental concept in trigonometry that helps us to understand the values of trigonometric functions at various angles. The unit circle is a circle with a radius of 1 centered at the origin of a coordinate plane. Any point on the unit circle can represent an angle, starting from the positive x-axis and moving counter-clockwise.
This circle helps to give exact values for sine, cosine, and tangent at specific angles, such as 30°, 45°, 60°, and 90°. What's special is that the (x, y) coordinates of any point on the circle are \(x = \cos(\theta)\) and \(y = \sin(\theta)\).
For example:
This circle helps to give exact values for sine, cosine, and tangent at specific angles, such as 30°, 45°, 60°, and 90°. What's special is that the (x, y) coordinates of any point on the circle are \(x = \cos(\theta)\) and \(y = \sin(\theta)\).
For example:
- At 0°, the coordinates are (1, 0). Hence, sin(0°) = 0 and cos(0°) = 1.
- At 90°, the coordinates are (0, 1). Hence, sin(90°) = 1 and cos(90°) = 0.
Simplifying Trigonometric Expressions
To solve trigonometric problems, simplifying trigonometric expressions is essential. Simplifying often involves recognizing equivalent values or transforming expressions using trigonometric identities. Let's break down a common example with sin(45°).
On the unit circle, we know that sin(45°) is the y-coordinate of the point where the terminal side of the 45° angle intersects the circle. We see that this point is \(\left( \frac{1}{\sqrt{2}}, \frac{1}{\sqrt{2}} \right)\).
This can be simplified further:
On the unit circle, we know that sin(45°) is the y-coordinate of the point where the terminal side of the 45° angle intersects the circle. We see that this point is \(\left( \frac{1}{\sqrt{2}}, \frac{1}{\sqrt{2}} \right)\).
This can be simplified further:
- \(\sin(45°) = \frac{1}{\sqrt{2}}\)
- To rationalize this, multiply the numerator and the denominator by \(\sqrt{2}\). Now, \(\frac{1}{\sqrt{2}} = \frac{\sqrt{2}}{2}\).
Special Angles in Trigonometry
Special angles are specific angles where the trigonometric function values are well-known and often used. Understanding these angles makes solving trigonometric problems quicker and easier.
Common special angles include 0°, 30°, 45°, 60°, and 90°. For instance, the values for sine and cosine at 45° are:
Moreover, recognizing these values can help in memorization and quick recall:
Common special angles include 0°, 30°, 45°, 60°, and 90°. For instance, the values for sine and cosine at 45° are:
- \(\sin(45°) = \cos(45°) = \frac{\sqrt{2}}{2}\)
Moreover, recognizing these values can help in memorization and quick recall:
- At 30°, \(\sin(30°) = \frac{1}{2}\) and \(\cos(30°) = \frac{\sqrt{3}}{2}\)
- At 60°, \(\sin(60°) = \frac{\sqrt{3}}{2}\) and \(\cos(60°) = \frac{1}{2}\)