/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 64 Solve. $$x^{2}-10 x+1=0$$... [FREE SOLUTION] | 91Ó°ÊÓ

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Solve. $$x^{2}-10 x+1=0$$

Short Answer

Expert verified
The solutions are \( x = 5 + 2\sqrt{6}\) and \( x = 5 - 2\sqrt{6} \).

Step by step solution

01

Identify the coefficients

Recognize that the given quadratic equation is in the standard form \(ax^2 + bx + c = 0\). Identify the coefficients: \(a = 1\), \(b = -10\), and \(c = 1\).
02

Apply the quadratic formula

Use the quadratic formula \[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]to find the roots of the equation. Substitute \(a = 1\), \(b = -10\), and \(c = 1\) into the formula.
03

Calculate the discriminant

Calculate the discriminant \(\Delta = b^2 - 4ac\).Substitute the values to get \(\Delta = (-10)^2 - 4(1)(1) = 100 - 4 = 96\).
04

Solve for x

Substitute \(\Delta = 96\) back into the quadratic formula:\[ x = \frac{-(-10) \pm \sqrt{96}}{2(1)} = \frac{10 \pm \sqrt{96}}{2} \]Simplify further: \[ x = \frac{10 \pm 4\sqrt{6}}{2} = 5 \pm 2\sqrt{6} \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

quadratic formula
The quadratic formula provides a straightforward way to find the solutions, or roots, of a quadratic equation. Quadratic equations are typically in the form \(ax^2 + bx + c = 0\). The quadratic formula is:\[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]To use the formula, you first need to identify the coefficients \(a\), \(b\), and \(c\) from the equation.In the equation \(x^2 - 10x + 1 = 0\), we have:
  • \(a = 1\)
  • \(b = -10\)
  • \(c = 1\)
These values are substituted into the quadratic formula to find the roots of the equation. This formula is very powerful because it works for any quadratic equation, regardless of whether it can be factored easily or not.
discriminant
The discriminant is a key component of the quadratic formula that helps determine the nature of the roots of the quadratic equation. The discriminant is found inside the square root of the quadratic formula and is given by: \[ \Delta = b^2 - 4ac \]Depending on the value of \(\Delta\):
  • If \(\Delta > 0\), the quadratic equation has two distinct real roots.
  • If \(\Delta = 0\), there is exactly one real root (a repeated root).
  • If \(\Delta < 0\), there are no real roots, but two complex roots.
In our example, the discriminant is calculated as follows:\[ \Delta = (-10)^2 - 4(1)(1) = 100 - 4 = 96 \]Because \(\Delta = 96\) is greater than zero, our quadratic equation \(x^2 - 10x + 1 = 0\) has two distinct real roots.
roots of quadratic equations
The roots of a quadratic equation are the values of \(x\) that make the equation equal to zero. Once we have calculated the discriminant (\(\Delta\)), we use it to find the exact values of the roots with the quadratic formula. For our equation \(x^2 - 10x + 1 = 0\), we computed that \(\Delta = 96\). Substituting this into the quadratic formula gives us: \[ x = \frac{-(-10) \pm \sqrt{96}}{2(1)} = \frac{10 \pm \sqrt{96}}{2} \] Simplifying further, we get: \[ x = \frac{10 \pm 4\sqrt{6}}{2} = 5 \pm 2\sqrt{6} \] Hence, the roots of the quadratic equation are \(x = 5 + 2\sqrt{6}\) and \(x = 5 - 2\sqrt{6}\). These roots are the points where the quadratic equation crosses the x-axis on a graph. Understanding the roots of quadratic equations is crucial in solving many mathematical problems involving parabolas and other quadratic functions.

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Most popular questions from this chapter

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