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Solve using a calculator, finding all solutions in \([0,2 \pi)\). $$2 \cos ^{2} x=x+1$$

Short Answer

Expert verified
Find solutions in \( [0, 2\pi) \) by solving \( 2 \, \text{cos}^{2} x - 1 - x = 0 \) and taking \( \text{arccos}(y) \) of the solutions.

Step by step solution

01

Rewrite the Equation

Rewrite the given equation in standard form: \[ 2 \, \text{cos}^{2} x - x - 1 = 0 \]
02

Substitute Cosine Function

Let \(y = \text{cos} x\). Then the equation becomes: \[ 2y^{2} - 1 = x \]
03

Solve for y

Using a calculator, solve for \(y\) in the range \([0, 2\pi)\) by setting \[2y^{2} - 1 - y = 0\]
04

Find arccos

For each solution for \(y\), find \( x \) by using \( x = \text{arccos}(y) \). Ensure that \( x \) falls within the interval \([0, 2\pi)\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Arccosine
Arccosine, denoted as \(\text{arccos}(x)\) or \(\text{cos}^{-1}(x)\), is the inverse function of cosine. It is used to find the angle whose cosine value equals \(x\). The range of \(\text{arccos}(x)\) is between \(0\) and \(\text{Ï€}\), which covers all possible angles for the cosine function in one cycle. When solving trigonometric equations, arccosine helps us determine the angle \(x\) for which \(\text{cos}(x) = y\). This is crucial for finding solutions within specified intervals.

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