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Find the inverse of the given one-to-one function \(f .\) Give the domain and the range of \(f\) and of \(f^{-1},\) and then graph both \(f\) and \(f^{-1}\) on the same set of axes. Find \(f\left(f^{-1}(5)\right)\) and \(f^{-1}(f(a))\) $$ f(x)=x^{3}-4 $$

Short Answer

Expert verified
The inverse function is \( f^{-1}(x) = (x + 4)^{1/3} \). Both the domain and range for \( f \) and \( f^{-1} \) are \( (-fty, +fty) \). The composite functions are: \( f(f^{-1}(5)) = 5 \) and \( f^{-1}(f(a)) = a \).

Step by step solution

01

- Define the Function

The given function is defined as follows: \( f(x) = x^3 - 4 \).
02

- Find the Inverse Function

To find the inverse function, begin by replacing \( f(x) \) with \( y \): \( y = x^3 - 4 \). Swap \( x \) and \( y \): \( x = y^3 - 4 \). Solve for \( y \): \( x + 4 = y^3 \) \( y = (x + 4)^{1/3} \). Therefore, the inverse function is: \( f^{-1}(x) = (x + 4)^{1/3} \).
03

- Determine Domain and Range

The domain of the original function \( f(x) \) is all real numbers, as any real number can be cubed and have 4 subtracted from it. Thus, the domain of \( f \) is \( (-fty, +fty) \). The range of \( f(x) \) is also all real numbers, since a cubic function spans all real numbers. Therefore, the range of \( f \) is \( (-fty, +fty) \). The domain and range of \( f^{-1}(x) \) will be the same as those of \( f(x) \), as inverses swap domains and ranges. Thus, both the domain and range for \( f^{-1}(x) \) are \( (-fty, +fty) \).
04

- Graph Function and Inverse

Graph the function \( f(x) \) and its inverse \( f^{-1}(x) \) on the same set of axes. To graph \( f(x) = x^3 - 4 \), plot several points and connect them smoothly, noting the cubic nature.Similarly, graph \( f^{-1}(x) = (x + 4)^{1/3} \) by plotting points and connecting them smoothly. Both graphs should be reflections of each other across the line \( y = x \).
05

- Evaluate Composite Functions

Find \( f(f^{-1}(5)) \): Substitute 5 into the inverse function: \( f^{-1}(5) = (5 + 4)^{1/3} = 9^{1/3} = 2.08 \). Substitute this result back into \( f \): \( f(2.08) = (2.08)^3 - 4 \) \( \approx 9 - 4 = 5 \). Thus, \( f(f^{-1}(5)) = 5 \). Find \( f^{-1}(f(a)) \): Substitute \( a \) into \( f \): \( f(a) = a^3 - 4 \). Substitute this result into the inverse function: \( f^{-1}(f(a)) = f^{-1}(a^3 - 4) = ((a^3 - 4) + 4)^{1/3} \). Simplify: \( (a^3)^{1/3} = a \). Thus, \( f^{-1}(f(a)) = a \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

domain and range
When working with functions and their inverses, understanding domain and range is essential. The domain of a function is the set of all possible input values (x-values), while the range is the set of all possible output values (y-values).

For the given function \( f(x) = x^3 - 4 \), we can see that it’s a cubic function. Generally, cubic functions have a domain of all real numbers, denoted by \( (-∞, ∞) \). This means that no matter what real number you input into the function, you will always get a valid output.

Similarly, the range of a cubic function is also all real numbers, because the output can span from negative to positive infinity as x varies through all real numbers. Thus, the range of \( f(x) \) is also \( (-∞, ∞) \).

Now, when finding the inverse function, \( f^{-1}(x) \), the domain and range of the inverse function are swapped from the original function. So, the domain of \( f^{-1}(x) = (x + 4)^{1/3} \) is \( (-∞, ∞) \) and its range is also \( (-∞, ∞) \).
graphing functions
Graphing functions helps in visualizing their behavior and understanding the relationship between the function and its inverse. To graph \( f(x) = x^3 - 4 \) and its inverse \( f^{-1}(x) = (x + 4)^{1/3} \) on the same axes, follow these steps:

1. **Plot Points for \( f(x) \)**: Choose several x-values and compute the corresponding y-values. For example:
- For \( x = -2 \), \( f(-2) = (-2)^3 - 4 = -12 \)
- For \( x = 0 \), \( f(0) = 0^3 - 4 = -4 \)
- For \( x = 2 \), \( f(2) = 2^3 - 4 = 4 \)

2. **Connect the Points Smoothly**: Since \( f(x) \) is a cubic function, the graph will be a smooth curve passing through the points.

3. **Plot Points for \( f^{-1}(x) \)**: Again, choose several x-values and compute the corresponding y-values for the inverse function. For example:
- For \( x = -3 \), \( f^{-1}(-3) = (-3 + 4)^{1/3} = 1^{1/3} = 1 \)
- For \( x = 0 \), \( f^{-1}(0) = (0 + 4)^{1/3} = 1.59 \)
- For \( x = 4 \), \( f^{-1}(4) = (4 + 4)^{1/3}= 2 \)

4. **Reflect Across Line \( y = x \)**: Note that the graph of \( f^{-1}(x) \) will be a reflection of the graph of \( f(x) \) across the line \( y = x \).

The visualization helps understand that for each corresponding value in \( f(x) \), there’s a mirrored value in \( f^{-1}(x) \).
composite functions
A composite function is formed when one function is applied to the results of another function. When we talk about composite functions involving a function and its inverse, we commonly examine \( f(f^{-1}(x)) \) and \( f^{-1}(f(a)) \).

Ensuring composite functions return to the original value is a crucial property of true inverse functions. Let's look deeper:

1. Finding \( f(f^{-1}(5)) \):
- First, find \( f^{-1}(5) \):
\( f^{-1}(5) = (5 + 4)^{1/3} = 9^{1/3} = 2.08 \)
- Next, substitute this result back into the function \( f \):
\( f(2.08) = (2.08)^3 - 4 = 9 - 4 = 5 \)
This confirms that \( f(f^{-1}(5)) = 5 \).

2. Finding \( f^{-1}(f(a)) \):
- First, substitute \( a \) into the function \( f \):
\( f(a) = a^3 - 4 \)
- Next, substitute this result into the inverse function \( f^{-1} \):
\( f^{-1}(a^3 - 4) = ((a^3 - 4) + 4)^{1/3} \)
Simplify:
\( (a^3)^{1/3} = a \)
So, \( f^{-1}(f(a)) = a \).

This shows that applying the function and its inverse in succession brings you back to your original starting value. This inherent property is a great way to check if two functions are truly inverses of each other.

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